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CHEMISTRY FORM ONE LESSON NOTES

CHEMISTRY FORM ONE NOTES

INTRODUCTION TO CHEMISTRY

Chemistry is a branch of Science. Science is basically the study of living and non-living things. The branch of science that study living things is called Biology. The branch of science that study non-living things is called Physical Science. Physical Science is made up of:

  • Physics- the study of matter in relation to energy
  • Chemistry- the study of the composition of matter.

Chemistry is thus defined as the branch of science that deals with the structure composition, properties and behavior of matter.

Basic Chemistry involves studying:

  • States/phases of matter

Matter is anything that has weight/mass and occupies space/volume. Naturally, there are basically three states of matter.

(i) Solid-e.g. soil, sand, copper metal, bucket, ice.

(ii)Liquid- e.g. water, Petrol, ethanol/alcohol, Mercury (liquid metal).

(iii) gas- e.g. Oxygen, Nitrogen ,Water vapour.

A solid is made up of particles which are very closely packed. It thus has a definite/fixed shape and fixed/definite volume /occupies definite space. It has a very high density.

A liquid is made up of particles which have some degree of freedom. It thus has no definite/fixed shape. It takes the shape of the container it is put. A liquid has fixed/definite volume/occupies definite space.

A gas is made up of particles free from each other. It thus has no definite/fixed shape. It takes the shape of the container it is put. It has no fixed/definite volume/occupies every space in a container.

(b) Separation of mixture

A mixture is a combination of two or more substances that can be separated by physical means. Simple methods of separating mixtures at basic chemistry level include:

  1. i) Sorting/picking-this involve physically picking one pure substance from a mixture with another/other. e. g. sorting maize from maize beans mixture.
  2. ii) Decantation-this involve pouring out a liquid from a solid that has settled /sinking solid in it. e. g. Decanting water forms sand.

iii)Filtration-this involves sieving /passing particles of a mixture through a filter containing small holes that allow smaller particle to pass through but do not allow bigger particle to pass through.

  1. iv) Skimming-this involve scooping floating particles. E.g. cream from milk

(c) Metals and non-metals

Metals are shiny, ductile(able to form wires), malleable(able to form sheet) and coil without breaking. E.g. Iron, gold, silver, copper. Mercury is the only liquid metal known.

Non-metals are dull, not ductile (do not form wires), not malleable (do not form sheet) and break on coiling/brittle. E.g. Charcoal, Sulphur, pla-stics.

(d) Conductors and non-conductors

A conductor is a solid that allow electric current to pass through. A non-conductor is a solid that do not allow electric current to pass through.

All metals conduct electricity. All non-metals do not conduct electricity except carbon graphite.

(e) Drugs

A drug is a natural or synthetic/man-made substance that when taken changes/alter the body functioning. A natural or synthetic/man-made substance that when taken changes/alter the abnormal body functioning to normal is called medicine. Medicines are thus drugs intended to correct abnormal body functions. . Medicines should therefore be taken on prescription and dosage.

A prescription is a medical instruction to a patient/sick on the correct type of medicine to take and period/time between one intake to the other.

A dosage is the correct quantity of drug required to alter the abnormal body function back to normal. This is called treatment. It is the professional work of qualified doctors/pharmacists to administer correct prescription and dosage of drugs/medicine to the sick. Prescription and dosage of drugs/medicine to the sick use medical language.

 Example

(i) 2  x  4 ;  means “2” tablets for solid drugs/spoonfuls for liquid drugs taken “4” times  for a duration of one day/24 hours  and then repeated and continued until all the drug given is finished.

(ii) 1  x  2 ;  means “1” tablets for solid drugs/spoonfuls for liquid drugs taken “2” times  for a duration of one day/24 hours  and then repeated and continued until all the drug given is finished.

Some drugs need minimal prescription and thus are available without pharmacist/ doctor’s prescription. They are called Over The Counter (OTC) drugs. OTC drugs used to treat mild headaches, stomach upsets, common cold include:

(i) Painkillers

(ii) Anti-acids

(iii) cold/flu drugs.

All medicine requires correct intake dosage. When a prescription dosage is not followed, this is called drug misuse/abuse.  Some drugs are used for other purposes other than that intended. This is called drug abuse.

Drug abuse is when a drug is intentionally used to alter the normal functioning of the body. The intentional abnormal function of the drug is to make the victim have false feeling of well being. The victim lack both mental and physical coordination.

Some drugs that induce a false feeling of well being are illegal. They include heroin, cocaine, bhang, Mandrax and morphine.

Some abused drugs which are not illegal include: Miraa, alcohol, tobacco, sleeping pills.

The role of chemistry in society

(a) Chemistry is used in the following:

(i) Washing/cleaning with soap:

Washing/cleaning is a chemical process that involves interaction of water, soap and dirt so as to remove the dirt from a garment.

(ii) Understanding chemicals of life

Living thing grow, respire and feed. The formation and growth of cells involve chemical processes in living things using carbohydrates, proteins and vitamins.

(iii) Baking:

Adding baking powder to dough and then heating in an oven involves interactions that require understanding of chemistry.

(iv) Medicine:

Discovery, test, prescription and dosage of drugs to be used for medicinal purposes require advanced understanding of chemistry

(v) Fractional distillation of crude oil:

Crude oil is fractional distilled to useful portions like petrol, diesel, kerosene by applying chemistry.

(vi) Manufacture of synthetic compounds/substances

Large amounts of plastics, glass, fertilizers, insecticides, soaps, cements, are manufactured worldwide. Advanced understanding of the chemical processes involved is a requirement.

(vii) Diagnosis/test for abnormal body functions.

If the body is not functioning normally, it is said to be sick/ill. Laboratory test are done to diagnose the illness/sickness.

(b) The following career fields require Chemistry as one of subject areas of advanced/specialized study:

(i) Chemical engineering/chemical engineer

(ii) Veterinary medicine/Veterinary doctor

(iii) Medicine/Medical doctor/pharmacist/nurse

(iv) Beauty/Beautician

(v) Teaching/Chemistry teacher.

The School Chemistry Laboratory

Chemistry is studied mainly in a science room called a school chemistry laboratory. The room is better ventilated than normal classroom. It has electricity, gas and water taps. A school chemistry laboratory has a qualified professional whose called Laboratory technician/assistant.

All students user in a school chemistry laboratory must consult the Laboratory technician/assistant for all their laboratory work. A school chemistry laboratory has chemicals and apparatus.

A chemical is a substance whose composition is known. All chemical are thus labeled as they are. This is because whereas physically a substance may appear similar, chemically they may be different.

All Chemicals which are not labeled should never be used. Some chemicals are toxic/poisonous, explosive, corrosive, caustic, irritants, flammable, oxidizing, carcinogenic, or radioactive.

Care should always be taken when handling any chemical which have any of the above characteristic properties.

Common school chemistry laboratory chemicals include:

(i) Distilled water

(ii) Concentrated mineral acid which are very corrosive (on contact with skin they cause painful open wounds)

(iii) Concentrated alkali/bases which are caustic (on contact with skin they cause painful blisters)

(iv) Very many types of salts

The following safety guideline rules should be followed by chemistry laboratory users:

(i) Enter the laboratory with permission in an orderly manner without rushing/pushing/scrabbling.

(ii) Do not try unauthorized experiments. They may produce flammable, explosive or toxic substances that affect your health.

(iii) Do not taste any chemical in the laboratory. They may be poisonous.

(iv) Waft gas fumes to your nose with your palm. Do not inhale/smell gases directly. They may be highly poisonous/toxic.

(v) Boil substances with mouth of the test tube facing away from others and yourself. Boiling liquids spurt out portions of the hot liquid. Products of heating solids may be a highly poisonous/toxic gas.

(vi) Wash with lots of water any skin contact with chemicals immediately. Report immediately to teacher/laboratory technician any irritation, cut, burn, bruise or feelings arising from laboratory work.

(vii) Read and follow safety instruction. All experiments that evolve/produce poisonous gases should be done in the open or in a fume chamber.

(viii )Clean your laboratory work station after use. Wash your hand before leaving the chemistry laboratory.

(ix) In case of fire, remain calm, switch of the source of fuel-gas tap. Leave the laboratory through the emergency door. Use fire extinguishers near the chemistry laboratory to put of medium fires. Leave strong fires wholly to professional fire fighters.

(x) Do not carry unauthorized item from a chemistry laboratory.

An apparator /apparatus are scientific tools/equipment used in performing scientific experiments. The conventional apparator used in performing scientific experiments is called standard apparator/apparatus. If the conventional standard apparator/apparatus is not available, an improvised apparator/apparatus may be used in performing scientific experiments. An improvised apparator/apparatus is one used in performing a scientific experiment for a standard apparator/apparatus. Most standard apparatus in a school chemistry laboratory are made of glass because:

(i)Glass is transparent and thus reactions /interactions inside are clearly visible from outside

(ii) Glass is comparatively cheaper which reduces cost of equipping the school chemistry laboratory

(iii) Glass is comparatively easy to clean/wash after use.
(iv) Glass is comparatively unreactive to many chemicals.

Apparatus are designed for the purpose they are intended in a school chemistry laboratory:

  • Apparatus for measuring volume
  1. Measuring cylinder

Measuring cylinders are apparatus used to measure volume of liquid/ solutions. They are calibrated/ graduated to measure any volume required to the maximum. Measuring cylinders are named according to the maximum calibrated/graduated volume e.g.

“10ml” measuring cylinder is can hold maximum calibrated/graduated volume of “10mililitres” /“10 cubic centimetres”

“50ml” measuring cylinder is can hold maximum calibrated/graduated volume of “50mililitres” /“50 cubic centimetres”

“250ml” measuring cylinder is can hold maximum calibrated/graduated volume of “250mililitres” /“250 cubic centimetres”

“1000ml” measuring cylinder is can hold maximum calibrated/graduated volume of “1000mililitres” /“1000 cubic centimetres”

  1. Burette

Burette is a long and narrow/thin apparatus used to measure small accurate and exact volumes of a liquid solution. It must be clamped first on a stand before being used. It has a tap to run out the required amount out. They are calibrated/ graduated to run out small volume required to the maximum 50ml/50cm3.

The maximum 50ml/50cm3 calibration/ graduation reading is at the bottom .This ensure the amount run out from a tap below can be determined directly from burette reading before and after during volumetric analysis.

Burettes are expensive and care should be taken when using them.

  1. (i) Pipette

Pipette is a long and narrow/thin apparatus that widens at the middle used to measure and transfer small very accurate/exact volumes of a liquid solution.

It is open on either ends.

The maximum 25ml/25cm3 calibration/ graduation mark is a visible ring on one thin end.

To fill a pipette to this mark, the user must suck up a liquid solution upto a level above the mark then adjust to the mark using a finger.

This requires practice.

(ii) Pipette filler

Pipette filler is used to suck in a liquid solution into a pipette instead of using the mouth. It has a suck, adjust and eject button for ensuring the exact volume is attained. This requires practice.

  1. Volumetric flask.

A volumetric flask is thin /narrow but widens at the base/bottom. It is used to measure very accurate/exact volumes of a liquid solution.

The maximum calibration / graduation mark is a visible ring.

Volumetric flasks are named according to the maximum calibrated/graduated volume e.g.

“250ml” volumetric flask has a calibrated/graduated mark at exact volume of “250mililitres” /“250centimetres”

“1l” volumetric flask has a calibrated/graduated mark at exact volume of “one litre” /“1000 cubic centimeters”

“2l” volumetric flask has a calibrated/graduated mark at exact volume of “two litres” /“2000 cubic centimeters”

  1. Dropper/teat pipette

A dropper/teat pipette is a long thin/narrow glass/rubber apparatus that has a flexible rubber head.

A dropper/teat pipette is used to measure very small amount/ drops of liquid solution by pressing the flexible rubber head. The numbers of drops needed are counted by pressing the rubber gently at a time

(b)Apparatus for measuring mass

  1. Beam balance

A beam balance has a pan where a substance of unknown mass is placed. The scales on the opposite end are adjusted to “balance” with the mass of the unknown substance. The mass from a beam balance is in grams.

  1. Electronic/electric balance.

An electronic/electric balance has a pan where a substance of unknown mass is placed. The mass of the unknown substance in grams is available immediately on the screen.

 

(c)Apparatus for measuring temperature

A thermometer has alcohol or mercury trapped in a bulb with a thin enclosed outlet for the alcohol/mercury in the bulb.

If temperature rises in the bulb, the alcohol /mercury expand along the thin narrow enclosed outlet.

The higher the temperature, the more the expansion

Outside, a calibration /graduation correspond to this expansion and thus changes in temperature.

A thermometer therefore determines the temperature when the bulb is fully dipped in to the substance being tested. To determine the temperature of solid is thus very difficult.

(d)Apparatus for measuring time

The stop watch/clock is the standard apparatus for measuring time. Time is measured using hours, minutes and second.

Common school stop watch/clock has start, stop and reset button for determining time for a chemical reaction. This requires practice.

(e) Apparatus for scooping

  1. Spatula

A spatula is used to scoop solids which do not require accurate measurement. Both ends of the spatula can be used at a time.

A solid scooped to the brim is “one spatula end full” A solid scooped to halfbrim is “half spatula end full”.

  1. Deflagrating spoon

A deflagrating spoon is used to scoop solids which do not require accurate measurement mainly for heating. Unlike a spatula, a deflagrating spoon is longer.

(f) Apparatus for putting liquids/solid for heating.

  1. Test tube.

A test tube is a narrow/thin glass apparatus open on one side. The end of the opening is commonly called the “the mouth of the test tube”.

  1. Boiling/ignition tube.

A boiling/ignition tube is a wide glass apparatus than a test tube open on one side. The end of the opening is commonly called the “the mouth of the boiling/ignition tube”.

  1. Beaker.

Beaker is a wide calibrated/graduated lipped glass/plastic apparatus used for transferring liquid solution which do not normally require very accurate measurements

Beakers are named according to the maximum calibrated/graduated volume they can hold e.g.

“250ml” beaker has a maximum calibrated/graduated volume of “250mililitres” /“250 cubic centimeters”

“1l” beaker has a maximum calibrated/graduated volume of “one litre” /“1000 cubic centimeters”

“5 l” beaker has a maximum calibrated/graduated volume of “two litres” /“2000 cubic centimeters”

  1. Conical flask.

A conical flask is a moderately narrow glass apparatus with a wide base and no calibration/graduation. Conical flasks thus carry/hold exact volumes of liquids that have been measured using other apparatus. It can also be put some solids. The narrow mouth ensures no spillage.

Conical flasks are named according to the maximum volume they can hold e.g. “250ml” Conical flasks hold a maximum volume of “250mililitres” /“250 cubic centimeters”

“500ml” Conical flasks hold a maximum volume of “500ml” /“1000 cubic centimeters”

  1. Round bottomed flask

A round bottomed flask is a moderately narrow glass apparatus with a wide round base and no calibration/graduation. Round bottomed flask thus carry/hold exact volumes of liquids that have been measured using other apparatus. The narrow/thin mouth prevents spillage. The flask can also hold (weighed) solids. A round bottomed flask must be held/ clamped when in use because of its wide narrow base.

  1. Flat bottomed flask

A flat bottomed flask is a moderately narrow glass apparatus with a wide round base with a small flat bottom. It has no calibration/graduation.

Flat bottomed flasks thus carry/hold exact volumes of liquids that have been measured using other apparatus. The narrow/thin mouth prevents spirage. They can also hold (weighed) solids. A flat bottomed flask must be held/ clamped when in use because it’s flat narrow base is not stable.

(g) Apparatus for holding unstable apparatus (during heating).

  1. Tripod stand

A tripod stand is a three legged metallic apparatus which unstable apparatus are placed on (during heating).Beakers. Conical flasks, round bottomed flask and flat bottomed flasks are placed on top of tripod stand (during heating).

  1. Wire gauze/mesh

Wire gauze/mesh is a metallic/iron plate of wires crossings. It is placed on top of a tripod stand:

(i) Ensure even distribution of heat to prevent cracking glass apparatus

(ii) Hold smaller apparatus that cannot reach the edges of tripod stand

3 Clamp stand

A clamp stand is a metallic apparatus which tightly hold apparatus at their “neck” firmly.

A clamp stand has a wide metallic base that ensures maximum stability. The height and position of clamping is variable. This require practice

  1. Test tube holder

A test tube holder is a hand held metallic apparatus which tightly hold test/boiling/ignition tube at their “neck” firmly on the other end.

Some test tube holders have wooden handle that prevent heat conduction to the hand during heating.

  1. Pair of tong.

A pair of tong is a scissor-like hand held metallic apparatus which tightly hold firmly a small solid sample on the other end.

  1. Gas jar

A gas jar is a long wide glass apparatus with a wide base.

It is open on one end. It is used to collect/put gases.

This requires practice.

(h) Apparatus for holding/directing liquid solutions/funnels (to avoid spillage).

  1. Filter funnel

A filter funnel is a wide mouthed (mainly plastic) apparatus that narrow drastically at the bottom to a long extension.

When the long extension is placed on top of another apparatus, a liquid solution can safely be directed through the wide mouth of the filter funnel into the apparatus without spirage.

Filter funnel is also used to place a filter paper during filtration.

  1. Thistle funnel

A thistle funnel is a wide mouthed glass apparatus that narrow drastically at the bottom to a very long extension.

The long extension is usually drilled through a stopper/cork.

A liquid solution can thus be directed into a stoppered container without spillage

  1. Dropping funnel

A dropping funnel is a wide mouthed glass apparatus with a tap that narrow drastically at the bottom to a very long extension.

The long extension is usually drilled through a stopper/cork.

A liquid solution can thus be directed into a stoppered container without spillage at the rate determined by adjusting the tap.

  1. Separating funnel

A separating funnel is a wide mouthed glass apparatus with a tap at the bottom narrow extension.

A liquid solution can thus be directed into a separating funnel without spillage. It can also safely be removed from the funnel by opening the tap.

It is used to separate two or more liquid solution mixtures that form layers/immiscible. This requires practice.

 

(h) Apparatus for heating/Burners

  1. Candle, spirit burner, kerosene stove, charcoal burner/jiko are some apparatus that can be used for heating.

Any flammable fuel when put in a container and ignited can produce some heat.

  1. Bunsen burner

The Bunsen burner is the standard apparatus for heating in a Chemistry school laboratory.

It was discovered by the German Scientist Robert Wilhelm Bunsen in1854.

(a)Diagram of a Bunsen burner

 

 

A Bunsen burner uses butane/laboratory gas as the fuel. The butane/laboratory gas is highly flammable and thus usually stored safely in a secure chamber outside   Chemistry school laboratory. It is tapped and distributed into the laboratory through gas pipes.

The gas pipes end at the gas tap on a chemistry laboratory bench .If opened the gas tap releases butane/laboratory gas. Butane/laboratory gas has a characteristic odor/smell that alerts leakages/open gas tap.

The Bunsen burner is fixed to the gas tap using a strong rubber tube.

The Bunsen burner is made up of the following parts:

(i) Base plate –to ensure the burner can stand on its own

(ii)Jet-a hole through which laboratory gas enters the burner

(iii)Collar/sleeve-adjustable circular metal attached to the main chimney/burell with a side hole/entry. It controls the amount of air entering used during burning.

(iv)Air hole- a hole/entry formed when the collar side hole is in line with chimney side hole. If the collar side hole is not in line with chimney side hole, the air hole is said to be “closed” If the collar side hole is in line with chimney side hole, the air hole is said to be “open”

(v)Chimney- tall round metallic rod attached to the base plate.

(b)Procedure for lighting/igniting a Bunsen burner

  1. Adjust the collar to ensure the air holes are closed.
  2. Connect the burner to the gas tap using a rubber tubing. Ensure the rubber tubing has no side leaks.
  3. Turn on the gas tap.
  4. Ignite the top of the chimney using a lighted match stick/gas lighter/wooden splint.
  5. Do not delay excessively procedure (iv) from (iii) to prevent highly flammable laboratory gas from escaping/leaking.

(c)Bunsen burner flames

A Bunsen burner produces two types of flames depending on the amount of air entering through the air holes.

If the air holes are fully open, a non luminous flame is produced. If the air holes are fully closed, a luminous flame is produced. If the air holes are partially open/ closed, a hybrid of non luminous and luminous flames is produced.

Characteristic differences between luminous and non-luminous flame

Luminous flame Non-luminous flame

 

1. Produced when the air holes are fully/completely closed. 1. Produced when the air holes are fully/completely open.

 

2. when the air holes are fully/ completely closed there is incomplete burning/ combustion of the laboratory gas 2.when the air holes are fully/ completely open there is complete burning/ combustion of the laboratory gas

 

3. Incomplete burning/ combustion of the laboratory gas produces fine unburnt carbon particles which make the flame sooty/smoky 3. Complete burning/ combustion of the laboratory gas does not produce carbon particles. This makes the flame non-sooty /non- smoky.
4. Some carbon particles become white hot and emit light. This flame is thus bright yellow in colour producing light. This makes luminous flame useful for lighting 4. Is mainly blue in colour and is hotter than luminous flame. This makes non-luminous flame useful for heating

 

5. Is larger, quiet  and wavy/easily swayed by wind 5.Is smaller, noisy  and steady

 

 

Luminous flame has three main regions:

(i)the top yellow region where there is incomplete combustion/burning

(ii)the region of unburnt gas  below the yellow region where the gas does not burn

(iii)  blue region on the sides of region of unburnt gas where there is complete burning

Non-luminous flame has four main regions:

(i)the top colourless region

(ii)  Blue region just below where there is complete burning. It is the hottest region

(iii)  green region surrounded by the blue region  where there is complete burning

(Ii) The region of unburnt gas  at the innermost surrounded by green and blue regions. No burning takes place here

 

Scientific apparatus are drawn:

(i) Using a proportional two dimension (2D) cross-sections. Three dimensions (3D) are not recommended.

(ii) Straight edges of the apparatus on a scientific diagram should be drawn using ruler.

(iii) Curved edges of the apparatus on a scientific diagram should be drawn using free hand.

(iv)The bench, tripod or clamp to support apparatus which cannot stand on their own should be shown.

CLASSIFICATION OF SUBSTANCES

Substances are either pure or impure. A pure substance is one which contains only one substance.

An impure substance is one which contains two or more substances. A pure substance is made up of a pure solid, pure liquid or pure gas.

A mixture is a combination of two or more pure substances which can be separated by physical means. The three states of matter in nature appear mainly as mixtures of one with the other.

Common mixtures include:

(a)Solutions/solid-liquid dissolved mixture

Experiment:

To make a solution of copper (II) sulphate (VI)/Potassium magnate(VII) /sodium chloride

Procedure

Put about 100 cm3 of water in three separate beakers. Separately place a half spatula end full of copper (II) sulphate (VI), Potassium manganate (VII) and sodium chloride crystals to each beaker. Stir for about two minutes.

Observation

Copper (II) sulphate (VI) crystals dissolve to form a blue solution

Potassium manganate (VII) crystals dissolve to form a purple solution

Sodium chloride crystals dissolve to form a colourless solution

Explanation

Some solids, liquids and gases dissolve in some other liquids.

A substance/liquid in which another substance dissolves is called solvent.

A substance /solid /gas which dissolves in a solvent is called solute.

When a solute dissolves in a solvent it forms a uniform mixture called solution.

A solute dissolved in water as the solvent exists in another state of matter called aqueous state. Water is referred as the universal solvent because it dissolves many solutes. A solute that dissolves in a solvent is said to be soluble. Soluble particles uniformly spread between the particles of water/solvent and cannot be seen.

Solute         +        Solvent       ->     solution

Solute         +        Water         ->      aqueous solution of solute

 

The solute dissolved in water gives the name of the solution e. g.

  1. Sodium chloride solution is a solution formed after dissolving sodium chloride crystals/solid in water. Sodium chloride exists in aqueous state after dissolving.

Sodium chloride    +    Water     ->     Sodium chloride solution

NaCl(s)       +        (aq)  ->     NaCl(aq)

  1. Ammonia solution is a solution formed after dissolving ammonia gas in water. Ammonia exists in aqueous state after dissolving.

Ammonia gas       +    Water     ->     aqueous ammonia

NH3 (g)       +        (aq)  ->       NH3 (aq)

  1. Copper (II) sulphate (VI) solution is a solution formed after dissolving Copper (II) sulphate (VI) crystals/solid in water. Copper (II) sulphate (VI) exists in aqueous state after dissolving.

Copper (II) sulphate (VI)    +   Water     ->   Copper (II) sulphate (VI) solution

CuSO4(s)                +      (aq)  ->     CuSO4 (aq)

  1. Potassium manganate(VII) solution is a solution formed after dissolving Potassium manganate(VII) crystals/solid in water.

Potassium manganate(VII)exist in aqueous state after dissolving.

Potassium manganate(VII) + Water   -> Potassium manganate(VII) solution

KMnO4(s)              +   (aq)     ->     KMnO4 (aq)

(b)Suspension/ precipitates/solid-liquid mixture which do not dissolve

Experiment: To make soil, flour and Lead (II) Iodide suspension/precipitate

Procedure

Put about 100 cm3 of water in three separate beakers. Separately place a half spatula end full of soil, maize and lead (II) Iodide to each beaker. Stir for about two minutes.

 

Observation

Some soil, maize and lead (II) Iodide float in the water

A brown suspension/precipitate/particles suspended in water containing soil

A white suspension/precipitate/particles suspended in water containing flour

A yellow suspension/precipitate/particles suspended in water containing Lead (II) iodide. Some soil, maize and lead (II) Iodide settle at the bottom after some time.

Explanation

Some solid substances do not dissolve in a liquid. They are said to be insoluble in the solvent .When an insoluble solid is put in liquid:

(i) Some particles remain suspended/floating in the liquid to form a suspension /precipitate.

(ii) Some particles sink/settle to the bottom to form sediments after being allowed to stand.

An insoluble solid acquire the colour of the suspension/precipitate .e.g.

  1. A white suspension /precipitate have some fine white particles suspended /floating in the liquid. Not “white solution”
  2. A blue suspension /precipitate has some fine blue particles suspended /floating in the liquid.
  3. A green suspension /precipitate has some fine green particles suspended /floating in the liquid.
  4. A brown suspension /precipitate has some fine brown particles suspended /floating in the liquid.
  5. A yellow suspension /precipitate has some fine yellow particles suspended /floating in the liquid.

(c) (i) Miscibles /Liquid-liquid mixtures

To form water-ethanol and Kerosene-turpentine miscibles

Procedure

(i)Measure 50cm3 of ethanol into 100cm3 beaker. Measure 50cm3 of water. Place the water into the beaker containing ethanol. Swirl for about one minute.

(ii)Measure 50cm3 of kerosene into 100cm3 beaker. Measure 50cm3 of turpentine oil. Place the turpentine oil into the beaker containing kerosene. Swirl for about one minute.

Observation

Two liquids do not form layers.

Ethanol and water form a uniform mixture.

Kerosene and turpentine oil form uniform mixture

Explanation

Ethanol is miscible in Water. Kerosene is miscible in turpentine oil. Miscible mixture form uniform mixture. They do not form layers. The particles of one liquid are smaller than the particles of the other. The smaller particles occupy the spaces between the bigger particles.

  • Immiscibles /Liquid-liquid mixtures

To form water-turpentine oil and Kerosene-water miscibles

Procedure

(i)Measure 50cm3 of water into 100cm3 beaker. Measure 50cm3 of turpentine oil. Place the oil into the beaker containing water. Swirl for about one minute.

(ii) Measure 50cm3 of water into 100cm3 beaker. Measure 50cm3 of kerosene. Place the kerosene into the beaker containing water. Swirl for about one minute.

Observation

Two liquids form layers.

Turpentine and water do not form a uniform mixture.

Water and kerosene do not form uniform mixture

Explanation

Kerosene is immiscible in Water. Water is immiscible in turpentine oil. Immiscible mixtures do not form uniform mixtures. They form layers. The size of the particles of one liquid is almost equal to the particles of the other. The particles of one liquid cannot occupy the spaces between the particles of the other. The heavier particles settle at the bottom. The less dense particles settle on top.

(d)Solid-solid mixtures/Alloys

Before solidifying, some heated molten/liquid metals dissolve in another metal to form a uniform mixture of the two. On solidifying, a uniform mixture of the metals is formed. A uniform mixture of two metals on solidifying is called alloy. In the alloy, one metallic particle occupies the spaces between the metallic particles of the other.

  1. c) Common alloys of metal.
Alloy name Constituents of the alloy Uses of the alloy
Brass Copper and Zinc Making screws and bulb caps

 

Bronze Copper and Tin Making clock springs, electrical contacts and copper coins

 

Soldier Lead and Tin Soldering, joining electrical contacts because of its low melting points and high thermal conductivity

 

Duralumin Aluminum, Copper and Magnesium Making aircraft, utensils, and windows frames because of its light weight and corrosion resistant.

 

Steel Iron, Carbon ,Manganese and other metals Railway lines, car bodies girders and utensils.
Nichrome Nichrome and Chromium Provide resistance in electric heaters and ovens

 

German silver Copper, Zinc and Nickel Making coins

 

METHODS OF SEPARATING MIXTURES

Mixtures can be separated from applying the following methods:

(a) Decantation

Sediments can be separated from a liquid by pouring out the liquid. This process is called decantation.

Experiment

Put some sand in a beaker. Add about 200cm3 of water. Allow sand to settle. Pour off water carefully into another beaker.

 Observation

Sand settles at the bottom as sediments.

Less clean water is poured out.

Explanation

Sand does not dissolve in water. Sand is denser than water and thus settles at the bottom as sediment. When poured out, the less dense water flows out.

(b)Filtration

Decantation leaves suspended particles in the liquid after separation. Filtration is thus improved decantation.Filtration is the method of separating insoluble mixtures/particles/solids from a liquid.

Experiment: To separate soil and water using filtration

Fold a filter paper to fit well into a filter funnel. Place the funnel in an empty 250 cm3 beaker.

Put one spatula end full of soil into 50cm3 of water. Stir. Put the soil/water mixture into the filter funnel.

Observations

Clean water is collected below the filter funnel.

Soil remains above the filter paper.

Explanation

A filter paper is porous which act like a fine sieve with very small holes. The holes allow smaller water particles to pass through but do not allow bigger soil particles. The liquid which passes through is called filtrate. The solid which do not pass through is called residue.

Set up of apparatus

 

In industries, filtration is used in engine filters to clean up air.

 

(c)Evaporation

Evaporation is a method of separating a solute/solid from its solution. This involves heating a solution (solvent and solute)to vapourize the solvent out of the solution mixture leaving pure solute/solid. If a mixture contain insoluble solid, they are filtered out.

Experiment: To separate a mixture of soil and salt (sodium chloride).

 

Procedure:

Put one spatula end full of soil on a filter paper.

Put one spatula full of common salt/sodium chloride into the same filter paper. Mix well using the spatula,.

Place about 200cm3 of water into a beaker.

Put the contents of the filter paper into the water. Stir thoroughly using a glass/stirring rod for about one minute.

Fold a filter paper into a filter funnel.

Pour half portion of the contents in the beaker into the filter funnel.

Put the filtrate into an evaporating dish. Heat on a water bath.

 Observation

(i)On mixing

Colourless crystals and brown soil particles appear on the filter paper.

(ii)On adding water

Common soil dissolves in water. Soil particles do not dissolve in water.

(iii)On filtration

Colourless liquid collected as filtrate below the filter funnel/paper.

Brown residue collected above the filter funnel/paper.

(iv)On evaporation

Colourless crystals collected after evaporation

Explanation

Solid mixture of sand and common salt take the colors of the two.

On adding water, common salt dissolves to form a solution.

Soil does not because it is insoluble in water and thus forms a suspension.

On filtration, a residue of insoluble soil does not pass through the filter paper.

It is collected as residue.

Common salt solution is collected as filtrate.

On heating the filtrate, the solvent/water evaporate/vaporize out of the evaporating dish leaving common salt crystals.

Vapourization/evaporation can take place even without heating.

This is the principle/process of drying wet clothes on the hanging line.

 

 

 

 

Set up of apparatus

 

(d) Distillation

Distillation is an improved evaporation where both the solute and the solvent in the solution are separated /collected. Distillation therefore is the process of separating a solution into constituent solid solute and the solvent. It involves heating the solution to evaporate/vaporize the solvent out. The solvent vapour is then condensed back to a liquid.

Experiment: To obtain copper (II) sulphate (VI) crystals and water from copper (II) sulphate (VI) solution.

Procedure:

Put one spatula end full of copper (II) sulphate (VI) crystals into a 250cm3 beaker.

Place about 200cm3 of water into the beaker.

Stir thoroughly using a glass/stirring rod for about one minute.

Pour half portion of the contents in the beaker into a round bottomed/flat/conical flask broken porcelain/sand/glass into the flask.

Put a few pieces of b Stopper the flask.

Connect the flask to a Liebig condenser using delivery tube.

Place a 200cm3 clean empty beaker/conical flask as a receiver at the end of the Liebig condenser.

Circulate water in the Liebig condenser.

Heat the flask strongly on a tripod stand with wire mesh/gauze until there is no more visible boiling bubbles in the flask.

Observation  

Copper (II) sulphate (VI) crystals dissolve in water to form a blue solution.
On heating, colourless liquid is collected in the receiver.

Blue crystals are left in the flask.

(If gently heated further, the blue crystals turn to white powder)

Explanation

On heating blue Copper (II) sulphate (VI) solution, the colourless liquid solvents evaporate/vaporize.

The liquid vapour/gas passes through the delivery tube to the Liebig condenser.

The Liebig condenser has a cold water inlet near the receiver and cold water out let.

This ensures efficient cooling. If the cold water outlet/inlet is reversed, the water circulation would be less efficient.

The water in the receiver would be warm. In the Liebig condenser, the cold water condenses the liquid vapour into liquid.

The condensed liquid collects in the receiver as distillate.

The solute of blue Copper (II) sulphate (VI) crystals is left in the flask as residue.

During simple distillation, therefore, the solution is heated to vaporize /evaporate the solvent/one component which is condensed at a different part of the apparatus.

The purpose of pieces of broken porcelain/porous pot/glass/sand/ is to:

(i) Prevent bumping of the solution during boiling.

(ii) Ensure smooth and even boiling.

Salty sea water can be made pure through simple distillation.

Any mixture with a large difference /40oC in boiling point can be separated using simple distillation.

Set up of apparatus

 

e)Fractional distillation

Fractional distillation is an improved simple distillation used specifically to separate miscible mixtures with very close /near boiling points.

Fractional distillation involves:

(i) Heating the mixture in a conical/round bottomed /flat bottomed flask.

The pure substance with a lower boiling point and thus more volatile evaporates/boils/vaporize first.e.g. Pure ethanol has a boiling point of 78oC.Pure water has a boiling point of 100 oC at sea level/one atmosphere pressure.

When a miscible mixture of ethanol and water is heated, ethanol vaporizes /boils/ evaporates first because it is more volatile.

(ii)The conical/round bottomed /flat bottomed flask is connected to a long glass tube called fractionating column.

The purpose of the fractionating column is to offer areas of condensation for the less volatile pure mixture.

The fractionating column is packed with glass beads/broken glass/ porcelain/ shelves to increase the surface area of condensation of the less volatile pure mixture.

(iii)When the vapors rise they condense on the glass beads/broken glass /porcelain / shelves which become hot.

When the temperature of the glass beads/broken glass/porcelain/shelves is beyond the boiling point of the less volatile pure substance, the pure substance rise and condensation take place on the glass beads/broken glass/porcelain/shelves at a higher level on the fractionating column.

The less volatile pure substance trickles/drips back down the fractionating column or back into the conical/round bottomed /flat bottomed flask to be heated again. e.g.

If the temperature on glass beads/broken glass/porcelain/shelves is beyond 78oC, the more volatile pure ethanol rise to condense on the glass beads/broken glass /porcelain/shelves higher in the fractionating column.

Water condenses and then drip/trickle to the glass beads/broken glass /porcelain /shelves lower in the fractionating column because it is less volatile.

(iv) The fractionating column is connected to a Liebig condenser. The Liebig condenser has a cold water inlet and outlet circulation.

The more volatile mixture that reach the top of the fractionating column is condenses by the Liebig condenser into a receiver. It is collected as the first fraction.

(v)At the top of the fractionating column, a thermometer is placed to note/monitor the temperature of the boiling mixtures.

Pure substances have constant/fixed boiling point. When one mixture is completely separated, the thermometer reading rises.

E.g. the thermometer reading remains at78oC when ethanol is being separated. When no more ethanol is being separated, the mercury/alcohol level in the thermometer rises.

(vi)The second /subsequent fractions are collected in the receiver after noting a rise the mercury/alcohol level in the thermometer.

E.g. the thermometer reading rises to 100oC when water is being separated. It is passed through the Liebig condenser with the cold water inlet and outlet circulation. It is collected different receiver as the second/subsequent fraction.

(vii)Each fraction collected should be confirmed from known physical/chemical properties/characteristic.

Example

Ethanol

Ethanol is a colourless liquid that has a characteristic smell .When it is put in a watch glass then ignited, it catches fire and burn with a blue flame.

Water

Water is a colourless liquid that has no smell/odour .When it is put in a watch glass then ignited, it does not catch fire.

Set up of apparatus

         

Industrial application of Fractional distillation

On a large scale,fractional distillation is used:

(i)In fractional distillation of crude oil in an oil refinery.

Crude oil is a mixture of many fractions. When heated in a furnace, the different fractions separate out according to their boiling point. In Kenya,fractional distillation takes place at Changamwe in Mombasa.

(ii)In fractional distillation of air.

Air contain a mixture of three main useful gases which are condensed by cooling to very low temperature (-200oC) to form a liquid. The liquid is then heated. Nitrogen is the most volatile (-196 oC) and thus comes out as the first fraction. Argon (at -186 oC) is the second fraction. Oxygen ( at -183 oC) is the last fraction. The three gases are very useful industrial gases.

(f)Separation of immiscibles (Using a separating funnel)

Two or more liquids that form layers on mixing are immiscible. Immiscible mixture arrange themselves according to their densities

i.e. The denser liquid sink to the bottom. The less dense liquid floats on the denser one. Immicible mixtures can be separated from each other by using a separating funnel.

Experiment: To separate an immiscible mixture of paraffin and water.

Procedure

Place about 100cm3 of water into a 250cm3 beaker. Add about 100cm3 of paraffin into the beaker. Stir.

Transfer the mixture into a separating funnel. Allow to settle for about one minute. Open the tap, run out the lower layer out slowly into a clean beaker. Close the tap when the upper layer is very close to the tap.

Run out the intermediate small amount of the mixture near the tap into a beaker. Discard it.

Run out the remaining upper layer into a fresh beaker.

Place a portion of upper and lower layer into a watch glass separately after separating each. Ignite.

Observation

Water and paraffin are both colourless liquids.

Two layers are formed on mixing.

Colourless odorless liquid collected first. It does not catch fire.

A colourless liquid with characteristic smell collected later/second. It catches fire and burn with a yellow smoky flame.

Explanation

Water and paraffin are immiscible. Water is denser than paraffin. When put in a separating funnel, paraffin float on water. On opening the tap, water runs out. A mixture of water and paraffin at the junction of the two is discarded. It is not pure.

Set up of apparatus

 

(g)Sublimation/deposition

Some solids on heating do not melt to a liquid but change directly to a gas. The process by which a solid changes to a gas is called sublimation. The gas cools back and changes directly to a solid. The process by which a gas changes to a solid is called deposition. Sublimation and deposition therefore are the same but opposite processes.

          GAS

 

 

 

 

 

 

Sublimation                   Deposition

SOLID

 

 

 

 

Some common substances that undergo sublimation/ deposition include:

(i)Iodine                         (ii)Carbon(IV)oxide             (iii)Camphor                 (iv) ammonium chloride         (v)Iron(III)chloride                 (vi)Aluminum(III)chloride

(vii) benzoic acid

If a mixture has any of the above as a component, then on heating it will change to a gas and be deposited away from the source of heating.

Procedure

Place about one spatula full of ammonium chloride crystals into a clean dry 100cm3 beaker. Add equal amount of sodium chloride crystals into the beaker. Swirl to mix.

Place the beaker on a tripod stand.

Put about 100cm3 of water into another beaker. Place carefully the beaker containing water on top of the beaker containing the solid mixture. Light/ignite a burner and heat the solid.

Set up of apparatus:

 

Observation

(i)With ammonium chloride/common salt mixture

White fumes produced.

White sublimate deposited

Colourless residue left

(ii)With Iodine/common salt mixture

Purple fumes produced.

Dark grey sublimate deposited

Colourless residue left

Explanation

(i)On heating a mixture of ammonium chloride and common salt, a white fume of ammonium chloride is produced. The white fumes solidify as white sublimate on the cooler parts. Common salt remains as residue.

Chemical equation:

Ammonium chloride solid                          Ammonium chloride gas

 

NH4Cl(s)                                  NH4Cl(g)

(ii)On heating a mixture of Iodine and common salt, a purple fume of Iodine vapour is produced. The purple fumes solidify as dark grey sublimate on the cooler parts. Common salt remains as residue.

Chemical equation:

Iodine solid                         Iodine gas

 

I2(s)                              I2 (g)

(h)Chromatography

Chromatography is a method of separating components of a solution mixture by passing it through a medium where the different components move at different rates. The medium through which the solution mixture is passed is called absorbent material.

Paper chromatography is a method of separating colored dyes by using paper as the absorbent material.

Since dyes are insoluble/do not dissolve in water, ethanol and propanone are used as suitable solvents for dissolving the dye.

Practically, a simple paper chromatography involve placing a dye/material on the absorbent material, adding slowly a suitable soluble solvent on the dye/material using a dropper, the solvent spread out on the absorbent material carrying the soluble dye away from the origin.

The spot on which the dye is initially/originally placed is called baseline. The farthest point the solvent spread is called solvent front.

The farthest a dye can be spread by the solvent depend on:

(i) Density of the dye-the denser the dye, the less it spread from the basely ne by the solvent.

(ii) Stickiness of the dye-some dyes sticks on the absorbent material more than other thus do not spread far from baseline.

Experiment: To investigate the colors in ink

Procedure

Method 1

Place a filter paper on an empty beaker. Put a drop of black/blue ink in the centre of the filter paper. Wait for about one minute for the ink drop to spread. Using a clean teat pipette/dropper add one drop of ethanol/propanone. Wait for about one minute for the ink drop to spread further. Add about twenty other drops of ethanol waiting for about one minute before each addition. Allow the filter paper to dry.

Experiment: To investigate the colors in ink

Procedure

Method 2

Cut an 8 centimeter thin strip of a filter paper.  At   about 3cm on the strip, place a drop of ink. Place the filter paper in a 10cm length boiling tube containing 5cm3 of ethanol. Ensure the cut strip of the filter paper just dips into the ethanol towards the ink mark. Cover the boiling tube. Wait for about twenty minutes. Remove the boiling tube and allow the filter paper to dry.

Set up of apparatus

Method 1

Set up of apparatus

Method 2

 

Explanation

When a drop of ink is placed on an absorbent material it sticks. On adding an eluting solvent, it dissolves the dye spread out with it. The denser and sticky pure dye move least. The least dense/sticky pure dye move farthest.  A pure dye will produce the same chromatogram/spot if the same eluting solvent is used on the same absorbent material. Comparing the distance moved by a pure dye with a mixture, the coloured dyes in a mixture can be deduced as below:

Example 1

The chromatogram of pure dyes A, B ,C and a dye mixture D is shown below Determine the pure dyes present in D. On the diagram show:

(i)the solvent front

(ii) Baseline

(Iii) the most soluble pure dye

(i) Solvent extraction

Solvent extraction is a method of separating oil from nuts/seeds. Most nuts contain oil. First the nuts are crushed to reduce their size and increase the surface area. A suitable volatile solvent is added. The mixture is filtered. The filtrate solvent is then allowed to crystallize leaving the oil/fat. If a filter paper is rubbed/smeared with the oil/fat, it becomes translucent. This is the test for the presence of oil/fat.

Experiment: To extract oil from Macadamia nut seeds 

Procedure

Crush Macadamia nut seeds form the hard outer cover .Place the inner soft seed into a mortar. Crush (add a little sand to assist in crushing).

Add a little propanone and continue crushing. Continue crushing and adding a little propanone until there is more liquid mixture than the solid. Decant/filter. Put the filtrate into an evaporating dish. Vapourize the solvent using solar energy /sunlight. Smear/rub a portion of the residue left after evaporation on a clean dry filter paper.

Observation /Explanation

Propanone dissolve fat/oil in the macadamia nuts. Propanone is more volatile (lower boiling point) than oil/fat. In sunlight/solar energy, propanone evaporate/vaporize leaving oil/fat(has a higher boiling point).Any seed like corn, wheat , rice, soya bean may be used instead of macadamia seed. When oil/fat is rubbed/ smeared on an opaque paper, it becomes translucent.

(j) Crystallization

Crystallization is the process of using solubility of a solute/solid to obtain the solute/solid crystals from a saturated solution by cooling or heating the solution.

A crystal is the smallest regular shaped particle of a solute. Every solute has unique shape of its crystals.

Some solutions form crystals when heated. This is because less solute dissolves at higher temperature. Some other solutions form crystals when cooled. This is because less solute dissolves at lower temperature.

Experiment; To crystallize copper (II) sulphate (VI) solution

 Procedure:

Place about one spatula full of hydrated copper sulphate (VI) crystals into 200cm3 of distilled water in a beaker. Stir. Continue adding a little more of the hydrated copper sulphate (VI) crystals and stirring until no more dissolve. Decant/filter. Cover the filtrate with a filter paper. Pierce and make small holes on the filter paper cover. Preserve the experiment for about seven days.

Observation/Explanation

Large blue crystals formed

When hydrated copper (II) sulphate crystals are placed in water, they dissolve to form copper (II) sulphate solution. After some days water slowly evaporate leaving large crystals of copper (II) sulphate. If the mixture is heated to dryness, small crystals are formed.

Physical/Temporary and Chemical changes

A physical/temporary change is one which no new substance is formed and is reversible back to original.

A chemical/permanent change is one which a new substance is formed and is irreversible back to original.

The following experiments illustrates physical and chemical changes

(a)Heating ice

Place about 10g of pure ice in a beaker. Determine its temperature. Record it at time “0.0” in the table below. Heat the ice on a strong Bunsen flame and determine its temperature after every 60seconds/1minute to complete the table below:

Time/minutes 0 1 2 3 4 5 6 7 8
Temperature (oC) -2 0 0 40 80 90 95 95 96

Plot a graph of time against Temperature (y-axes)

Explain the shape of your graph

Melting/freezing/fusion/solidification and boiling /vaporization /evaporation are the two physical processes.

Melting /freezing point of pure substances is fixed /constant.

The boiling point of pure substance depends on external atmospheric pressure.

Melting/fusion is the physical change of a solid to liquid.

Freezing is the physical change of a liquid to solid.

Melting/freezing/fusion/solidification is therefore two opposite but same reversible physical processes i.e.

A (s)                           A (l)

Boiling/vaporization/evaporation is the physical change of a liquid to gas.

Condensation/ liquidification is the physical change of gas to liquid.

Boiling/vaporization/evaporation and condensation/ liquidification are therefore two opposite but same reversible physical processes i.e.

B (l)                            B(g)

Practically

(i) Melting/liquidification/fusion involves heating a solid to weaken the strong bonds holding the solid particles together.

Solids are made up of very strong bonds holding the particles very close to each other (Kinetic Theory of matter).

On heating these particles gain energy/heat from the surrounding heat source to form a liquid with weaker bonds holding the particles close together but with some degree of freedom.

(ii)Freezing/fusion/solidification involves cooling a liquid to reform /rejoin the very strong bonds to hold the particles very close to each other as solid and thus lose their degree of freedom (Kinetic Theory of matter).

Freezing /fusion / solidification is an exothermic (∆H) process that require particles holding the liquid together to lose energy to the surrounding.

(iii)Boiling/vaporization/evaporation involves heating a liquid to completely break/free the bonds holding the liquid particles together.

Gaseous particles have high degree of freedom (Kinetic Theory of matter).

Boiling /vaporization / evaporation is an endothermic (+∆H) process that require/absorb energy from the surrounding.

(iv)Condensation/liquidification is reverse process of boiling /vaporization / evaporation.

It involves gaseous particles losing energy to the surrounding to form a liquid.

 

AIR OXYGEN AND COMBUSTION

A.THE ATMOSPHERE

  1. The atmosphere is made up of air. Air is a mixture of colourless, odorless gases which is felt as wind (air in motion).All living things breath in air for respiration. Plants use air for respiration and photosynthesis.
  2. The main gases present in the atmosphere/air:

 

Gas Approximate % composition by volume
Nitrogen 78.0
Oxygen 21.0
Carbon(IV)oxide 0.03
Noble gases 1.0
Water vapour Vary from region

 

  1. The following experiments below shows the presence and composition of the gases in air/atmosphere

 

(a)To find the composition of air supporting combustion using a candle stick

 

Procedure

Measure the length of an empty gas jar M1. Place a candle stick on a Petri dish. Float it on water in basin/trough. Cover it with the gas jar. Mark the level of the water in the gas jar M2. Remove the gas jar. Light the candle sick. Carefully cover it with the gas jar. Observe for two minutes. Mark the new level of the water M3.

Set up of apparatus

Sample observations

Candle continues to burn then extinguished/goes off

Level of water in the gas jar rises after igniting the candle

Length of empty gas jar = M1= 14cm

Length of gas jar without water before igniting candle = M2= 10 cm

Length of gas jar with water before igniting candle = M1 – M2= 14- 10 = 4 cm

Length of gas jar with water after igniting candle = M3 = 8 cm

Length of gas jar without water after igniting candle = M1 – M3 = 10 -8 = 2 cm

Explanation

Candle burns in air. In a closed system (vessel), the candle continues to burn using the part of air that support burning/combustion. This is called the active part of air. The candle goes off/extinguished when all theactive part of air is used up. The level of the water rises to occupy the space /volume occupied by the usedactive part of air.

The experiment is better when very dilute sodium/potassium hydroxide is used instead of water. Dilute Potassium/ sodium hydroxide absorb Carbon (IV) oxide gas that comes out from burning/combustion of candle stick.

From the experiment above the % composition of the:

(i) Active part of air can be calculated:

M2 – M3 x 100%   =>      10- 8 x 100% = 20%

M2                               10cm

(ii) Inactive part of air can be calculated:

100% –20% = 80%   //   M3     =>     8   x 100% = 80%

                                                                                          M2                     10cm

(b)To find the composition of active part of air using heated copper turnings.

Procedure

Clamp a completely packed/filled open ended glass tube with copper turnings. Seal the ends with glass/cotton wool.

Label two graduated syringes as “A” and “B” Push out air from syringe “A”. Pull in air into syringe “B”.

Attach both syringe “A” and “B” on opposite ends of the glass tube.

Determine and record the volume of air in syringe “B” V1.

Heat the glass tube strongly for about three minutes.

Push all the air slowly from syringe “B” to syringe “A” as heating continues. Push all the air slowly from syringe “A” back to syringe “B” and repeatedly back and forth.

After about ten minutes, determine the new volume of air in syringe “B” V2

Set up of apparatus

 

Sample observations

Colour change from brown to black

Volume of air in syringe “B” before heating    V1             = 158.0cm3

Volume of air in syringe “B” after heating       V2         = 127.2cm3

Volume of air in syringe “B” used by copper    V1 – V2 = 30.8cm3

 

Sample questions

  1. What is the purpose of:

(i) glass/cotton wool

To prevent/stop copper turnings from being blown into the syringe/out of the glass tube

(ii) Passing air through the glass tube repeatedly

To ensure all the active part of air is used up

(iii) Passing air through the glass tube slowly

To allow enough time of contact between the active part of and the heated copper turnings

  1. State and explain the observations made in the glass tube.

Colour change from brown to black

Brown copper metal reacts with the active part of air/oxygen to form black copper (II) oxide.

Chemical equation

Copper   +        Oxygen      ->      Copper (II) oxide

2Cu(s)    +            O2 (g)        ->          2CuO(s)

 

The reaction reduces the amount/volume of oxygen in syringe “B” leaving the inactive part of air. Copper only react with oxygen when heated.

  1. Calculate the % of

(i) Active part of air

% active part of air =     V1 – V2 x 100%       =>   30.8cm3 x 100% = 19.493%

V1                                                158.0cm3

(ii) Inactive part of air

Method 1

% inactive part of air = V2 x 100%    =>127.2cm3 x 100% = 80.506%

V1                                     158.0cm3

Method 2

% inactive part of air = 100% -% active part of air

=> 100 % – 19.493 % = 80.507%

  1. The % of active part of air is theoretically higher than the above while % of inactive part of air is theoretically lower than the above. Explain.

Not all the active part of air reacted with copper

  1. State the main gases that constitute:

(a )active part of air.

Oxygen

 

(b) Inactive part of air

Nitrogen, carbon (IV) oxide and noble gases

 

  1. If the copper turnings are replaced with magnesium shavings the % of active part of air obtained is extraordinary very high. Explain.

Magnesium is more reactive than copper. The reaction is highly exothermic. It generates enough heat for magnesium to react with both oxygen and nitrogen in the air.

A white solid/ash mixture of Magnesium oxide and Magnesium nitride is formed. This considerably reduces the volume of air left after the experiment.

Chemical equation

Magnesium     +        Oxygen      ->      magnesium (II) oxide

2Mg(s)              +            O2 (g)        ->          2MgO(s)

Magnesium       +       Nitrogen    ->      magnesium (II) nitride

3Mg(s)               +            N2 (g)        ->           Mg3N2 (s)

(c)To find the composition of active part of air using alkaline pyrogallol

Procedure

Measure about 2cm3 of dilute sodium hydroxide into a graduated gas jar. Record the volume of the graduated cylinder V1.

Place about two spatula end full of pyrogallol/1, 2, 3-trihydroxobenzene into the gas jar. Immediately place a cover slip firmly on the mouth of the gas jar. Swirl thoroughly for about two minutes.

Invert the gas jar in a trough/basin containing water. Measure the volume of air in the gas jar V2

Sample observations

Colour of pyrogallol/1, 2, 3-trihydroxobenzene change to brown.

Level of water in gas jar rises when inverted in basin/trough.

Volume of gas jar /air in gas jar V1= 800cm3

Volume of gas jar /air in gas jar after shaking with alkaline pyrogallol/1, 2, 3-trihydroxobenzene V2= 640 cm3

Sample questions

  1. Which gas is absorbed by alkaline pyrogallol/1,2,3-trihydroxobenzene

Oxygen

  1. Calculate the

(i) % of active part of air

V1-V2 x 100%         => (800cm3 – 640 cm3) x 100%     = 20%

V1                             800cm3

(ii) % of inactive part of air

V2 x 100%           =>     640 cm3 x 100%     = 80%

V1                        800cm3

(d)To establish the presence of carbon (IV) oxide in air using lime water

Pass tap water slowly into an empty flask as in the set up below

Sample observation questions

  1. What is the purpose of paper cover?

To ensure no air enters into the lime water.

  1. What happens when water enters the flask?

It forces the air from the flask into the lime water.

  1. What is observed when the air is bubbled in the lime water?

A white precipitate is formed. The white precipitate dissolves on prolonged bubbling of air.

  1. (a) Identify the compound that form:

          (i)lime water

Calcium hydroxide / Ca(OH)2

(ii) White precipitate

                    Calcium carbonate/ CaCO3

               (iii) When the white precipitate dissolves

                    Calcium hydrogen carbonate/ CaHCO3

     (b)Write the chemical equation for the reaction that tale place when:

          (i) White precipitate is formed

          Calcium hydroxide   +   carbon (IV) oxide   -> Calcium carbonate   +   water

Ca (OH) 2(aq)     +   CO2 (g)     ->   CaCO3(s)   + H2O (l)

(ii) White precipitate dissolves

Calcium carbonate +   water+   carbon (IV) oxide -> Calcium hydrogen carbonate

CaCO3(s)        + H2O (l) +       CO2 (g) -> CaHCO3 (aq)

  1. State the chemical test for the presence of carbon (IV) oxide gas based on 4(a) and (b) above:

Carbon (IV) oxide forms a white precipitate with lime water that dissolves in excess of the gas.

  1. State the composition of carbon (IV) oxide gas by volume in the air.

                    About 0.03% by volume

B.OXYGEN

  1. a) Occurrence.
  2. Fifty 50% of the earth’s crust consist of Oxygen combined with other elements e.g. oxides of metals
  3. About 70% of the earth is water made up of Hydrogen and Oxygen.
  4. About 20% by volume of the atmospheric gases is Oxygen that form the active part of air.
  5. b) School laboratory preparation.

Oxygen was first prepared in 1772 by Karl Scheele and later in 1774 by Joseph Priestly. It was Antony Lavoisier who gave it the name “Oxygen”

Procedure

Method 1: Using Hydrogen peroxide

Half fill a trough/basin with tap water. Place a bee hive shelf/stand into the water.

Completely fill the gas jar with water and invert in onto the bee hive shelf/stand.

Clamp a round bottomed flask and set up the apparatus as below.

Collect several gas jars of Oxygen covering each sample.

Sample observation questions

  1. What is observed when the hydrogen peroxide is added into the flask?

Rapid effervescence/bubbling/fizzing

  1. Describe the colour and smell of the gas

Colourless and odorless

  1. (a)Name the method of gas collection used.

          –Over water

-Upward delivery

-Down ward displacement of water

   (b)What property of Oxygen makes it to be collected using the method above?

          -Slightly soluble in water

  1. What is the purpose of manganese (IV) oxide?

          Manganese (IV) oxide is catalyst.

A catalyst is a substance that speeds up the rate of a chemical reaction but remain chemically unchanged at the end of the reaction.

Hydrogen peroxide decomposes slowly to form water and Oxygen gas.

A little Manganese (IV) oxide speeds up the rate of decomposition by reducing the time taken for a given volume of Oxygen to be produced.

  1. Write the equation for the reaction.

          Hydrogen peroxide    ->          Water     +      Oxygen

2H2O2 (aq)                 -> 2H2O (l)   +        O2 (g)

  1. Lower a glowing splint slowly into a gas jar containing Oxygen gas. State what is observed.

The glowing splint relights/rekindles

Oxygen relights/rekindles a glowing splint. This is the confirmatory test for the presence of Oxygen gas

Method 1: Using Sodium peroxide

Half fill a trough/basin with tap water. Add four drops of phenolphthalein indicator.

Place a bee hive shelf/stand into the water.

Completely fill a gas jar with water and invert in onto the bee hive shelf/stand.

Clamp a round bottomed flask and set up the apparatus as below.

Collect several gas jars of Oxygen covering each sample.

Sample observation questions

  1. What is observed when water is added?

(i) Into the flask containing sodium peroxide

Rapid effervescence/bubbling/fizzing

(ii) Phenolphththalein

Remains colourless /Phenolphthalein indicator is colourless in neutral solution

  1. Describe the colour and smell of the gas

Colourless and odorless

3.(a)Name the method of gas collection used.

 –Over water. Oxygen is slightly soluble in water.

  1. Test the gas by lowering a glowing splint slowly into a gas jar containing the prepared sample.

The glowing splint relights/rekindles. This confirms the presence of Oxygen gas

  1. Write the equation for the reaction.

          Sodium peroxide + Water     -> Sodium hydroxide    +      Oxygen

2Na2O2 (aq)          + 2H2O (l)   -> 4NaOH (aq)       +         O2 (g)

 

  1. Test the gas by lowering a glowing splint slowly into a gas jar containing the prepared sample.

The glowing splint relights/rekindles.

This confirms the presence of Oxygen gas

  1. Write the equation for the reaction.

Potassium Chlorate (V)     -> Potassium Chloride   + Oxygen

2KClO3 (aq)                   ->        2KCl (aq)       +         3O2 (g)

  1. What is the purpose of manganese (IV) oxide?

Manganese (IV) oxide is catalyst.

A catalyst is a substance that speeds up the rate of a chemical reaction but remain chemically unchanged at the end of the reaction.

Potassium Chlorate (V) decomposes slowly to form potassium chloride and Oxygen gas.

A little Manganese (IV) oxide speeds up the rate of decomposition by reducing the time taken for a given volume of Oxygen to be produced.

(c)Uses of Oxygen

  1. Oxygen is put in cylinders for use where natural supply is not sufficiently enough. This is mainly in:

(i)Mountain climbing/Mountaineering-at high altitudes, the concentration of air/oxygen is low. Mountain climbers must therefore carry their own supply of oxygen for breathing.

(ii) Deep sea diving-Deep sea divers carry their own supply of Oxygen.

(iii) Saving life in hospitals for patients with breathing problems and during anesthesia.

  1. A mixture of oxygen and some other gases produces a flame that is very hot.

(i) Oxy-acetylene/ethyne flame is produced when Ethyne/acetylene gas is burnt in pure oxygen. The flame has a temperature of about 3000oC.It is used for welding /cuttingmetals.

(ii)Oxy-hydrogen flame is produced when Hydrogen is burn in pure oxygen. The flame has a temperature of about 2000oC.It is used also for welding /cuttingmetals.

  1. Oxy-hydrogen mixture is used as rocket fuel
  2. A mixture of charcoal, petrol and liquid Oxygen is an explosive.

(d) Chemical properties of Oxygen /combustion.

Oxygen is a very reactive non metal. Many elements react with oxygen through burning to form a group of compounds called Oxides.

Burning/combustion is the reaction of Oxygen with an element/substances.

Reaction in which a substance is added oxygen is called Oxidation reaction. Burning/combustion are an example of an oxidation reaction.

Most non metals burn in Oxygen/air to form an Oxide which in solution / dissolved in water is acidic in nature. They turn blue litmus red.e.g. Carbon (IV) oxide/CO2, Nitrogen (IV) oxide/ NO2, Sulphur (IV) oxide/ SO2

Some non metals burn in Oxygen/air to form an Oxide which in solution / dissolved in water is neutral in nature. They don’t turn blue or red litmus. E.g. Carbon (II) oxide/CO, Water/ H2O

All metals burns in Oxygen/air to form an Oxide which in solution/dissolved in water is basic/alkaline in nature. They turn red litmus blue.e.g.

Magnesium oxide/MgO, Sodium Oxide/ Na2O, Copper (II) oxide/CuO
Elements/substances burn faster in pure Oxygen than in air

Air contains the inactive part of air that slows the rate of burning of substances/elements.

(i)Reaction of metals with Oxygen/air

The following experiments show the reaction of metals with Oxygen and air.

  1. Burning Magnesium

Procedure

(a)Cut a 2cm length piece of magnesium ribbon. Using a pair of tongs introduce it to a Bunsen flame. Remove it when it catches fire. Observe.

Place the products in a beaker containing about 5cm3 of water. Test the solution/mixture using litmus papers

(b)Cut another 2cm length piece of magnesium ribbon. Using a pair of tongs introduce it to a Bunsen flame. When it catches fire, lower it slowly into a gas jar containing Oxygen.

Place about 5cm3 of water into the gas jar. Test the solution/mixture using litmus papers. Test the solution/mixture using litmus papers

Observations

(a)In air

Magnesium burns with a bright blindening flame in air forming white solid/ash /powder. Effervescence/bubbles/ fizzing Pungent smell of urine. Blue litmus paper remains blue. Red litmus paper turns blue

(b) In pure Oxygen 

Magnesium burns faster with a very bright blindening flame pure oxygen forming white solid/ash /powder. No effervescence/bubbles/ fizzing. No pungent smell of urine. Blue litmus paper remains blue. Red litmus paper turns blue

Explanation

Magnesium burns in air producing enough heat energy to react with both Oxygen and Nitrogen to form Magnesium Oxide and Magnesium nitride. Both Magnesium Oxide and Magnesium nitride are white solid/ash /powder.

Chemical equations

Magnesium     +      Oxygen      ->      Magnesium Oxide

2Mg(s)    +          O2(g)      ->             2MgO(s)

 

Magnesium     +      Nitrogen      ->      Magnesium Nitride

3Mg(s)    +          N2(g)      ->             Mg3N2 (s)

Magnesium Oxide dissolves in water to form a basic/alkaline solution of Magnesium hydroxide

Chemical equations

Magnesium Oxide     +      Water         ->      Magnesium hydroxide

2Mg(s)            +          O2 (l)      ->             2MgO(s)

Magnesium Nitride dissolves in water to form a basic/alkaline solution of Magnesium hydroxide and producing Ammonia gas. Ammonia is also an alkaline/basic gas that has a pungent smell of urine.

Chemical equations

Magnesium Nitride + Water     ->   Magnesium hydroxide + Ammonia gas

Mg3N2 (s)          +   6H2O (l)      ->       3Mg (OH)2 (aq)   +     2NH3(g)

  1. Burning Sodium

Procedure

(a)Carefully cut a very small piece of sodium. Using a deflagrating spoon introduce it to a Bunsen flame. Remove it when it catches fire. Observe.

Place the products in a beaker containing about 20cm3 of water. Test the solution/mixture using litmus papers

(b) Carefully cut another very small piece of sodium. Using a deflagrating spoon introduce it to a Bunsen flame. When it catches fire, lower it slowly into a gas jar containing Oxygen.

Place about 20 cm3 of water into the gas jar. Test the solution/mixture using litmus papers. Test the solution/mixture using litmus papers

Observations

(a)In air

Sodium burns with a yellow flame in air forming a black solid. Blue litmus paper remains blue. Red litmus paper turns blue

(b) In pure Oxygen 

Sodium burns faster with a golden yellow flame in pure oxygen forming a yellow solid. Effervescence/bubbles/ fizzing. Gas produced relights glowing splint. Blue litmus paper remains blue. Red litmus paper turns blue.

Explanation

(a)Sodium burns in air forming black Sodium Oxide

Chemical equations

Sodium     +      Oxygen/air      ->      Sodium Oxide

4Na(s)    +          O2 (g)             ->             2Na2O(s)

Sodium Oxide dissolves in water to form a basic/alkaline solution of Sodium hydroxide

Chemical equations

Sodium Oxide     +      Water            ->      Sodium hydroxide

Na2O(s)          +      H2O (l)          ->             2NaOH (aq)

(b)Sodium burns in pure oxygen forming yellow Sodium peroxide

Chemical equations

Sodium     +      Oxygen      ->      Sodium peroxide

2Na(s)    +          O2 (g)      ->             Na2O2 (s)

Sodium peroxide dissolves in water to form a basic/alkaline solution of Sodium hydroxide. Oxygen is produced.

Chemical equations

Sodium Oxide     +      Water            ->      Sodium hydroxide +   Oxygen

2Na2O2 (s)       +      2H2O (l)       ->             4NaOH (aq)       +   O2 (l)

III. Burning Calcium

   Procedure

(a)Using a pair of tongs hold the piece of calcium on a bunsen flame.

Observe.

Place the products in a beaker containing about 2cm3 of water. Test the solution/mixture using litmus papers

(b)Using a pair of tongs hold another piece of calcium on a Bunsen flame. Quickly lower it into a gas jar containing Oxygen gas .Observe.

Place about 2cm3 of water. Swirl.

Test the solution/mixture using litmus papers

Observations

(a)In air

Calcium burns with difficulty producing a faint red flame in air forming a white solid. Blue litmus paper remains blue. Red litmus paper turns blue

(b) In pure Oxygen 

Calcium burns with difficulty producing a less faint red flame Oxygen forming a white solid. Blue litmus paper remains blue. Red litmus paper turns blue

Explanation

(a)Calcium burns in air forming white calcium Oxide. Calcium Oxide coat/cover the calcium preventing further burning.

  Chemical equations

Calcium     +      Oxygen/air      ->      calcium Oxide

2Ca(s)    +          O2(g)             ->             2CaO(s)

Small amount of Calcium Oxide dissolves in water to form a basic/alkaline solution of Calcium hydroxide. The common name of Calcium hydroxide is lime water.

Chemical equations

Calcium Oxide     +      Water            ->      Calcium hydroxide

CaO(s)          +      H2O (l)          ->             Ca (OH) 2 (aq)

  1. Burning Iron

   Procedure

(a)Using a pair of tongs hold the piece of Iron wool/steel wire on a Bunsen flame.

Observe.

Place the products in a beaker containing about 2cm3 of water. Test the solution/mixture using litmus papers

(b)Using a pair of tongs hold another piece of Iron wool/steel wire on a Bunsen flame.

Quickly lower it into a gas jar containing Oxygen gas .Observe.

Place about 2cm3 of water. Swirl. Test the solution/mixture using litmus papers

Observations

(a)In air

Iron wool/steel wire burns producing an Orange flame in air forming a brown solid. Blue litmus paper remains blue. Red litmus paper turns faint blue

(b) In pure Oxygen 

Iron wool/steel wire burns producing a golden Orange flame in Oxygen forming a Brown solid. Blue litmus paper remains blue. Red litmus paper turns faint blue

Explanation

(a)Iron burns in air forming brown Iron (III) Oxide

Chemical equations

Iron     +      Oxygen/air      ->      Iron (III) Oxide

4Fe(s)    +          3O2 (g)             ->             2Fe2O3(s)

Very small amount of Iron (III) Oxide dissolves in water to form a weakly basic/alkaline brown solution of Iron (III) hydroxide.

Chemical equations

Calcium Oxide     +      Water            ->      Iron (III) hydroxide

Fe2O3(s)          +      3H2O (l)          ->             2Fe (OH) 3 (s)

  1. Burning Copper

   Procedure

(a)Using a pair of tongs hold the piece of copper turnings/shavings on a Bunsen flame.

Observe.

Place the products in a beaker containing about 2cm3 of water. Test the solution/mixture using litmus papers

(b)Using a pair of tongs hold another piece of Copper turnings/shavings on a Bunsen flame. Quickly lower it into a gas jar containing Oxygen gas .Observe.

Place about 2cm3 of water. Swirl. Test the solution/mixture using litmus papers

Observations

(a)In air

Copper turnings/shavings burns with difficulty producing a green flame in air forming a black solid. Blue litmus paper remains blue. Red litmus paper turns faint blue

(b) In pure Oxygen 

Copper turnings/shavings burns less difficulty producing a green flame in Oxygen forming a Brown solid. Blue litmus paper remains blue. Red litmus paper turns faint blue

Explanation

(a)Copper burns in air forming black Copper (II) Oxide

Chemical equations

Copper    +      Oxygen/air       ->      Copper (II) Oxide

2 Cu(s)    +          O2 (g)             ->             2CuO(s)

 

Very small amount of Copper (II) Oxide dissolves in water to form a weakly basic/alkaline blue solution of Copper (II) hydroxide.

Chemical equations

Copper (II) Oxide     +      Water    ->      Copper (II) hydroxide

CuO(s)                +      H2O (l)          ->             Cu (OH) 2 (s)

(i)Reaction of non metals with Oxygen/air

The following experiments show the reaction of non metals with Oxygen and air.

  1. Burning Carbon

 Procedure

(a)Using a pair of tongs hold a dry piece of charcoal on a Bunsen flame.

Observe.

Place the products in a beaker containing about 2cm3 of water. Test the solution/mixture using litmus papers

(b)Using a pair of tongs hold another piece of dry charcoal on a Bunsen flame. Quickly lower it into a gas jar containing Oxygen gas .Observe.

Place about 2cm3 of water. Swirl. Test the solution/mixture using litmus papers

Observations

          -Carbon chars then burns with a blue flame

-Colourless and odorless gas produced

-Solution formed turn blue litmus paper faint red.

Red litmus paper remains red.

Explanation

Carbon burns in air and faster in Oxygen with a blue non-sooty/non-smoky flame forming Carbon (IV) oxide gas.

Carbon burns in limited supply of air with a blue non-sooty/non-smoky flame forming Carbon (IV) oxide gas.

Carbon (IV) oxide gas dissolves in water to form weak acidic solution of Carbonic (IV) acid.

Chemical Equation

Carbon      +      Oxygen         ->        Carbon (IV) oxide

(excess air/oxygen)

C(s)       +    O2 (g)      -> CO2 (g)      (in excess air)

Carbon      +      Oxygen         ->        Carbon (II) oxide

(limited air/oxygen)

2C(s)               +    O2 (g)              ->  2CO (g)     (in limited air)

Carbon (IV) oxide     +          Water     ->        Carbonic (IV) acid

CO2 (g)   +    H2O (l)             ->               H2CO3 (aq) (very weak acid)

  1. Burning Sulphur

 Procedure

(a)Using a deflagrating spoon place sulphur powder on a Bunsen flame.

Observe.

Place the products in a beaker containing about 3cm3 of water. Test the solution/mixture using litmus papers

(b) Using a deflagrating spoon place sulphur powder on a Bunsen flame. Slowly lower it into a gas jar containing Oxygen gas. Observe.

Place about 5cm3 of water. Swirl. Test the solution/mixture using litmus papers.

Observations

          -Sulphur burns with a blue flame

-Gas produced that has pungent choking smell

-Solution formed turn blue litmus paper faint red.

Red litmus paper remains red.

Explanation

Sulphur burns in air and faster in Oxygen with a blue non-sooty/non-smoky flame forming Sulphur (IV) oxide gas.

Sulphur (IV) oxide gas dissolves in water to form weak acidic solution of Sulphuric (IV) acid.

Chemical Equation

Sulphur      +      Oxygen         ->        Sulphur (IV) oxide

S(s)       +    O2 (g)      -> SO2 (g)       (in excess air)

Sulphur (IV) oxide +           Water     ->        Sulphuric (IV) acid

SO2 (g)   +    H2O (l)   ->          H2SO3 (aq) (very weak acid)

III. Burning Phosphorus

 Procedure

(a)Remove a small piece of phosphorus from water and using a deflagrating spoon (with a lid cover) places it on a Bunsen flame.

Observe.

Carefully put the burning phosphorus to cover gas jar containing about 3cm3 of water. Test the solution/mixture using litmus papers

(b) Remove another small piece of phosphorus from water and using a deflagrating spoon (with a lid cover) place it on a Bunsen flame.

Slowly lower it into a gas jar containing Oxygen gas with about 5 cm3 of water. Observe.

Swirl. Test the solution/mixture using litmus papers.

Observations

          -Phosphorus catches fire before heating on Bunsen flame

-Dense white fumes of a gas produced that has pungent choking poisonous smell

-Solution formed turn blue litmus paper faint red.

Red litmus paper remains red.

Explanation

Phosphorus is stored in water. On exposure to air it instantaneously fumes then catch fire to burn in air and faster in Oxygen with a yellow flame producing dense white acidic fumes of Phosphorus (V) oxide gas.

Phosphoric (V) oxide gas dissolves in water to form weak acidic solution of Phosphoric (V) acid.

Chemical Equation

Phosphorus    +     Oxygen      ->        Phosphorous (V) oxide

4P(s)            +       5O2 (g)        ->      2P2O5(s)

Phosphorous (V) oxide + Water     ->        Phosphoric (V) acid

P2O5(s)      +    3H2O (l)          ->        2H3PO4 (aq) (very weak acid)

(e) Reactivity series/competition for combined Oxygen.

The reactivity series is a list of elements/metals according to their affinity for oxygen.

Some metals have higher affinity for Oxygen than others.

A metal/element with higher affinity for oxygen is placed higher/on top of the one less affinity.

The complete reactivity series of metals/elements

Most reactive

Element/Metal

Symbol
Potassium K
Sodium Na
Calcium Ca
Magnesium Mg
Aluminum Al
Carbon C
Zinc Zn
Iron Fe
Tin Sn
Lead Pb
Hydrogen H
Copper Cu
Mercury Hg
Silver Ag
Gold Au
Platinum
Least reactive

Pt

Metals compete for combined Oxygen. A metal/element with higher affinity for oxygen removes Oxygen from a metal lower in the reactivity series/less affinity for Oxygen.

When a metal/element gains/acquire Oxygen, the process is called Oxidation.

When metal/element donate/lose Oxygen, the process is called Reduction.

An element/metal/compound that undergoes Oxidation is called Reducing agent.

An element/metal/compound that undergoes Reduction is called Oxidizing agent.

A reaction in which both Oxidation and Reduction take place is called a Redox reaction.

Redox reaction between Magnesium and copper (II) Oxide

Procedure

Place about 2g of copper (II) oxide in a crucible with a lid. Place another 2g of Magnesium powder into the crucible. Mix thoroughly.

Cover the crucible with lid. Heat strongly for five minutes.

Allow the mixture to cool. Open the lid. Observe.

Observation

Colour change from black to brown. White solid power formed.

Explanation

Magnesium is higher in the reactivity series than Copper. It has therefore higher affinity for Oxygen than copper.

When a mixture of copper (II) oxide and Magnesium is heated, Magnesium reduces copper (II) oxide to brown copper metal and itself oxidized to Magnesium oxide. Magnesium is the reducing agent because it undergoes oxidation process.

Copper (II) oxide is the oxidizing agent because it undergoes redox reduction process.

The mixture should be cooled before opening the lid to prevent hot brown copper from being reoxidized back to black copper (II) oxide.

The reaction of Magnesium and Copper (II) oxide is a reaction

Chemical equation

 

 

 

 

  1. Copper (II) oxide +   Magnesium    ->   Magnesium oxide   +   Copper

(black)                                             (white ash/solid)        (brown)

CuO(s)           +        Mg(s)        ->          MgO(s)            +      Cu(s)

(Oxidizing Agent)    (Reducing Agent)

  1. Zinc (II) oxide +   Magnesium    ->   Magnesium oxide   +   Zinc

(yellow when hot)                               (white ash/solid)        (grey)

ZnO(s)          +        Mg(s)        ->          MgO(s)            +      Zn(s)

(Oxidizing agent)    (Reducing agent)

  1. Zinc (II) oxide + Carbon    ->   Carbon (IV) oxide gas   +   Zinc

(yellow when hot)                      (colourless gas)            (grey)

ZnO(s)          +        C(s)        ->          CO2 (g)            +      Zn(s)

(Oxidizing agent)    (Reducing agent)

The reactivity series is used during extraction of metals from their ore. An ore is a rock containing mineral element which can be extracted for commercial purposes. Most metallic ores occur naturally as:

(i) oxides combined with Oxygen

(ii) sulphides combined with Sulphur

(iii) carbonates combined with carbon and Oxygen.

Metallic ores that naturally occur as metallic sulphides are first roasted in air to form the corresponding oxide. Sulphur (IV) oxide gas is produced. e.g.

Copper (I) sulphide   +   Oxygen    ->   Copper (I) Oxide + Sulphur (IV) oxide

Cu2S(s)         +      O2 (g)     ->        2Cu(s)         +       SO2 (g)

Zinc (II) sulphide      +   Oxygen    ->   Zinc (II) Oxide     +   Sulphur (IV) oxide

ZnS(s)           +      O2 (g)     ->        Zn(s)           +       SO2 (g)

 

Lead (II) sulphide     +   Oxygen    ->   Lead (II) Oxide    +   Sulphur (IV) oxide

PbS(s)           +      O2 (g)     ->        Pb(s)           +       SO2 (g)

Iron (II) sulphide      +   Oxygen    ->   Iron (II) Oxide     +    Sulphur (IV) oxide

FeS(s)           +       O2 (g)     ->        Fe(s)           +       SO2 (g)

Metallic ores that naturally occur as metallic carbonates are first heated in air. They decompose/split to form the corresponding oxide and produce Carbon (IV) oxide gas. .e.g.

Copper (II) carbonate    ->    Copper (II) oxide   +   Carbon (IV) oxide

CuCO3(s)     ->   CuO(s)      +       CO2 (g)

Zinc (II) carbonate    ->    Zinc (II) oxide   +   Carbon (IV) oxide

ZnCO3(s)           ->         ZnO(s)       +          CO2 (g)

Lead (II) carbonate    ->    Lead (II) oxide   +   Carbon (IV) oxide

PbCO3(s)           ->         PbO(s)       +          CO2 (g)

Iron (II) carbonate    ->    Iron (II) oxide   +   Carbon (IV) oxide

FeCO3(s)           ->         FeO(s)       +          CO2 (g)

Metallic ores

 

WATER AND HYDROGEN

A.WATER

Pure water is a colourless, odorless, tasteless, neutral liquid. Pure water does not exist in nature but naturally in varying degree of purity. The main sources of water include rain, springs, borehole, lakes, seas and oceans:

Water is generally used for the following purposes:

(i) Drinking by animals and plants.

(ii) Washing clothes.

(iii) Bleaching and dyeing.

(iv) Generating hydroelectric power.

(v) Cooling industrial processes.

Water dissolves many substances/solutes.

It is therefore called universal solvent.

It contains about 35% dissolved Oxygen which support aquatic fauna and flora.

Water naturally exists in three phases/states solid ice, liquid water and gaseous water vapour.

The three states of water are naturally interconvertible.

The natural interconvertion of the three phases/states of water forms the water cycle.

 

 

 

 

 

Precipitation

 

Evaporation(Water in gaseous state)

 

 

 

 

 

 

 

 

 

 

 

 

 

 

Liquid water in land, lakes, seas and oceans use the solar/sun energy to evaporate/vapourize to form water vapour/gas. Solar/sun energy is also used during transpiration by plants and respiration by animals.

During evaporation, the water vapour rises up the earth’s surface. Temperatures decrease with height above the earth surface increase. Water vapour therefore cools as it rises up. At a height where it is cold enough to below 373Kelvin/100oC Water vapour looses enough energy to form tiny droplets of liquid.

The process by which a gas/water vapour changes to a liquid is called condensation/liquidification.

On further cooling, the liquid looses more energy to form ice/solid. The process by which a liquid/water changes to a ice/solid is called freezing/solidification. Minute/tiny ice/solid particles float in the atmosphere and coalesce/join together to form clouds. When the clouds become too heavy they fall  to the earth’s surface as rain/snow as the temperature increase with the fall.

 

 

 

 

 

 

 

Interconversion of the three phases/states water

Solid/Ice
 Liquid/Water
Gas/water vapour

Evaporation                                       Liquidification/

/boiling/Vapourization                  condensation

Melting                                                Freezing                                                                 liquidification

 

 

Solidification                                                                            

Pure water has:

(i) fixed/constant/sharp freezing point/melting point of 273K/0oC

(ii) fixed/constant/sharp boiling point of 373K/100oC at sea level/1 atmosphere pressure

(iii) fixed density of 1gcm-3

This is the criteria of identifying pure/purity of water.

Whether a substance is water can be determined by using the following methods:

  1. a) To test for presence of water using anhydrous copper (II) suphate (VI)

Procedure                                                                                 

Put about 2g of anhydrous copper (II) sulphate (VI) crystals into a clean test tube. Add three drops of tap water. Repeat the procedure using distilled water.

 Observation

Colour changes from white to blue

Explanation

Anhydrous copper (II) sulphate (VI) is white. On adding water, anhydrous copper (II) sulphate (VI) gains/reacts with water to form hydrated copper (II) sulphate (VI).

Hydrated copper (II) sulphate (VI) is blue.Hydrated copper (II) sulphate (VI) contains water of crystallization.

The change of white anhydrous copper (II) sulphate (VI) to bluehydrated copper (II) sulphate (VI) is a confirmatory test for the presence of water

Chemical equation

Anhydrous                                                Hydrated                                     copper (II) sulphate (VI)    + Water     ->   copper (II) sulphate (VI)

(white)                                                          (blue)

CuSO4(s)                        + 5H2O (l) ->CuSO4.5H2O(s)

  1. b) To test for presence of water using anhydrous cobalt (II) chloride

Procedure                                                                                           

Put about 5cm3 of water into a clean test tube.

Dip a dry anhydrouscobalt (II) chloride paper into the test tube.

Repeat the procedure using distilled water.

Observation

Colour changes from blue to pink

Explanation

Anhydrous cobalt (II) chloride is blue. On adding water, anhydrous cobalt (II) chloride gains/reacts with water to form hydrated cobalt (II) chloride.

Hydrated cobalt (II) chloride is pink.

Hydrated cobalt (II) chloride contains water of crystallization.

The change of blue anhydrous cobalt (II) chloride to pinkhydrated cobalt (II) chloride is a confirmatory test for the presence of water    Chemical equation.

Anhydrous                                                Hydrated                                     cobalt (II) chloride    + Water     ->   cobalt (II) chloride

(Blue)                                                           (pink)

CoCl2 (s)                         + 5H2O (l) ->CoCl2.5H2O(s)

Burning a candle in air

Most organic substances/fuels burn in air to produce water. Carbon (IV) oxide gas is also produced if the air is sufficient/excess.

Procedure

Put about 2g of anhydrous copper (II) sulphate (VI) crystals in a boiling tube.

Put about 5cm3 of lime water in a boiling tube.

Light a small candle stick. Place it below an inverted thistle/filter funnel

Collect the products of the burning candle by setting the apparatus as below

Set up of apparatus

 

Observation

The sanction pump pulls the products of burning into the inverted funnel. Colour of anhydrous copper (II) sulphate (VI) changes from white to blue. A white precipitate is formed in the lime water/calcium hydroxide.

Explanation

When a candle burn it forms a water and carbon (IV) oxide.

Water turns anhydrous copper (II) sulphate (VI) changes from white to blue.

Carbon (IV) oxide gasforms white precipitate when bubbled in lime water/calcium hydroxide.

Since:

(i) hydrogen in the wax burn to form water

Hydrogen   +        Oxygen      ->      Water

(from candle)       (from the air)

2H2 (g)      +        O2 (g)                    ->      2H2O (g/l)

(ii) carbon in the wax burn to form carbon (IV) oxide

Hydrogen   +        Oxygen      ->      Water

(from candle)        (from the air)

C(s)             +           O2(g)        ->      CO2 (g)

The candle before burning therefore contained only Carbon and Hydrogenonly. A compound made up of hydrogen and carbon is called Hydrocarbon.

A candle is a hydrocarbon.

Other hydrocarbons include: Petrol, diesel, Kerosene, and Laboratory gas. Hydrocarbons burn in air to form water and carbon (IV) oxide gas.

Hydrocarbons    +   Oxygen   ->   Water   +   Oxygen

 

Water pollution

Water pollution takes place when undesirable substances are added into the water. Sources of water pollution include:

(i)Industrial chemicals being disposed into water bodies like rivers, lakes and oceans.

(ii)Discharging untreated /raw sewage into water bodies.

(iii)Leaching of insecticides/herbicides form agricultural activities into water bodies.

(iv)Discharging non-biodegradable detergents after domestic and industrial use into water bodies.

(v)Petroleum oil spilling by ships and oil refineries

(vi)Toxic/poisonous gases from industries dissolving in rain.

(vii) Acidic gases from industries dissolving in rain to form “acid rain”

(viii)Discharging hot water into water bodies. This reduces the quantity of dissolved Oxygen in the water killing the aquatic fauna and flora.

Water pollution can be reduced by:

(i) Reducing the use of agricultural fertilizers and chemicals in agricultural activities.

(ii) Use of biological control method instead of insecticides and herbicides

(iii) Using biodegradable detergents

REACTION OF WATER WITH METALS.

Some metals react with water while others do not. The reaction of metals with water depends on the reactivity series. The higher the metal in the reactivity series the more reactive the metal with water .The following experiments shows the reaction of metals with cold water and water vapour/steam.

(a)Reaction of sodium/ potassium with cold water:

Procedure

Put about 500cm3 of water in a beaker. Add three drops of phenolphthalein indicator/litmus solution/universal indicator solution/methyl orange indicator into the water.

Cut a very small piece of sodium .Using a pair of forceps put the metal into the water.

Observation

Sodium melts to a silvery ball that floats and darts on the surface decreasing in size. Effervescence/fizzing/ bubbles of colourless gas produced.

Colour of phenolphthalein turns pink

Colour of litmus solution turns blue

Colour of methyl orange solution turns Orange

Colour of universal indicator solution turns blue

Explanation

Sodium is less dense than water. Sodium floats on water and vigorously reacts to form an alkaline solution of sodium hydroxide and producing hydrogen gas. Sodium is thus stored in paraffin to prevent contact with water.

Chemical equation

Sodium       +        Water                    ->     Sodium hydroxide   +   Hydrogen gas

2Na(s)         +        2H2O (l)      ->      2NaOH (aq)                       + H2(g)

To collect hydrogen gas, Sodium metal is forced to sink to the bottom of the trough/beaker by wrapping it in wire gauze/mesh.

 

Potassium is more reactive than Sodium. On contact with water it explodes/burst into flames. An alkaline solution of potassium hydroxide is formed and hydrogen gas

 

Chemical equation

Potassium   +        Water                    ->    Potassium hydroxide   +   Hydrogen gas

2K(s)     +        2H2O (l)      ->      2KOH (aq)     +  H2(g)

Caution: Reaction of Potassium with water is very risky to try in a school laboratory.

(b)Reaction of Lithium/ Calcium with cold water:

Procedure

Put about 200cm3 of water in a beaker. Add three drops of phenolphthalein indicator/litmus solution/universal indicator solution/methyl orange indicator into the water.

Cut a small piece of Lithium .Using a pair of forceps put the metal into the water.

Repeat with a piece Calcium metal

Observation

Lithium sinks to the bottom of the water. Rapid effervescence/fizzing/ bubbles of colourless gas produced.

Colour of phenolphthalein turns pink

Colour of litmus solution turns blue

Colour of methyl orange solution turns Orange

Colour of universal indicator solution turns blue

Explanation

Lithium and calcium are denser than water. Both sink in water and vigorously react to form an alkaline solution of Lithium hydroxide / calcium hydroxide and producing hydrogen gas. Lithium is more reactive than calcium. It is also stored in paraffin like Sodium to prevent contact with water.

Chemical equation

Lithium       +        Water          ->     Lithium hydroxide   +   Hydrogen gas

2Li(s)          +        2H2O (l)      ->      2LiOH (aq)   +  H2 (g)

Calcium      +        Water          ->     Calcium hydroxide   +   Hydrogen gas

Ca(s)           +        2H2O (l)      ->      Ca (OH) 2(aq)           +   H2 (g)

 

 

(c) Reaction of Magnesium/Zinc/ Iron with Steam/water vapour:

Procedure method1

Place some wet sand or cotton/glass wool soaked in water at the bottom of an ignition/hard glass boiling tube.

Polish magnesium ribbon using sand paper.

Coil it at the centre of the ignition/hard glass boiling tube.

Set up the apparatus as below.

Heat the wet sand or cotton/glass wool soaked in water gently to:

(i) Drive away air in the ignition/hard glass boiling tube.

(ii) Generate steam

Heat the coiled ribbon strongly using another burner. Repeat the experiment using Zinc powder and fresh Iron filings.

Set up of apparatus

Observations

(i)With Magnesium ribbon: 

The Magnesium glows with a bright flame (and continues to burn even if heating is stopped)

White solid /ash formed

White solid /ash formed dissolve in water to form a colourless solution

Colourless gas produced/collected that extinguish burning splint with “pop sound”

 (ii) With Zinc powder: 

The Zinc powder turns red hot on strong heating

Yellow solid formed that turn white on cooling

White solid formed on cooling does not dissolve in water.

(iii)With Iron fillings: 

The Iron fillings turn red hot on strong heating

Dark blue solid formed

Dark blue solid formed does not dissolve in water.

 

Procedure method 2

Put some water in a round bottomed flask

Polish magnesium ribbon using sand paper.

Coil it at the centre of a hard glass tube

Set up the apparatus as below.

Heat water strongly to boil so as to:

(i) drive away air in the glass tube.

(ii) generate steam

Heat the coiled ribbon strongly using another burner. Repeat the experiment using Zinc powder and fresh Iron filings.

Observations

(i)With Magnesium ribbon: 

The Magnesium glows with a bright flame (and continues to burn even if heating is stopped)

White solid /ash formed

White solid /ash formed dissolve in water to form a colourless solution

Colourless gas produced/collected that extinguish burning splint with “pop sound”

(ii) With Zinc powder: 

The Zinc powder turns red hot on strong heating

Yellow solid formed that turn white on cooling

White solid formed on cooling does not dissolve in water.

(iii)With Iron fillings: 

The Iron fillings turn red hot on strong heating

Dark blue solid formed

Dark blue solid formed does not dissolve in water.

Explanations

(a)Hot magnesium burn vigorously in steam. The reaction is highly exothermic generating enough heat/energy to proceed without further heating.

White Magnesium oxide solid/ash is left as residue.

Hydrogen gas is produced .It extinguishes a burning splint with a “pop sound”.

Chemical Equation

Magnesium   + Steam    ->   Magnesium oxide   +   Hydrogen

Mg(s)           +  H2O(g)   ->         MgO(s)            +       H2(g)

 

Magnesium oxide reacts /dissolves in water to form an alkaline solution of Magnesium oxide

Chemical Equation

Magnesium oxide    + Water ->   Magnesium hydroxide

MgO(s)          +  H2O(l)  ->         Mg(OH) 2 (aq)

(b)Hot Zinc react vigorously in steam forming yellow Zinc oxide solid/ash as residue which cools to white.

Hydrogen gas is produced .It extinguishes a burning splint with a “pop sound”.

Chemical Equation

Zinc    + Steam  ->      Zinc oxide    +    Hydrogen

Zn(s)   +  H2O(g)        ->         ZnO(s)       +       H2(g)

Zinc oxide does not dissolve in water.

(c)Hot Iron reacts with steam forming dark blue tri iron tetra oxide solid/ash as residue.

Hydrogen gas is produced .It extinguishes a burning splint with a “pop sound”.

Chemical Equation

Iron              +  Steam    ->      Tri iron tetra oxide  +    Hydrogen

2Fe(s)          +  4H2O(g  ->         Fe2O4(s)       +    4H2(g)

Tri iron tetra oxide does not dissolve in water.

(d)Aluminum reacts with steam forming an insoluble coat/cover of impervious layer of aluminum oxide on the surface preventing further reaction.

(e) Lead, Copper, Mercury, Silver, Gold and Platinum do not react with either water or steam.

 

HYDROGEN

Occurrence

Hydrogen does not occur free in nature. It occurs as Water and in Petroleum.

School laboratory Preparation

Procedure

Put Zinc granules in a round/flat/conical flask. Add dilute sulphuric (VI) /Hydrochloric acid.

Add about 3cm3 of copper (II) sulphate (VI) solution.

Collect the gas produced over water as in the set up below.

Discard the first gas jar. Collect several gas jars.

 

Observation/Explanation

Zinc reacts with dilute sulphuric (VI)/hydrochloric acid to form a salt and produce hydrogen gas.

When the acid comes into contact with the metal, there is rapid effervescence/ bubbles /fizzing are produced and a colourless gas is produced that is collected:

(i) Over water because it is insoluble in water

(ii) Through downward displacement of air/upward delivery because it is less dense than air.

The first gas jar is impure. It contains air that was present in the apparatus.

Copper (II) sulphate (VI) solution act as catalyst.

Chemical equation

(a) Zinc     +    Hydrochloric acid     ->     Zinc chloride        +    Hydrogen

Zn(s)      +   2HCl (aq)                      ->             ZnCl2 (aq)         +       H2 (g)

Ionic equation

Zn (s)    +   2H+ (aq)      ->       Zn2+ (aq)         +        H2 (g)

Zinc     +    Sulphuric (VI) acid     ->     Zinc Sulphate (VI)    +    Hydrogen

Zn(s)    +      H2SO4 (aq)           ->       ZnSO4 (aq)           +       H2 (g)

Ionic equation

Zn (s)    +   2H+ (aq)      ->       Zn2+ (aq)         +        H2 (g)

(b) Chemical equation

Magnesium   +    Hydrochloric acid -> Magnesium chloride     +    Hydrogen

Mg(s)      +   2HCl (aq)                       ->             MgCl2 (aq)        +       H2(g)

Ionic equation

Mg (s)    +   2H+ (aq)     ->       Mg2+ (aq)        +        H2 (g)

Magnesium     + Sulphuric (VI) acid -> Magnesium Sulphate(VI)  +    Hydrogen

Mg(s)    +      H2SO4 (aq)             ->       MgSO4 (aq)          +       H2(g)

Ionic equation

Mg (s)    +   2H+ (aq)      ->       Mg2+ (aq)        +        H2 (g)

(c) Chemical equation

Iron   +    Hydrochloric acid -> Iron (II) chloride     +    Hydrogen

Fe(s)      +   2HCl (aq)     ->         FeCl2 (aq)      +       H2 (g)

Ionic equation

Fe (s)    +   2H+ (aq)      ->       Fe2+ (aq)         +        H2 (g)

Iron     + Sulphuric (VI) acid -> Iron (II) Sulphate (VI) +    Hydrogen

Fe(s)    +      H2SO4 (aq)        ->       FeSO4 (aq)        +     H2 (g)

Ionic equation

Fe (s)    +   2H+ (aq)       ->       Fe2+ (aq)         +        H2 (g)

Note

  1. Hydrogen cannot be prepared from reaction of:

(i)Nitric (V) acid and a metal. Nitric (V) acid is a strong oxidizing agent. It oxidizes hydrogen gas to water.

(ii) Dilute sulphuric (VI) acid with calcium/Barium/Lead because Calcium sulphate (VI), Barium sulphate (VI) and Lead (II) sulphate (VI) salts formed are insoluble. Once formed, they cover/coat the unreacted calcium/Barium/Lead stopping further reaction and producing very small amount/volume of hydrogen gas.

(iii) Dilute acid with sodium/potassium. The reaction is explosive.

Properties of Hydrogen gas

(a)Physical properties

  1. Hydrogen is a neutral, colourlessand odorless gas. When mixed with air it has a characteristic pungent choking smell
  2. It is insoluble in water thus can be collected over water.
  3. It is the lightest known gas. It can be transferred by inverting one gas jar over another.

(b)Chemical properties

(i)Burning

  1. Hydrogen does not support burning/combustion. When a burning splint is inserted into a gas jar containing Hydrogen, the flame is extinguished /put off.
  2. Pure dry hydrogen burn with a blue quiet flame to form water. When a stream of pure dry hydrogen is ignited, it catches fire and continues to burn with a blue flame.

III. Impure (air mixed with) hydrogen burns with an explosion. Small amount/ volume of air mixed with hydrogen in a test tube produce a small explosion as a “pop” sound. This is the confirmatory test for the presence of Hydrogen gas. A gas that burns with a “pop” sound is confirmed to be Hydrogen.

(ii)Redox in terms of Hydrogen transfer

Redox can also be defined in terms of Hydrogen transfer.

(i)Oxidation is removal of Hydrogen

(ii)Reduction is addition of Hydrogen

(iii)Redox is simultaneous addition and removal of Hydrogen

Example

When a stream of dry hydrogen gas is passed through black copper (II) oxide, hydrogen gas gains the oxygen from copper (II) oxide.

Black copper (II) oxide is reduced to brown copper metal.

Black copper (II) oxide thus the Oxidizing agent.

Hydrogen gas is oxidized to Water. Hydrogen is the Reducing agent.

Set up of apparatus

(a)Chemical equation

(i) In glass tube

Copper (II) Oxide   +    Hydrogen        ->      Copper     +    Hydrogen gas

(oxidizing agent)   (reducing agent)

(black)                                                 (brown)

CuO (s)          +          H2(g)          ->      Cu(s)        +        H2O(l)

(ii) when excess Hydrogen is burning.

Oxygen    +         Hydrogen      ->           Water

O2 (g)        +          2H2 (g)          ->              2H2O (l)

(b)Chemical equation

  (i) In glass tube

Lead (II) Oxide   +    Hydrogen        ->      Lead     +    Hydrogen gas

(oxidizing agent)   (reducing agent)

(brown when hot/                                     (grey)

yellow when cool)

PbO (s)          +          H2 (g)          ->      Pb(s)        +        H2O (l)

   (ii) when excess Hydrogen is burning.

Oxygen       +         Hydrogen            ->            Water

O2 (g)          +          2H2 (g)                ->              2H2O(l)

(c)Chemical equation

(i) In glass tube

Iron (III) Oxide   +    Hydrogen        ->      Iron     +    Hydrogen gas

(oxidizing agent)   (reducing agent)

(Dark grey)                                                          (grey)

Fe2O3 (s)          +          3H2 (g)         ->      Fe(s)        +        3H2O (l)

(ii) when excess Hydrogen is burning.

Oxygen       +         Hydrogen            ->            Water

O2 (g)          +          2H2 (g)                ->        2H2O (l)

(iii) Water as an Oxide as Hydrogen

Burning is a reaction of an element with Oxygen. The substance formed when an element burn in air is the oxide of the element. When hydrogen burns, it reacts/ combines with Oxygen to form the oxide of Hydrogen. Theoxide of Hydrogen is called water. Hydrogen is first dried because a mixture of Hydrogen and air explode. The gas is then ignited .The products condense on a cold surface/flask containing a freezing mixture. A freezing mixture is a mixture of water and ice.

 

The condensed products are collected in a receiver as a colourless liquid.

Tests

(a) When about 1g of white anhydrous copper (II) sulphate (VI) is added to a sample of the liquid, it turns to blue. This confirms the liquid formed is water.

(b) When blue anhydrous cobalt (II) chloride paper is dipped in a sample of the liquid, it turns to pink. This confirms the liquid formed is water.

(c)When the liquid is heated to boil, its boiling point is 100oC at sea level/one atmosphere pressure. This confirms the liquid is pure water.

Uses of Hydrogen gas

  1. Hydrogenation/Hardening of unsaturated vegetable oils to saturated fats/margarine.

When Hydrogen is passed through unsaturated compounds in presence of Nickel catalyst and about 150oC, they become saturated. Most vegetable oil is unsaturated liquids at room temperature. They become saturated and hard through hydrogenation.

  1. In weather forecast balloons.

Hydrogen is the lightest known gas. Meteorological data is collected for analysis by sending hydrogen filled weather balloons to the atmosphere. The data collected is then used to forecast weather conditions.

  1. In the Haber process for the manufacture of Ammonia

Hydrogen is mixed with Nitrogen in presence of Iron catalyst to form Ammonia gas. Ammonia gas is a very important raw material for manufacture of agricultural fertilizers.

  1. In the manufacture of Hydrochloric acid.

Limited volume/amount of Hydrogen is burnt in excess chlorine gas to form Hydrogen chloride gas. Hydrogen chloride gas is dissolved in water to form Hydrochloric acid. Hydrochloric acid is used in pickling/washing metal surfaces.

  1. As rocket fuel.

Fixed proportions of Hydrogen and Oxygen when ignited explode violently producing a lot of energy/heat. This energy is used to power/propel a rocket to space.

  1. In oxy-hydrogen flame for welding.

A cylinder containing Hydrogen when ignited in pure Oxygen from a second cylinder produces a flame that is very hot. It is used to cut metals and welding.

 

Sample revision questions

  1. A colourless liquid was added anhydrous copper (II) sulphate (VI) which turned blue.

(a)Why is it wrong to conclude the liquid was pure water?

Anhydrous copper (II) sulphate (VI) test for presence of water. Purity of water is determined from freezing/melting/boiling point.

(b)Write an equation for the reaction that takes place with anhydrous copper (II) sulphate (VI)

Anhydrous copper (II) sulphate (VI) + Water    ->   hydrated copper (II) sulphate (VI)

CuSO4(s)                     + 5H2O (l) ->            CuSO4.5H2O(s)

(c)(i)Which other compound would achieve the same results asanhydrous copper (II) sulphate (VI)  

Anhydrous cobalt (II) chloride/CoCl2.6H2O

     (ii)Write the equation for the reaction

Anhydrous cobalt (II) chloride + Water       ->   hydrated cobalt (II) chloride

CoCl2 (s)                +  6H2O(l)   ->            CoCl2.6H2O (s)

(d)Complete the equation

(i) Sulphur (VI) oxide                      + Water      ->   Sulphuric (VI) acid

(ii) Sulphur (IV) oxide                     + Water      ->   Sulphuric (IV) acid

(iii) Carbon (IV) oxide                     + Water       ->   Carbonic (IV) acid

(iv) Nitrogen (IV) oxide                    + Water      ->   Nitric (V) acid

(v) Phosphorus (V) oxide      + Water       ->   Phosphoric (V) acid

(vi) Sodium oxide                   + Water      ->   Sodium hydroxide

(vi) Sodium peroxide                       + Water       ->   Sodium hydroxide

  1. Metal B reacts with steam. Metal C reacts with cold water. Metal A does not react with water.

(a)Arrange the metals as they should appear in the reactivity series.

                                        B

C

A

(b)A product residue in D which was brown when hot but turned yellow on cooling during the reaction of metal B was formed. Gas E was also evolved. Identify

          (i)Metal B            Lead/Pb

(ii)Residue D       Lead (II) oxide/PbO

(iii)Gas E             Hydrogen/H2

(c)A portion of product residue in D was added dilute nitric (V) acid. Another portion of product residue in D was added dilute sulphuric (VI) acid. State and explain the observations made.

When added dilute nitric (V) acid, D dissolves to form a colourless solution.

Lead (II) Oxide + dilute nitric (V) acid -> Lead (II) nitrate (V) + Water

PbO (s) +   2HNO3 (aq) ->   Pb (NO3)2 (aq)   +   H2O (l)

When added dilute sulphuric (VI) acid, D does not dissolve. A white suspension/precipitate was formed. Lead(II)Oxide reacts with sulphuric(VI)acid to form insoluble Lead(II)sulphate(VI) that cover/coat unreacted Lead(II)Oxide, stopping further reaction.

Lead (II) Oxide + dilute sulphuric (VI) acid -> Lead (II) sulphate (VI) + Water

PbO (s)    +   H2SO4 (aq)            ->         PbSO4 (s)             +   H2O (l)

  1. (a) Hydrogen can reduce copper (II) Oxide but not alluminium oxide. Explain

(b) When water reacts with potassium metal the hydrogen produced ignites explosively on the surface of water.

(i) What causes this ignition?                                                                                            (ii) Write an equation to show how this ignition occurs

  1. In an experiment, dry hydrogen gas was passed over hot copper (II) oxide in a combustion tube as shown in the diagram below:

 

 

 

 

 

 

 

 

 

 

 

(a) Complete the diagram to show how the other product, substance R could be collected in the laboratory.

(b) Describe how copper could be obtained from the mixture containing copper (II) oxide

  1. The setup below was used to investigate the reaction between metals and water.

 

 

 

 

 

(a) Identify solid X and state its purpose

Solid X    .…………………………………………………………………..

Purpose        …………………………………………………………………..

(b) Write a chemical equation for the reaction that produces the flame.                                                  4. Gas P was passed over heated magnesium ribbon and hydrogen gas was collected as shown in the diagram below:

 
 

 

 

 

 

 

(i) Name gas P          …………………………………………………………………………………………………

(ii) Write an equation of the reaction that takes place in the combustion tube            (iii) State one precaution necessary at the end of this experiment

  1. When hydrogen is burnt and the product cooled, the following results are obtained as shown in the diagram below:

 

 

 

 

 

 

 

 

 

(a) Write the equation for the formation of liquid Y

(b) Give a chemical test for liquid Y

Jane set-up the experiment as shown below to collect a gas. The wet sand was heated before

heating Zinc granules

 

 

 

 

 

 

 Wet sand

 

 

(a) Complete the diagram for the laboratory preparation of the gas                              (b) Why was it necessary to heat wet sand before heating Zinc granules?

 

 

 

 

 

 

 

N

 

 

 

(a) Between N and M which part should be heated first? Explain

(b) Write a chemical equation for the reaction occurring in the combustion tube.

  1. The set-up below was used to investigate electrolysis of a certain molten compound;-

 

 

 

 

 

 

(a) Complete the circuit by drawing the cell in the gap left in the diagram

(b) Write half-cell equation to show what happens at the cathode

(c) Using an arrow show the direction of electron flow in the diagram above

  1. Hydrogen can be prepared by reacting zinc with dilute hydrochloric acid.
  2. a) Write an equation for the reaction.
  3. b) Name an appropriate drying agent for hydrogen gas.
  4. c) Explain why copper metal cannot be used to prepare hydrogen gas.
  5. d) Hydrogen burns in oxygen to form an oxide.

(i) Write an equation for the reaction.

(ii) State two precautions that must be taken before the combustion begins and at the end of   the combustion.

  1. e) Give two uses of hydrogen gas.
  2. f) When zinc is heated to redness in a current of steam, hydrogen gas is obtained. Write an equation for the reaction.
  3. g) Element Q reacts with dilute acids but not with cold water. Element R does not react with dilute acids. Elements S displaces element P from its oxide. P reacts with cold water. Arrange the four elements in order of their reactivity, starting with the most reactive.
  4. h) Explain how hydrogen is used in the manufacture of margarine.

 

 

  1. a) The set-up below is used to investigate the properties of hydrogen.

 

 

 

 

 

  1. On the diagram, indicate what should be done for the reaction to occur
  2. Hydrogen gas is allowed to pass through the tube for some time before it is lit. Explain

iii) Write an equation for the reaction that occurs in the combustion tube                        iv) When the reaction is complete, hydrogen gas is passed through the apparatus until they cool down.   Explain

  1. v) What property of hydrogen is being investigated?
  2. vi) What observation confirms the property stated in (v) above?

vii) Why is zinc oxide not used to investigate this property of hydrogen gas?

  1. The set up below was used to collect gas K, produced by the reaction between water and

calcium metal.

 

 

 

 

(a) Name gas K          ……………………………………………………………..

(b) At the end of the experiment, the solution in the beaker was found to be a weak base. Explain  why the solution is a weak base

 

 

 

 

 

 

 

 

 

 

 

ACIDS, BASES AND INDICATORS 

 

INTRODUCTION TO ACIDS, BASES AND INDICATORS

  1. In a school laboratory:

(i)An acid may be defined as a substance that turns litmus red.

(ii)A base may be defined as a substance that turns litmus blue.

Litmus is lichen found mainly in West Africa. It changes its colour depending on whether the solution it is in, is basic/alkaline or acidic. It is thus able to identify/show whether another substance is an acid, base or neutral.

(iii)An indicator is a substance that shows whether another substance is a base/alkaline,acid or neutral.

  1. Common naturally occurring acids include:
Name of acid Occurrence
1.Citric acid Found in ripe citrus fruits like passion fruit/oranges/lemon
2.Tartaric acid Found in grapes/baking powder/health salts
3.Lactic acid Found in sour milk
4.Ethanoic acid Found in vinegar
5.Methanoic  acid Present in ants, bees stings
6.Carbonic acid Used in preservation of fizzy drinks like coke, Lemonade, Fanta
7.Butanoic acid Present in cheese
8.Tannic acid Present in tea
  1. Most commonly used acids found in a school laboratory are not naturally occurring. They are manufactured. They are called mineral acids.

Common mineral acids include:

Name of mineral acid Common use
Hydrochloric acid (HCl) Used to clean/pickling surface of metals

Is found in the stomach of mammals/human beings

Sulphuric(VI) acid (H2SO4) Used as acid in car battery, making battery, making fertilizers
Nitric(V)acid (HNO3) Used in making fertilizers and explosives
  1. Mineral acids are manufactured to very high concentration. They are corrosive (causes painful wounds on contact with the skin) and attack/reacts with garments/clothes/metals.

In a school laboratory, they are mainly used when added a lot of water. This is called diluting. Diluting ensures the concentration of the acid is safely low.

 

  1. Bases are opposite of acids. Most bases do not dissolve in water.

Bases which dissolve in water are called alkalis.

Common alkalis include:

Name of alkali Common uses
Sodium hydroxide (NaOH) Making soaps and detergents
Potassium hydroxide(KOH) Making soaps and detergents
Ammonia solution(NH4OH) Making fertilizers, softening hard water

Common bases (which are not alkali) include:

Name of base Common name
Magnesium oxide/hydroxide Anti acid to treat indigestion
Calcium oxide Making cement and neutralizing soil acidity
  1. Indicators are useful in identifying substances which look-alike.

An acid-base indicator is a substance used to identify whether another substance is alkaline or acidic.

An acid-base indicator works by changing to different colors in neutral, acidic and alkaline solutions/dissolved in water.

Experiment: To prepare simple acid-base indicator

Procedure

(a)Place some flowers petals in a mortar. Crush them using a pestle. Add a little sand to assist in crushing.

Add about 5cm3 of propanone/ethanol and carefully continue grinding.

Add more 5cm3 of propanone/ethanol and continue until there is enough extract in the mortar.

Filter the extract into a clean 100cm3 beaker.

(b)Place 5cm3 of filtered wood ash, soap solution, ammonia solution, sodium hydroxide, hydrochloric acid, distilled water, sulphuric (VI) acid, sour milk, sodium chloride, toothpaste and calcium hydroxide into separate test tubes.

(c)Put about three drops of the extract in (a)to each test tube in (b). Record the observations made in each case.

Sample observations

Solution mixture Colour on adding indicator extract Nature of solution
wood ash green Base/alkaline
soap solution green Basic/alkaline
ammonia solution green Basic/alkaline
sodium hydroxide green Basic/alkaline
hydrochloric acid Red Acidic
distilled water orange Neutral
sulphuric(VI)acid Red Acidic
sour milk green Basic/alkaline
sodium chloride orange Neutral
Toothpaste green Basic/alkaline
calcium hydroxide green Basic/alkaline
Lemon juice Red Acidic

The plant extract is able to differentiate between solutions by their nature. It is changing to a similar colour for similar solutions.

(i)Since lemon juice is a known acid, then sulphuric (VI) and hydrochloric acids are similar in nature with lemon juice because the indicator shows similar colors. They are acidic in nature.

(ii)Since sodium hydroxide is a known base/alkali, then the green colour of indicator shows an alkaline/basic solution.

(iii) Since pure water is neutral, then the orange colour of indicator shows neutral solutions.

  1. In a school laboratory, commercial indicators are used. A commercial indicator is cheap, readily available and easy to store. Common indicators include: Litmus, phenolphthalein, methyl orange, screened methyl orange, bromothymol blue.

Experiment:

Using commercial indicators to determine acidic, basic/alkaline and neutral solutions     

Procedure

Place 5cm3 of the solutions in the table below. Add three drops of litmus solution to each solution.

Repeat with phenolphthalein indicator, methyl orange, screened methyl orange and bromothymol blue.

Sample results

Substance/

Solution

Indicator used

 

Litmus Phenolphthalein Methyl orange Screened methyl orange Bromothymol

 blue

wood ash Blue Pink Yellow Orange Blue
soap solution Blue Pink Yellow Orange Blue
ammonia solution Blue Pink Yellow Orange Blue
sodium hydroxide Blue Pink Yellow Orange Blue
hydrochloric acid Red Colourless Red Purple Orange
distilled water Colourless Colourless Red Orange Orange
sulphuric(VI)acid Red Colourless Red Purple Orange
sour milk Blue Pink Yellow Orange Blue
sodium chloride Colourless Colourless Red Orange Orange
Toothpaste Blue Pink Yellow Orange Blue
calcium hydroxide Blue Pink Yellow Orange Blue
Lemon juice Red Colourless Red Purple Orange

 

From the table above, then the colour of indicators in different solution can be summarized.

Indicator Colour of indicator in
Acid Base/alkali Neutral
Litmus paper/solution Red Blue Colourless
Methyl orange Red Yellow Red
Screened methyl orange Purple Orange Orange
Phenolphthalein Colourless Purple Colourless
Bromothymol blue Orange Blue Orange

The universal indicator

The universal indicator is a mixture of other indicator dyes. The indicator uses the pH scale. The pH scale shows the strength of bases and acids. The pH scale ranges from 1-14.These numbers are called pH values:

(i) pH values 1, 2, 3 shows a substance is  strongly acid

(ii) pH values 4, 5, 6 shows a substance is a weakly acid

(iii) pH value 7 shows a substance is a neutral

(iv) pH values 8, 9, 10, 11 shows a substance is a weak base/alkali.

(v) pH values 12, 13, 14 shows a substance is a strong base/alkali

The pH values are determined from a pH chart. The pH chart is a multicolored paper with each colour corresponding to a pH value.i.e

(i) red correspond to pH 1, 2, 3 showing strongly acidic solutions.

(ii)Orange/ yellow correspond to pH 4, 5, 6 showing weakly acidic solutions.

(iii)Green correspond to pH 7 showing neutral solutions.

(iv)Blue correspond to pH 8, 9, 10, 11 showing weakly alkaline solutions.

(v)Purple/dark blue correspond to pH 12,13,14 showing strong alkalis.

The universal indicator is available as:

(i) Universal indicator paper/pH paper

(ii) Universal indicator solution.

When determining the pH of a unknown solution using

(i) pH paper then the pH paper is dipped into the unknown solution. It changes/turn to a certain colour. The new colour is marched/compared to its corresponding one on the pH chart to get the pH value.

(ii) universal indicator solution then about 3 drops of the universal indicator solution is added into about 5cm3 of the unknown solution in a test tube. It changes/turn to a certain colour. The new colour is marched/compared to its corresponding one on the pH chart to get the pH value.

Experiment: To determine the pH value of some solutions    

(a)Place 5cm3 of filtered wood ash, soap solution, ammonia solution, sodium hydroxide, hydrochloric acid, distilled water, sulphuric (VI) acid, sour milk, sodium chloride, toothpaste and calcium hydroxide into separate test tubes.

(b)Put about three drops of universal indicator solution or dip a portion of a piece of pH paper into each. Record the observations made in each case.

(c)Compare the colour in each solution with the colors on the pH chart provided. Determine the pH value of each solution.

Sample observations

Solution mixture Colour on the pH paper/adding universal indicator pH value Nature of solution
wood ash Blue 8 Weakly alkaline
soap solution Blue 8 Weakly alkaline
ammonia solution green 8 Weakly alkaline
sodium hydroxide Purple 14 Strongly alkaline
hydrochloric acid red 1 Strongly acidic
distilled water green 7 Neutral
sulphuric(VI)acid red 1 Strongly acidic
sour milk blue 9 Weakly alkaline
sodium chloride green 7 Neutral
toothpaste Blue 10 Weakly alkaline
calcium hydroxide Blue 11 Weakly alkaline
Lemon juice Orange 5 Weakly acidic

Note

  1. All the mineral acids Hydrochloric, sulphuric (VI) and nitric (V) acids are strong acids
  2. Two alkalis/soluble bases, sodium hydroxide and potassium hydroxide are strong bases/alkali. Ammonia solution is a weak base/alkali. All other bases are weakly alkaline.
  3. Pure/deionized water is a neutral solution.
  4. Common salt/sodium chloride is a neutral salt.
  5. When an acid and an alkali/base are mixed, the final product has pH 7 and is neutral.

Properties of acids

(a)Physical properties of acids

  1. Acids have a characteristic sour taste
  2. Most acids are colourless liquids
  3. Mineral acids are odorless. Organic acids have characteristic smell
  4. All acids have pH less than 7
  5. All acids turn blue litmus paper red, methyl orange red and phenolphthalein colourless.
  6. All acids dissolve in water to form an acidic solution. Most do not dissolve in organic solvents like propanone, kerosene, tetrachloromethane, petrol.

(b)Chemical properties of acids

  1. Reaction with metals

All acids react with reactive metals to form a salt and produce /evolve hydrogen gas.

Metal          +        Acid  ->     Salt    +        Hydrogen gas

Experiment: reaction of metals with mineral acids.

(a)Place 5cm3 of dilute hydrochloric acid in a small test tube. Add 1cm length of polished magnesium ribbon. Stopper the test tube using a thump. Light a wooden splint. Place the burning splint on top of the stoppered test tube. Release the thump stopper. Record the observations made.

(b)Repeat the procedure in (a) above using Zinc granules, iron filings, copper turnings, aluminum foil in place of Magnesium ribbon

(c)Repeat the procedure in (a) then (b) using dilute sulphuric (VI) acid in place of dilute hydrochloric acid.

Sample observations

(i) effervescence/bubbles produced/fizzing in all cases except when using copper

(ii) Colourless gas produced in all cases except when using copper

(iii) Gas produced extinguishes a burning wooden splint with an explosion/pop sound.

Explanation

Some metals react with dilute acids, while others do not. Metals which react with acids produce bubbles of hydrogen gas. Hydrogen gas is a colourless gas that extinguishes a burning splint with a pop sound. This shows acids contain hydrogen gas.

This hydrogen is displaced/removed from the acids by some metals like Magnesium, Zinc, aluminium, iron and sodium.

Some other metals like copper, silver, gold; platinum and mercury are not reactive enough to displace/remove the hydrogen from dilute acids.

Chemical equations

  1. Magnesium + Hydrochloric acid -> Magnesium chloride + Hydrogen

Mg(s)        +       2HCl (aq)             ->       MgCl2 (aq)           +      H2(g)

 

  1. Zinc + Hydrochloric acid -> Zinc chloride + Hydrogen

Zn(s)       +       2HCl (aq)       ->      ZnCl2 (aq)           +      H2(g)

  1. Iron + Hydrochloric acid -> Iron (II) chloride + Hydrogen

Fe(s)       +       2HCl (aq)      ->              FeCl2 (aq)           +      H2(g)

  1. Aluminium + Hydrochloric acid -> Aluminium chloride + Hydrogen

2Al(s)      +       3HCl (aq)        ->         AlCl3 (aq)           +      3H2(g)

  1. Magnesium + Sulphuric (VI) acid -> Magnesium sulphate (VI) + Hydrogen

Mg(s)     +       H2SO4 (aq)   ->          MgSO4 (aq)           +      H2(g)

  1. Zinc + Sulphuric (VI) acid -> Zinc sulphate (VI) + Hydrogen

Zn(s)        +       H2SO4 (aq)   ->          ZnSO4 (aq)           +      H2 (g)

  1. Iron + Sulphuric (VI) acid -> Iron (II) sulphate (VI) + Hydrogen Fe(s)          +       H2SO4 (aq)  ->         FeSO4 (aq)           +      H2(g)
  2. Aluminium + Sulphuric (VI) acid -> Aluminium sulphate (VI) + Hydrogen

2Al(s)            +       3H2SO4 (aq   ->   Al2 (SO4)3 (aq   +      3H2 (g)

  1. Reaction of metal carbonates and hydrogen carbonates with mineral acids.

All acids react with carbonates and hydrogen carbonates to form salt, water and produce /evolve carbon (IV) oxide gas.

Metal carbonate   + Acid   ->   Salt   +    Water+ Carbon(IV)oxide gas

Metal hydrogen carbonate + Acid   ->   Salt   +   Water         + Carbon (IV) oxide gas

Experiment: reaction of metal carbonates and hydrogen carbonates with mineral acids.

(a)Place 5cm3 of dilute hydrochloric acid in a small test tube. Add half spatula full of sodium carbonate. Stopper the test tube using a cork with delivery tube directed into lime water. Record the observations made. Test the gas also with burning splint.

(b)Repeat the procedure in (a) above using Zinc carbonate, Calcium carbonate, copper carbonate, sodium hydrogen carbonate, Potassium hydrogen carbonate in place of Sodium carbonate.

(c)Repeat the procedure in (a) then (b) using dilute sulphuric (VI) acid in place of dilute hydrochloric acid.

 

Set up of apparatus

 

 

 

 

 

 

Sample observations

(i) effervescence/bubbles produced/fizzing in all cases.

(ii) Colourless gas produced in all cases.

(iii) Gas produced forms a white precipitate with lime water.

Explanation

All metal carbonate/hydrogen carbonate reacts with dilute acids to produce bubbles of carbon (IV) oxide gas. Carbon (IV) oxide gas is a colourless gas that extinguishes a burning splint. When carbon (IV) oxide gas is bubbled in lime water, a white precipitate is formed.

Chemical equations

  1. Sodium carbonate +Hydrochloric acid -> Sodium chloride + Carbon (IV) Oxide+ Water

Na2CO3(s)      +       2HCl (aq)       ->       2NaCl (aq)      +   H2O(g) + CO2 (g)

  1. Calcium carbonate +Hydrochloric acid -> Calcium chloride + Carbon (IV) Oxide+ Water

CaCO3(s)        +       2HCl (aq)       ->       CaCl2 (aq)      +   H2O(g) + CO2 (g)

  1. Magnesium carbonate +Hydrochloric acid ->Magnesium chloride + Carbon (IV) Oxide+ Water

MgCO3(s)       +       2HCl (aq)       ->       MgCl2 (aq)      +   H2O (g) + CO2 (g)

  1. Copper carbonate +Hydrochloric acid ->Copper (II) chloride + Carbon (IV) Oxide+ Water

CuCO3(s)        +       2HCl (aq)       ->       CuCl2 (aq)      +   H2O (g) + CO2 (g)

  1. Copper carbonate +Sulphuric (VI) acid ->Copper (II) sulphate (VI) + Carbon (IV) Oxide+ Water

CuCO3(s)        +     H2SO4 (aq)    ->    CuSO4 (aq)     +   H2O (g) + CO2 (g)

  1. Zinc carbonate +Sulphuric (VI) acid ->Zinc sulphate (VI) + Carbon (IV) Oxide+ Water

ZnCO3(s)        +     H2SO4 (aq)    ->    ZnSO4 (aq)     +   H2O (g) + CO2 (g)

  1. Sodium hydrogen carbonate +Sulphuric (VI) acid ->Sodium sulphate (VI) + Carbon (IV) Oxide+ Water

NaHCO3(s)     +     H2SO4 (aq)    ->    Na2SO4 (aq)     +   H2O (g) + CO2 (g)

  1. Potassium hydrogen carbonate +Sulphuric (VI) acid ->Potassium sulphate (VI) + Carbon (IV) Oxide+ Water

KHCO3(s)       +     H2SO4 (aq)    ->    K2SO4 (aq)     +   H2O (g) + CO2 (g)

  1. Potassium hydrogen carbonate +Hydrochloric acid ->Potassium chloride + Carbon (IV) Oxide+ Water

KHCO3(s)       +     HCl (aq)        ->    KCl (aq)     +   H2O (g) + CO2 (g)

  1. Sodium hydrogen carbonate +Hydrochloric acid ->Sodium chloride + Carbon (IV) Oxide+ Water

NaHCO3(s)     +     HCl (aq)        ->    NaCl (aq)     +   H2O (g) + CO2 (g)

  1. Neutralization by bases/alkalis

All acids react with bases to form a salt and water only. The reaction of an acid with metal oxides/hydroxides (bases) to salt and water only is called neutralization reaction.

Since no effervescence/bubbling/fizzing take place during neutralization:

(i) The reaction with alkalis requires a suitable indicator. The colour of the indicator changes when all the acid has reacted with the soluble solution of the alkali (metal oxides/ hydroxides).

(ii) Excess of the base is added to ensure all the acid reacts. The excess acid is then filtered off.

Experiment 1: reaction of alkali with mineral acids.

(i)Place about 5cm3 of dilute hydrochloric acid in a boiling tube. Add one drop of phenolphthalein indicator. Using a dropper/teat pipette, add dilute sodium hydroxide dropwise until there is a colour change.

(ii)Repeat the procedure with dilute sulphuric (VI) acid instead of hydrochloric acid.

(iii)Repeat the procedure with potassium hydroxide instead of sodium hydroxide.

Sample observation:

Colour of phenolphthalein change from colourless to pink in all cases.

Explanation

Bases/alkalis neutralize acids. Acids and bases/alkalis are colourless. A suitable indicator like phenolphthalein change colour topink, when all the acid has been neutralized by the bases/alkalis. Phenolphthalein change colour frompink, to colourless when all the bases/alkalis has been neutralized by the acid.

Chemical equation

Sodium oxide   +   Hydrochloric acid    ->   Sodium chloride   +    Water

Na2O(s)    +               HCl              ->         NaCl(aq)         +     H2O(l)

Potassium oxide   +   Hydrochloric acid    ->   Potassium chloride   +    Water

K2O(s)           +              HCl              ->         KCl(aq)         +     H2O(l)

Sodium hydroxide   +   Hydrochloric acid    ->   Sodium chloride   +    Water

NaOH(s)         +               HCl               ->         NaCl(aq)         +     H2O(l)

Ammonia solution   +   Hydrochloric acid    -> Ammonium chloride   +    Water

NH4OH(s)     +               HCl               ->         NH4Cl (aq)           +     H2O (l)

Potassium hydroxide   +   Hydrochloric acid    ->   Potassium chloride   +    Water

KOH(s)               +               HCl              ->         KCl(aq)               +     H2O(l)

Sodium hydroxide   +   sulphuric (VI)acid    ->   Sodium sulphate(VI)   +    Water

2NaOH(s)       +               H2SO4          ->         Na2SO4 (aq)           +   2H2O (l)

Potassium hydroxide   + sulphuric (VI) acid ->   Potassium sulphate (VI)   +    Water

2KOH(s)             +               H2SO4      ->         K2SO4 (aq)                + 2H2O (l)

Ammonia solution + sulphuric (VI) acid    -> Ammonium sulphate (VI)   + Water

2NH4OH(s)             +       H2SO4                ->    (NH4)2SO4 (aq)                + 2H2O (l)

Magnesium hydroxide + sulphuric (VI) acid -> Magnesium sulphate (VI) + Water

Mg (OH)2(s)       +       H2SO4          ->         MgSO4 (aq)           +   2H2O(l)

Magnesium hydroxide + Hydrochloric acid -> Magnesium chloride + Water

Mg (OH)2(s)       +       HCl(aq)          ->         MgCl2 (aq)           +   2H2O(l)

 

CHEMISTRY NOTES FORM 1-4 PDF

UNIT 1: INTRODUCTION TO CHEMISTRY.

Unit Checklist.

Meaning of chemistry

  • Matter
  • States of matter
  • Properties of the different states of matter.
  • Conductors and non-conductors.

DOWNLOAD FREE PDF NOTES HERE; Free Chemistry notes, revision questions, KCSE past Papers, Exams, Marking Schemes, Topical revision materials, Syllabus and Many more

Role of chemistry in society.

Laboratory rules.

  • Necessity for laboratory rules.
  • The laboratory rules and regulations.
  • Laboratory safety symbols.

Common apparatus used in a chemistry laboratory.

The Bunsen burner.

  • Structure
  • Functions of the various parts.
  • Types of Bunsen burner flames.

Methods of gas collection.

  • Upward delivery
  • Downward delivery
  • Over water
  • Using a collecting syringe.

Drying of gases

  • Using concentrated sulphuric acid.
  • Using anhydrous calcium chloride
  • Using calcium oxide.

Drugs and drug abuse.

 

Meaning of chemistry.

– It is a branch of science which deals with the composition and properties of matter.

 

Matter

– Matter is anything that has mass and occupies space.

 

States of matter.

– Matter exists in three different states: solids, liquids and gases.

 

Properties of the different states of matter.

 

  Solid Liquids Gases
Mass Definite Definite Definite
Shape Definite Indefinite: they take the volume of the container in which they are in. Indefinite: they take the shape of the container in which they are.
Volume Definite Definite Indefinite: volume may increase with increase in temperature; and decrease with decrease in pressure

 

Note: Conductors and non-conductors:

– The flow of electric current through materials is called electrical conductivity.

– Solid substances which allow electric current to flow through them are called conductors.

– Solid substances that do not allow electric current to flow through them are called non-conductors.

 

Role of chemistry in a society.

– Chemistry has enabled extraction of chemicals from plants.

– It is used in the manufacture of substances such as soap, glass, plastics, medicine, rubber, textiles etc from naturally occurring substances.

– Purification of substances from natural raw materials.

– It forms a basis for entry into careers e.g. teaching, medicine, chemical engineering etc.

 

Laboratory rules and safety symbols.

Necessity of laboratory safety rules.

  1. To avoid accidents and injuries during practical experiments in the laboratory.
  2. To avoid damage to and breakage of apparatus and laboratory fittings.
  3. To avoid wastage of laboratory chemicals.

 

The laboratory safety rules and regulations.

– Never run while in the laboratory;

Reason: You may injure others or yourself in the laboratory.

– Never taste or eat something in the laboratory;

Reason: to avoid poisoning.

– Always consult your teacher before trying out any experiment; so as to avoid accidents.

– Label all chemicals in use so as to avoid confusion.

– Always use a clean spatula for scooping a substance from a container to minimize contamination.

– Always hold test-tubes and boiling tubes using test tube holder when heating; to avoid being burned.

– When heating a substance never let the open end of the tube face yourself or anybody else, because the liquid may spurt out and cause injury.

– Never look directly into flasks and test tubes where reactions are taking place, because the chemicals may spurt into your eyes and cause injury.

– Never smell gases directly. Instead, waft the gaseous fumes near your nose with your hand.

– Experiments in which poisonous gases and vapours are produced must be carried out in a fume cupboard or an open space outdoors.

– Always keep flammable substances away from flames because they easily catch fire.

– Always report any accidents to the teacher or the laboratory technician immediately for necessary action.

– In case of an accident do not scramble for the same exit, because it may hinder easy escape.

– Always put off flames that are not in use in order to avoid accidents and minimize fuel wastage.

– If a chemical gets on your skin or mouth rinse it immediately with a lot of water.

– Always dispose off the chemicals already used safely to avoid explosions and contaminations.

– Always work on a clean bench. After completing your experiment, clean all the pieces of apparatus you have used and return them to their correct storage places.

– Always read the label of the reagents before using them.

 

Safety symbols.

– These are signs found on the labels of bottles or cartons containing dangerous chemicals.

– The common safety symbols are as follows:

Symbols Meaning.
 

 

 

 

 

Toxic: are very poisonous and can easily kill if swallowed, inhaled or on contact with the skin.

Examples: Chlorine and mercury;

  Harmful: Less harmful (dangerous) than the toxic substances; are only likely to cause pain and discomfort.

Examples: copper (II) sulphate, lead (II) oxide

  Highly flammable: are substances that catch fire easily and must not be handled near open fire.

Examples: ethanol, hydrogen

  Oxidizing: rapidly provide oxygen and can cause fire to burn more fiercely.

Examples: potassium manganate (VII), hydrogen peroxide

  Corrosive: are substances that cause burns to skin and fabric; and can also react with other substances such as metals

Examples: nitric (V) acid, conc. sulphuric acid, bromine.

  Irritant: can cause blisters or reddening of the skin; usually irritate the respiratory tract, skin, eyes etc.

Examples: calcium chloride and zinc sulphate

Common Chemistry laboratory apparatus and their uses.            

 

Name of apparatus Diagram. Use.
Test tubes  

 

 

 

 

 

 

– General laboratory experiments; like heating solids; qualitative analysis etc
Boiling tubes

 

 

 

 

 

 

– Mainly used for heating small amounts of solids and liquids.
Test tube holder

 

 

 

 

 

 

  Used for holding test tubes and boiling tubes during heating experiments.
Measuring cylinder

 

 

 

 

 

 

 

– Measuring accurate volumes of liquids in the laboratory
Beaker

– Lipped glass or plastic vessels of various capacities.

 

 

 

 

– Glass beakers are used for boiling liquid substances;

– Holding solutions during chemistry experiments.

Filtering funnel

 

 

 

 

 

 

 

– Directing liquids into containers with small narrow mouths;

– Holding filter papers during filtration;

Name of apparatus Diagram Use
Stirring rod

 

 

 

 

 

   
Watch glass

 

 

 

 

 

   
Thermometer

 

 

 

 

 

– Measuring temperatures during experiments.
Conical flask

 

 

 

 

 

 

– Normal laboratory experiments like titration.

– May be used for measuring volumes if graduated.

Round-bottomed flask

 

 

 

 

 

 

  – Used when heating liquid substances because heat is supplied uniformly.
Flat-bottomed flask

 

 

 

 

 

 

 

 

 

 

 

 

 

 

– Used for general laboratory experiments.
Evaporating dish

 

 

 

 

 

 

 

 

 

– Used when evaporating liquids.
Name of apparatus Diagram Use
Crucible

 

 

 

 

 

 

  – Use when heating solid substances that require strong heating.
Pestle and mortar

 

 

 

 

 

 

 

  – Crushing substances while the mortar holds the substances being crushed.
Pie clay (ceramic) triangle

 

 

 

 

 

  – Supporting crucibles during heating.
Tripod stand

 

 

 

 

 

 

 

  – Supporting beakers and flasks in which liquids are being heated.

 

Wire gauze

 

 

 

 

 

 

 

  – Used when glass apparatus are being heated; to facilitate even distribution of heat when heating substances in beakers or flasks
Clamp

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

– Supporting and holding pieces of apparatus during experiments.
Name of apparatus Diagram Use
Deflagrating spoon

 

 

 

 

 

 

  – Holding burning substances.
Spatula

 

 

 

 

 

 

  – Scooping solid substances from containers
Crucible tongs

 

 

 

 

 

 

 

  – Holding solid chemicals.
Condenser

 

 

 

 

 

 

 

   
Separating funnel

 

 

 

 

 

 

 

  – Separating immiscible liquids.
Thistle funnel

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

– Delivering liquid substances into other containers like flasks during reactions.
Name of apparatus Diagram Use
Wash bottle

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

– Holding water for rinsing apparatus
Dropping funnel

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 
Test tube rack

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

– Holding boiling tubes and test tubes.
Teat pipette (dropper)

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

– Sucking liquid chemicals and placing them in another container dropwise.
Burette

– It consists of a long narrow tube with a tap and a jet at the bottom.

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

– Delivering accurate volumes of liquids
Name of apparatus Diagram Use
Pipette

 

 

 

 

 

 

 

 

  – Delivering a specified volume of liquid accurately.
Gas jar

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

– Gas collection.
Trough

 

 

 

 

 

 

 

 

  – Holding some amount of water for some experiments e.g. gas preparation.
Reagent bottles

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

– Storing chemicals in liquid state.
Desiccator

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

– Drying substances or keeping substances free from moisture.
Name of apparatus Diagram Use
Spirit lamp

Note: less preferred for heating because their flames are not hot enough; and they deposit soot on apparatus making them dirty hence difficulty in observing changes during experiments

 

 

  – Heating substances in the laboratory.

 

 

 

 

 

 

 

 

Kerosene stove

Note: less preferred for heating because their flames are not hot enough; and they deposit soot on apparatus making them dirty hence difficulty in observing changes during experiments

 

 

 

 

 

 

 

 

 

 

 

 

 

– Heating substances in the laboratory.
Electric heater

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

– Heating substances in the laboratory.
Candles

Note: less preferred for heating because their flames are not hot enough; and they deposit soot on apparatus making them dirty hence difficulty in observing changes during experiments

 

 

 

 

 

 

 

 

 

 

 

 

 

 

– Heating substances in the laboratory.
Bunsen burner

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

– Heating substances in the laboratory.
Name of apparatus Diagram Use
Stop watch (clock)

 

 

 

 

 

 

 

 

  – Measuring time particularly in determination of reaction rates.

 

 

 

Beam balance

 

 

 

 

 

 

 

  – To take accurate weight measurements
Electronic balance  

 

 

 

 

 

 

 

– Take accurate weight measurements; and can take extremely low weight measurements.
Volumetric flask

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

Note: most chemistry apparatus are made of glass:

Advantages of glassware:

– It does not react with most chemicals

– Glass is transparent and hence reactions can easily be observed as they progress.

– Glass materials are easy to wash and rinse after experiments.

– They can be used comfortable in heating experiments.

 

Disadvantages:

– Have higher chances of breakages in case they fall during experiments.

– They are comparatively expensive to plastics

 

 

 

– Some materials like beakers may however be made of plastics.

Advantages of plastic apparatus.

– Have lower chances of breaking.

– They are relatively cheaper to buy.

 

Disadvantages:

– Plastics tend to react with some laboratory chemicals

– may not be transparent and hence reactions cannot easily be observed as they progress.

– Glass materials are difficult to wash and rinse after experiments.

– They cannot be used in heating experiments.

 

The Bunsen burner.

– is the most common heating apparatus in the laboratory.

– Was invented by a German scientist known as Wilhelm Bunsen hence the name.

– It uses natural (cooking) gas for heating.

 

Parts of a bunsen burner

– Chimney

– The air hole

– Collar

– The jet

– Base

– Gas inlet

 

Diagram: structure of a bunsen burner.                                                                  Diagram: Bunsen burner-components detached

 

 

 

 

 

 

 

 

 

 

 

 

 

Functions of the various parts:

  • The chimney:

– It is a hollow metallic cylinder with an air hole near its lower end.

Function:

– allows air and the laboratory gas from the jet mix before they start burning at the upper end of the chimney.

– Its upper opened end provided a site where the gas burns.

 

  • The air hole:

– Is a small aperture found at the lower end of the chimney and smaller than the collar.

– Its diameter (size) is regulated by the collar.

Function:

– Allows air (oxygen) to enter and mix with the laboratory gas in the chimney.

 

  • The collar:

– Is a metallic ring with an air hole whose diameter is the same size as that of the air hole in the chimney.

– It fits into the lower part of the chimney; and can rotate around the chimney opening or closing the air hole.

Function:

– Regulates the amount of air entering the chimney.

 

  • The jet:

– It is a very tiny opening just below the air hole, that connects the gas inlet to the chimney.

Function:

– allows the laboratory gas (methane) into the chimney at high pressure.

 

  • The gas inlet:

– It is a hollow metal connected to the base and extending into the jet.

– Its external opening is usually connected to a rubber tubing that is connected to a gas tap.

Function:

– Allows laboratory gas from the cylinders (reservoirs) in the lab; through the gas taps into the Bunsen burner.

 

  • The base:

– A thick heavy metal, that is usually circular or oval.

Function:

– It supports the Bunsen burner on the bench.

 

The Bunsen burner flames.

– A flame is a mass of burning gases.

– A bunsen burner can produce two types of flames depending on the size of the air hole and hence amount of air entering the chimney.

 

Types of flames.

  • Luminous flame.
  • Non-luminous flame.

 

(a). The luminous flame.

– It is a large bright yellow flame produced when the air hole is closed and hence no air enters the chimney.

 

Characteristics of a luminous flame.

– It is large, quiet and bright yellow.

– Colour is not uniform and it ahs four zones.

– It produces less heat.

– It gives a lot of light to the glow of unburnt hot carbon particles

– It produces soot.

 

 

Diagram: the luminous flame.

 

 

 

 

 

 

 

 

 

 

Parts of a luminous flame.

  • The thin outer zone:

– Is a fairly visible, narrow zone on the outer surface of the flame.

– At this point methane (lab gas) mixes with sufficient air from the outside and burns completely to carbon (IV) oxide and water.

 

  • The inner bright yellow zone:

– It is a large bright yellow zone that lies beneath the thin outer zone.

– Here, air supply is insufficient resulting to incomplete combustion of the gas.

– Consequently the gas burns producing tiny carbon particles instead of carbon (IV) oxide.

– The white hot carbon particles glow brightly and are responsible for the yellow colour and the emission of light.

– On cooling the carbon particles form soot, which blackens the bottom of the apparatus being heated.

 

  • The almost colourless inner zone.

– Is found below the yellow inner zone; and consists mainly of unburnt gases.

 

  • The blue zone (region)

– Is found on the outer side of the base of the flame.

– Here, air near the flame rises rapidly due to convection currents and mixes with the burning gas.

– This makes burning more complete than in the two upper parts above it.

 

Advantages of the luminous flame:

– Can be used for lighting purposes; because it produces more light.

 

Disadvantages.

– Produces less heat hence inefficient in heating.

– Due to production of soot it blackens apparatus thus preventing better observations of experiments.

 

 

 

 

 

 

 

 

 

 

(b). The non-luminous flame.

– It is a small blue flame produced when the air hole is completely open and hence a lot of air enters the chimney.

 

Characteristics of a non-luminous flame.

– It is small, noisy and blue.

– Colour is uniform and it ahs three regions.

– It produces comparatively more (a lot of) heat.

– It does not produce soot, due to complete combustion hence no carbon particles remain.

– It produces less light due to lack of white-hot carbon particles.

 

Diagram: the luminous flame.

 

 

 

 

 

 

 

 

 

 

Parts of a non-luminous flame.

  • The outer pale blue region.

– It is a large light blue zone.

– Here, there is a lot of air coming up the chimney from the air hole and from the outside.

– The air gas mixture thus burns completely to carbon (IV) oxide and water.

– No soot formation because there are no carbon particles.

 

  • The middle greenish blue region.

– consists of partially burnt gas-air mixture, due to insufficient air supply.

– However as the mixture rises up the pale blue region, it undergoes complete combustion due to plenty of air (from outside)

 

  • The inner almost colourless region.

– Is located at the base of the flame.

– It consists of unburnt gas-air mixture.

 

Advantages of a non-luminous flame.

– Gives out a lot of heat hence very efficient in hating.

– It does not form soot hence will leave apparatus clean even after experiment (heating).

 

Disadvantages:

– It uses a lot of laboratory gas in burning.

– cannot be used for lighting purposes since it produces very little light.

 

 

 

 

Differences between a luminous and a non-luminous flame.

 

Luminous flam Non-luminous flame
Bright yellow in colour Blue in colour
Produces a lot of light Produces a lot of light.
Large and unsteady Small and steady
Produces soot Does not produce soot
Has four zones Has three zones
Burns quietly Burns noisily
Moderately hot Very hot

 

Experiments on Bunsen burner flames.

  1. To investigate the heating effects of the luminous and non-luminous flames.

Apparatus:

– Bunsen burners, 250 ml beakers, lighter, stopwatch, tripod stand, wire gauze.

 

Procedure

– 100 cm3 of water is put into ach of the two 250 ml beakers.

– One beaker is put over a luminous flame while the other is simultaneously put over a luminous flame

– Time taken for water to boil is noted for each set up.

– The bottom of ach beaker is observed for any changes.

 

Apparatus

 

 

 

 

 

 

 

 

 

Observations.

– Water heated over the non-luminous flame boiled ion a shorter time than the same amount of water heated over a non-luminous flame.

– The bottom of the beaker heated over the non-luminous flame remained clear but the one heated over the luminous flame was covered with black deposits of soot.

 

Explanations.

– The non-luminous flame is hotter than the luminous flame; hence boils the water faster

– The hottest part of the luminous flam is the outer blue zone.

– Incomplete combustion in the luminous flame leads to production of carbon particles, which when hot glow yellow and on cooling forms black soot on the beaker;

– Incomplete combustion in a non-luminous flame leads to production of carbon (IV) oxide and steam only, hence no soot formation.

 

Conclusions.

– The non-luminous flame is hotter than the luminous flame.

– The non-luminous flame is cleaner than the luminous flame.

 

  1. To investigate the hottest part of a non-luminous flame.

Requirements

– Bunsen burner, stiff white paper (cardboard), wooden splint.

 

Procedure

– A bunsen burner is ignited with the air hole open to get anon-luminous flame.

– A piece of white paper (cardboard) is slipped into the flame in region marked X as shown below.

– The piece of paper is removed quickly before it catches fire.

– A fresh piece of paper is then slipped into region marked Y as shown below; then again quickly removed before it catches fire.

– The experiment for each of the regions marked X and Y is then repeated using wooden splints.

– The splints should be held long enough for some of their parts to get charred

Apparatus

 

 

 

 

 

 

 

 

Observations.

  • Using pieces of paper.

– In region X, the part of the paper that was in contact with the flame was charred uniformly as shown below.

– In region Y, the part of the paper in contact with the flame had a charred ring with an unburnt part in the middle of the ring as shown below

 

Diagrams

 

 

 

 

 

  • Using wooden splints.

– In region X, the part of the splint in contact with the flame was charred uniformly as shown below.

– In region Y, the part of the splint in contact with the flame had an unburnt part in between two charred regions as shown below.

 

Diagrams:

 

 

 

 

 

 

 

 

 

 

Explanations.

– Regions which become charred indicate that they are the hottest part of the flame.

– Region X corresponds to the outermost blue region of a non-luminous flame.

– Region Y is the almost colourless region of the non-luminous flame, which is however surrounded by the middle greenish blue and the outer pale blue zones.

–  Thus in region X, the uniform charring of the paper and splint indicate that the outer pale blue zone is the hottest pat of the flame.

– Similarly the charred ring for experiment in region Y show that the parts in contact with the outer pale blue zone gets burnt faster before the parts in contact with the almost colourless or the greenish blue zones.

 

Conclusions.

– The hottest part of the non-luminous flame is the outermost pale blue zone.

– During heating the object being heated should not be placed nearer the chimney; these parts are less hot.

– For efficient heating the object being heated should be placed at the outermost region of the flame.

 

  1. To show the presence of unburnt gases in a Bunsen burner flame.

Apparatus:

– Bunsen burner, tongs, narrow hard glass tubing.

 

Procedure

– A bunsen burner is lit and adjusted to get a non-luminous flame.

– A narrow hard glass tubing is held with a pair of tongs and one of its end s is placed in the colourless zone of the flame.

– A match is lit and placed at the free end of the glass tubing.

 

Apparatus

 

 

 

 

 

 

 

Observations.

– A flame is obtained at the free end of the glass tubing.

 

Explanations.

– The tubing trapped unburnt gases at the almost colourless zone of the flame.

– The trapped gases combined with atmospheric air (oxygen) at the other (free) end of the tubing hence the flame.

 

Conclusions.

– The almost colourless region contains unburnt gases.

 

 

 

 

  1. To show the hottest part of the flame.

Apparatus:

– Bunsen burner, match stick

 

Procedure

– A matchstick is placed at the top of the bunsen burner chimney using a pin.

– A bunsen burner is lit and adjusted to get a non-luminous flame.

– The match stick is observed fro sometime for any changes.

– If no observable changes are made, the matchstick is then slowly raised towards the blue zone and observed keenly.

 

Apparatus

 

 

 

 

 

 

 

Observations.

– The matchstick did not ignite while it was at the bottom of the flame (resting on top of the chimney).

– It ignited as it was being raised towards the outer pale blue zone.

 

Explanations.

– The bottom of the flame (just on top of chimney) corresponds to the almost colourless zone.

– This zone contains unburnt gases, hence no burning occurs and is thus least hot to cause ignition of the matchstick.

– As the matchstick is raised upwards it moves past the greenish blue zone (where there is partial combustion) then to the outer pale blue zone where there is complete combustion and hence most heat.

– The heat in this region is adequate to cause ignition of the matchstick.

 

Conclusions.

– The outer pale blue zone is the hottest part of the non-luminous flame, and is thus the correct position to place an object during heating.

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

Methods of gas collection.

– Various chemical reactions produce gases; some of which are colourless while others are coloured.

– Additionally some gases are poisonous to the human body, while others are major causes of environmental pollution.

 

Examples:

  • Coloured gases:

Chlorine (green-yellow); nitrogen (IV) oxide (brown); bromine (red-brown)

 

  • Colourless gases:

Oxygen; carbon (II) oxide; carbon (IV) oxide; sulphur (IV) oxide; hydrogen; ammonia etc.

 

Factors affecting method used in collecting a gas.

– Density

– Solubility in water.

– Colour

– Toxicity

 

Summary on collection methods.

 

Method Apparatus Characteristic of gas
Upward delivery

– Also called downward displacement of air

 

 

 

 

 

 

 

 

– Must be less dense than air.

Examples: Hydrogen, ammonia gas.

Note: being lighter the gas is supported by the denser air from below;

– When used for colourless gases, it is not possible to know when the gas jar is full;

Downward delivery (upward displacement of air)   – Must be denser than air.

Examples: carbon (IV) oxide; nitrogen (IV) oxide; chlorine gas;

Note: – The gas displaces air and settle at the bottom of the collecting vessel

– Unless the gas is coloured, it is difficult to know when the container is full

Over water   – insoluble or only slightly soluble in water;

– does not react with water

Examples: carbon (IV) oxide; hydrogen; carbon (II) oxide;

Note: – with this method it is easy to tell when the gas jar or collecting tube is full of gas;

– This method cannot be used when the gas is required dry;

 

Collecting syringe

– the gas produced is collected in a syringe;

  – Mainly for poisonous gases; since the gases are confined and leakages are limited;

Note: this method allows collection of small volumes of gases;

– It also allows direct measurement of volume of gas produced;

Drying of gases.

– Is the process by which the moisture in a gas being prepared is removed prior to collection.

– This is done by passing the gas through chemicals that absorb moisture.

– Such chemicals are called drying agents.

– The drying agents should not react with the gases being dried.

 

Examples of drying agents.

– Anhydrous calcium chloride

– Concentrated sulphuric acid.

– Calcium oxide.

 

Apparatus and drying agents

 

 

 

 

 

 

 

 

 

 

 

Collection and drying of some gases

 

Gas Collection method Drying agent
Oxygen Over water Concentrated sulphuric (VI) acid; anhydrous calcium chloride.
Hydrogen Over water, upward delivery Concentrated sulphuric (VI) acid; anhydrous calcium chloride
Nitrogen Over water Concentrated sulphuric (VI) acid; anhydrous calcium chloride
Carbon (IV) oxide Over water, downward delivery Concentrated sulphuric (VI) acid; anhydrous calcium chloride
Ammonia Upward delivery Calcium oxide

 

Drugs and drug abuse.

Drug: is a chemical substance that alters the functioning of the body.

 

Types of drugs

(i). Medicinal drugs (medicines):

– Are drugs mainly used for treatment and prevention of diseases.

– Are also classified into two: over the counter drugs and prescription drugs.

 

  • Over-the-counter drugs.

– Are medicinal drugs that can be bought at a pharmacy or retail shop without written instructions from a doctor.

Examples: Mild painkillers like aspirin, panadol, paracetamol, drugs for flu etc.

 

  • Prescription drugs:

– Are strong medicines which should only be taken upon a doctors instruction (prescription).

– In this prescription, the doctors give a dosage, which indicates the amount and the rate at which it should be taken.

 

(ii). Leisure drugs.

– Are drugs that are usually taken for pleasure.

– Are classified into two:

  • Mild drugs: alcohol, tobacco;
  • Narcotic drugs: marijuana, cocaine, heroin, mandrax etc.

 

 

Drug abuse:

– Is the indiscriminate use of a drug for purposes which it is meant for; or administration of an overdose or underdose of a drug; as well as use of drugs for leisure purposes.

Note:

– The worst form of drug abuse is the taking of drugs for leisure purposes; and the most commonly abused drugs are the leisure drugs.

 

Effects of commonly abused drugs.

  • Alcohol:

– Affects the brain and the nervous system

– Damages the liver, and is a common cause of liver cirrhosis.

– Poor health due to loss of appetite.

– Time for working is wasted in drinking and hence less productivity and even lose of jobs; which results to poverty and family disintegrations.

 

– Bad breath, discoloured fingers and teeth

– Cause diseases such as bronchitis and tuberculosis.

– damages the lungs and is a common cause of lung cancer due to chemicals found in the cigarettes.

– Smoking during pregnancy is a common cause of miscarriages or still births.

– It is expensive: money used for other better uses is wasted in cigarette smoking.

 

  • Narcotic drugs:

– Interferes with the functioning of the brain.

– Results to addiction and drug dependency.

– Some are administered directly into the blood through syringes and hence common routes of transmission of HIV/AIDS.

 

General effects of drug abuse on the society.

– Drug abuses spend most of their money on drugs and hence neglect their family leading to misery and societal breakdown.

– Drunk drivers cause accidents.

– People who are drunk with a drug are unreasonable and cannot make logical decisions; and hence cannot be productive at that time.

– Drug abuse has resulted into loss of morals leading to higher rates of rapes, violent crimes, murders, prostitution etc.

– Drug abuse has fueled the spread of sexually transmitted diseases and HIV/AIDS.

 

Note:

Drug addiction:

– Is a situation in which an individual becomes dependent on a particular drug such that he cannot function normally without it; and lack of it result to some discomfort.

UNIT 2: SIMPLE CLASSIFICATION OF SUBSTANCES

 

Unit Checklist:

  1. Elements compounds and mixtures.
  2. Mixtures
  • Types of mixtures
  • Separation of mixtures
  • Basic concepts
  • Method of separation of mixtures.
    • Decantation
    • Evaporation
    • Condensation
    • Filtration
    • Crystallization
    • Separating funnel separation
    • Distillation
    • Sublimation
    • Chromatography
    • Solvent extraction
  1. Criteria for purity
  • Effects of impurity on melting point
  • Effects of impurity on melting point
  1. Nature of matter and kinetic theory of matter.
  • Effects of heat on matter
    • Melting
    • Evaporation
    • Condensation
    • Freezing
    • Freezing
    • Sublimation
  1. Permanent and non-permanent changes
  2. Constituents of matter
  • Atoms
  • Elements
  • Molecules
  • Compounds
  1. Names and symbols of common elements
  2. Simple word equations.

 

 

 

 

 

 

 

 

 

 

Elements compound and mixtures.

(a). Element:

– Is a pure substance that cannot be split up into simpler substances by chemical means.

Examples: copper, hydrogen, carbon.

 

(b). Compound:

– A pure substance that consists of two or more elements that are chemically combined.

Examples:

 

Compound Elements in the compound
Calcium carbonate Calcium, carbon and oxygen
Sodium chloride Sodium and chlorine
Ammonium nitrate Nitrogen, hydrogen, oxygen
Iron (II) sulphate Iron, sulphur, oxygen

 

(c). Mixture:

– A substance that consists of two or more elements or compounds that are not chemically combined

– Some mixtures can be naturally occurring while some are artificial.

 

Examples

Naturally occurring mixtures.

 

Mixture Components
Air Nitrogen, oxygen, carbon (IV) oxide, water vapour, noble gases etc
Sea water Water and various salts like chlorides of sodium, potassium and magnesium
Crude oil A mixture of hydrocarbons like methane, petrol, bitumen, etc
Magadi soda Sodium carbonate, sodium hydrogen carbonate and sodium chloride

 

Artificial mixtures.

 

Mixture Components
Soft drinks Water, citric acid, sugar, carbon (IV) oxide, stabilizers, sodium benzoate
Black ink Blue, black, yellow dyes and solvent
Cement Oxides of aluminium, iron, silicon, calcium and calcium carbonate.

 

Types of mixtures:

– There are two types of mixtures;

  • Homogenous mixtures
  • Heterogenous mixtures

 

(i). Homogenous mixtures.

– Is a mixture with a uniform composition and properties throughout its mass.

– The parts (components) of the mixture are uniformly distributed throughout the mixture

Examples:

Tea with sugar solution.

 

(ii). Heterogenous mixture:

Is a mixture without uniform composition throughout its mass.

Examples:

– Soil, rocks and sand mixture.

 

 

Separating mixtures.

A mixture can be separated into its various components (constituents) by appropriate physical means, depending on type of mixture.

 

Basic concepts:

Residue: solid that remains on the filter paper during filtration

 

Filtrate: liquid that passes past the filter paper during filtration

 

Solute: a solid that dissolves in a particular liquid

 

Solvent: the liquid in which a solute dissolves.

 

Saturated solution: a solution in which no more solute can dissolve at a particular temperature

 

Unsaturated solution: a solution that can take more of the solute (solute) at a particular temperature.

 

Miscible liquids: liquids that can mix together completely.

 

Immiscible liquids: liquids that cannot mix together completely.

 

There are various methods that can be used to separate mixtures.

These include:

  • Decantation
  • Evaporation
  • Condensation
  • Filtration
  • Crystallization
  • Separating funnel separation
  • Distillation (simple and fractional)
  • Sublimation
  • Chromatography
  • Solvent extraction
  1. Decantation:

– Is a method used to separate insoluble solids from liquids; a heterogenous mixture.

 

Procedure:

– The solid-liquid mixture is allowed to stand in a container.

– The insoluble solid settles at the bottom and the upper liquid portion poured out with care.

 

Apparatus.

 

 

 

 

 

 

 

 

Examples:

– Separation of sand-water mixture

– Separation of maize flour-water mixture.

 

Limitations (disadvantages) of decantation.

– It is not efficient as some fine suspended solids may come long with the liquid during pouring.

 

  1. Filtration.

– Is the separation of an insoluble solid from a heterogenous mixture (liquid) using a porous filter that does not allow the solids to pass through.

– Upon filtration the undissolved solid is left on the filter paper and is called the residue.

– The liquid that passes the filter paper is called filtrate.

 

Examples: separation of sand from water.

(i). Procedure.

– The filter paper is folded into ¼ and opened to from a cone.

 

Diagram: folding a filter paper.

 

 

 

 

 

 

 

– It is carefully placed inside a filter funnel.

– The apparatus are then arranged as shown blow.

– The sand-water mixture is then poured into the filter paper in the filter funnel.

– The collecting liquid is directed into a conical flask.

 

(ii). Apparatus.

 

 

 

 

 

 

 

 

 

 

Applications of filtration.

– Filtration of domestic water.

– Extraction of medicinal substances from plants.

– Extraction of sugar from sugarcane.

– Operation of a vacuum cleaner.

– Fuel filters in automobile engines.

 

 

  1. Evaporation.

– Is used to separate a soluble solid from its solution.

– Such solutions are usually homogenous mixtures.

– The solid is called a solute while the liquid is called a solvent.

 

Example: separation of salt from salt solution.

(i). Procedure:

– The salt solution is poured in an evaporating dish.

– The set up is then arranged as in the apparatus shown below.

– The solution is boiled under steam or sand bath until all the water in the salt solution evaporates and salt crystals remain in the dish.

 

(ii). Apparatus.

 

 

 

 

 

 

 

 

 

(iii). Observations and explanations.

– Upon heating the solution, water evaporates because it has lower boiling point than the salt.

– The solution is boiled until salt crystals start appearing on a glass rid dipped into the solution.

– This shall indicate that the solution is saturated.

– The saturated solution is allowed to cool and crystallize.

– The mother liquor (liquid that remains with the crystals) is poured and the salt (solid) dried between absorbent papers.

 

Note:

A crystal: is a solid that consists of particles arranged in an orderly repetitive manner.

 

– It is advantageous to boil the solution under a steam or sand bath rather than directly.

Reason:

– The steam or sand bath prevents the mixture from splashing out (spitting) of the evaporating dish.

– It also reduces chances of the evaporating dish cracking.

 

Applications of evaporation:

– Extraction of soda ash from Lake Magadi.

 

 

 

 

 

 

 

 

 

  1. Crystallization and recrystallization.

(a). Crystallization:

– is the process of formation of crystals from a solution.

– It involves evaporation of the solution to form a concentrated solution.

 

Example: crystallization of potassium nitrate from its solution.

(i). Procedure:

– About 5g of powdered potassium nitrate is added to 10cm3 of water in a boiling tube.

– The solution is heated until all the solid dissolves and then allowed to cool and crystallize.

Note:

– More potassium nitrate dissolves in hot water than in cold water.

– The resultant solution is then heated until crystals start appearing; and this can be confirmed by dipping a glass rod into the solution and feeling for crystals.

– This is called a saturated solution i.e. a solution that cannot take in any more of the solute at a given temperature.

– The saturated solution is then allowed to cool and crystallize.

 

(ii). Observations:

– The resultant solid particles have definite shapes.

– Some are needle-like while others are flat and sharp-edged.

– These are the potassium nitrate crystals.

 

(b). Recrystallization:

– Is used in obtaining pure crystals from a soluble solid containing impurities.

– Involves filtration and evaporation.

 

Examples:

Obtaining pure copper (II) sulphate crystals from impure copper (II) sulphate.

Purification of rock salt.

 

Note: The process can be enhanced by suspending a small piece of pure crystal into the saturated solution.

 

Diagram: recrystallization of copper (II) sulphate.

 

 

 

 

 

 

 

Applications of crystallization.

– Separation of Trona from sodium chloride in Lake Magadi.

 

  1. Distillation.

– Is the vapourisation of a liquid from a mixture and then condensing the vapour.

– Is used in the purification of liquids and separation of liquids from a mixture.

– It utilizes the differences in boiling points of the components of the mixture.

– Are of two types:

 

  • Simple distillation
  • Fractional distillation.

(i). Simple distillation.

– Is mainly used for purification of liquids containing dissolved substances.

– It is also useful in separating two miscible liquids with widely differing boiling points

 

Note:

Miscible liquids: Liquids that mix to from a uniform a uniform homogenous solution

– The liquid with the lower boiling point usually distills over first, and is collected.

 

Example: To obtain pure water from sea water.

(i). Procedure:

– Salty sea water is poured into a distillation flask.

– A few pieces of pumice or porcelain is added to the solution.

Reason:

– To increase the surface area fro condensation and evaporation.

 

– The solution is heated until it starts boiling, then the burner removed so that the liquid boils gently.

– The boiling goes on until the liquid (distillate) starts collecting in the beaker.

 

(ii). Apparatus.

 

 

 

 

 

 

 

 

 

 

 

 

 

 

(iii). Observations and explanations:

– The water boils and the resultant steam is passed through the Liebig condenser.

– As the vapour passes through the condenser, it is cooled by circulating cold water through the jacket of the condenser.

– The cold water enters through the lower bottom and leaves through the top upper part.

Reason:

– To provide more time for the cold water to condense the vapours.

 

– The distillate is collected in the beaker while the residue remains in the distillation flask.

 

Applications of simple distillation.

– Manufacture of wins and spirits.

– Desalinization of sea water to obtain fresh water.

(ii). Fractional distillation:

– Is a method used fro the separation of miscible liquids with very close boiling points.

Examples:

Ethanol and water.

 

– It is a modification of simple distillation in which the fractionating column is inserted on top of the distillation flask.

– All the components must be volatile at different extents in order for separation to be possible.

 

The fractionating column.

– Is usually an elongated (glass) tube, packed with pieces of glass beads or pieces of broken glass.

 

Role of glass beads.

– To increase the surface area for vapourisation of the various components of the mixture and allow the separation of the vapours to occur.

– Thus the more the glass beads in the fractionating column, the higher the efficiency of separation.

Note:

– The efficiency of the fractional distillation so s to get more pure components can also be done by:

  1. Increasing the length of the fractionating column (making it longer)
  2. Making the fractionating column narrower (decreasing the diameter)

 

Volatile liquids:

– Are liquids with the ability to change into vapour.

– More volatile liquids vapourize and condense faster than the less volatile liquids.

 

Note:

– During fractional distillation, the components of a mixture are collected at intervals, one at a time with the most volatile (lowest boiling point) coming out first.

– Each component collected in the receiver is called a fraction.

 

Example: separation of ethanol and water.

(i). Apparatus.

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

(ii). Procedure:

– Water-ethanol mixture is poured into a round-bottomed flask.

– The apparatus is then connected and set up as shown below.

 

Note:

– The thermometer bulb must be at the vapour outlet to the condenser.

Reason:

– For accurate determination of the vapourisation temperature for each fraction.

 

– The mixture is then strongly heated until the first fraction comes out of the distillation flask into the conical flask.

– Collection of the fractions should be done in a conical flask other than in a beaker.

Reason:

– To reduce the rates of evaporation of the fractions, especially the highly volatile ones (in this case ethanol)

 

– For this particular separation the first temperatures recorded by the thermometer should not exceed 80oC; to ensure that the first fraction is only ethanol.

 

(iii). Discussion.

– Ethanol boils at 78oC and water boils at 100oC.

– When the mixture is heated, ethanol and water evaporate and pass through the fractionating column which is filled with glass beads to offer a large surface area

– The large surface area encourages evaporation of ethanol and condensation of water vapour.

– Water can be seen dropping back into the distillation flask.

-Ethanol vapour passes through the condenser and warm liquid ethanol is collected in the conical flask.

 

Note:

– The first portion is almost pure ethanol (about 97%) and burns quietly with a blue flame.

– It also has the characteristic smell of alcohols.

 

Industrial applications of fractional distillation.

– Separation of air into various components in BOC gases Kenya limited.

– Separation of crude oil into paraffin, petrol, kerosene diesel and other components in the Kenya oil refinery.

– Distillation of ethanol from molasses at Muhoroni Agro-chemicals company.

 

  1. Sublimation.

– Is the process by which a solid changes directly to gaseous state upon heating.

– It is used to separate a mixture in which one of the components sublimes on heating.

Note:

Solid                           Gas

 

Solids that sublime have very weak forces of attraction between the atoms and hence are easily broken on slight heating.

 

 

 

 

Examples of solids that sublime on heating.

– Iodine; sublimes to from a purple vapour.

– Ammonium chloride; sublimes to from dense white fumes;

– Solid carbon (IV) oxide (dry ice);

– Anhydrous iron (III) chloride; sublimes to give red brown fumes.

 

Examples: separation of iodine from sodium chloride.

(i). apparatus:

 

 

 

 

 

 

 

 

 

 

 

(ii). Procedure:

– The iodine-common salt mixture is poured into a beaker and placed in a tripod stand.

– A watch glass full of cold water is placed on the beaker.

– The beaker is heated gently until some dense purple fumes are observed.

 

(iii). Observations:

– A purple vapour appears in the beaker.

– A dark-grey shiny solid collects on the bottom of the watch-glass.

– White solid remains in the beaker.

 

(iv). Explanations:

– Upon heating the mixture iodine sublimes and condenses on the cold watch glass to form a sublimate of pure iodine.

Note:

– Solid carbon (IV) oxide (dry ice) is used a s refrigerant by ice cream and soft drink vendors.

Reason:

– It sublimes on heating; as it sublimes it takes latent heat from ice cream (soft drinks) thus leaving it cold.

– It is also advantageous as it does not turn into liquid, which could be cumbersome to carry and would mess up the ice cream.

 

  1. Chromatography.

– Is the separation of coloured substances using an eluting solvent.

– It is also used to identify the components of a coloured substance.

– It involves the use of a moving liquid (eluting solvent) on a material that absorbs the solvent.

– It involves two major processes:

  • Solubility:

The tendency of a substance to dissolve in a solvent.

  • Adsorption:

The tendency of a substance to stick on an adsorbent material.

Examples:

  1. Separation of components of black ink.

(i). Procedure:

– A filter paper is placed on the rim of an evaporating dish or a small beaker.

– A drop of the black ink is placed at the centre of the filter paper; allowed to spread out and dry.

– A drop of water (ethanol) is then added to the ink and allowed to spread.

– After complete spread of the drop, a second drop is added.

– Water drops are added continuously until the disc of coloured substances almost reaches the edge.

 

(ii). Observations:

 

 

 

 

 

 

 

 

Note: The dry filter paper showing the separated components of a mixture is called a chromatogram.

 

(iii). Explanations:

– Water is the eluting solvent since ink is soluble in it.

– The various dyes in the black ink move at different distances from the black spot hence the bands.

Reasons:

– The dyes have different solubilities in the solvent; the more soluble the dye, the further the distance it travels on the absorbent paper

– They have different rates of adsorption i.e. the tendency of the dyes to stick on the absorbent material; dyes with low rates of absorption travel far from the original spot.

 

Note:

Solvent front.

– Is the furthest distance reached by the eluting solvent on the filter paper.

 

Baseline:

– The point at which the dye to be separated is placed; i.e. it is the starting point of separation.

 

  1. To verify contents of red, black and blue inks.

(i). apparatus:

 

 

 

 

 

 

 

 

 

 

 

(ii). Observations:

 

 

 

 

 

 

 

 

 

 

 

(iii). Explanations:

– The mixtures A to D have various components with varying solubilities in the solvent (ethanol)

– Mixture D is the most pure because it has only one spot.

– Mixture C is the least pure (most impure), as it has the highest number of spots indicating it is composed of so many dyes (four)

– Mixture C has the most soluble dye; its last component is the one nearest to the solvent front.

– Mixtures with similar dyes in their composition have spots at same levels; in this case A, B and D.

 

Applications of chromatography.

– Purification of natural products such as hormones, vitamins and natural pigments.

– Detection of food poisons e.g. in canned foods and soft drinks.

 

  1. Solvent extraction.

– Is the extraction of a solute from its original solvent by using a second solvent in which it has a higher solubility

 

Example: extraction of oil from nuts.

(i). Apparatus.

 

 

 

 

 

 

 

 

 

 

(ii). Procedure:

– Some nuts are crushed in a mortar using a pestle; to increase the surface area for solubility.

– A suitable solvent such as hexane or propanone (acetone) is added.

– The nuts are further crushed in the solvent.

– The resultant solution is decanted in an evaporating dish, and left in the sun to evaporate.

– The liquid remaining in the evaporating dish is smeared onto a clean filter paper.

 

(iv). Observations;

– A permanent translucent mark appears on the filter paper.

(v). Explanations:

– The nuts are crushed when in contact with the solvent to bring more of the oil in the nuts closer to the solvent.

– Upon evaporation oil is left behind because it has a higher boiling point than the solvent.

– A permanent translucent mark verifies the presence of oils.

 

Applications of solvent extraction.

– Used by dry-cleaners to remove dirt (grease) and stains from “dry-clean-only” clothes such as sweaters, suits, dresses etc.

 

  1. Separating funnel separation.

– Is used fro separating a mixture with two or more immiscible liquids.

– Such liquids do not mix but instead form layers based on their densities.

– The heaviest liquid layer is found at the bottom of the separating funnel; while the lightest liquid is found at the top of the separating funnel.

– The liquids are drained one after the other by opening and closing the tap of the separating funnel.

 

Example: Separation of oil from water

Apparatus:

Beakers, separating funnel, paraffin oil, distilled water, rubber stopper.

 

Apparatus.

 

 

 

 

 

 

 

 

 

 

Procedure.

– The tap of the separating funnel is closed.

– Equal volumes of water and paraffin are put in a separating funnel until it is half full.

– The mouth of the funnel is closed with a stopper and the mixture shaken.

– The mixture is allowed to stand until two distinct layers are formed.

– The stopper is removed and the tap opened to allow the bottom layer to drain into the beaker.

– The tap is closed after most of the bottom layer has drained off.

– The beaker is removed and the rest of the bottom layer is drained into a separate container and discarded; to ensure that no part of the top layer (paraffin) gets into the beaker containing the bottom (water) layer.

– The other (top) layer is then drained into another beaker.

 

Observations:

– After the mixture has settled oil and paraffin separate into two layers.

– The first beaker contains only water; while the second beaker contains only paraffin.

 

 

Conclusion.

– Paraffin and water are immiscible.

– The top layer contains water which is denser while the top layer contains oil (paraffin) which is lighter.

 

Practical application:

– Extraction of useful substances from complex mixtures.

 

Example: Separation of iodine from sodium chloride.

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  1. Use of magnets.

– Is used to separate solid mixtures, one of which is magnetic (usually iron).

– The iron is picked with a magnet leaving the other components of the mixture behind.

 

Examples:

– Separation of powdered iron from iron powder-sulphur mixture.

 

Practical applications:

-In the extraction (mining of iron); where magnetic iron ore is separated from other materials in the crushed ore.

– Separation of scrap iron from non-magnetic materials like glass and plastics in recycling plants.

 

Criteria for purity.

  • Pure substance:

– Is a substance that contains only one type of compound or element.

 

Determination of purity

(a). Solids:

– Purity of solids is determined by measuring the melting point.

– Pure solids melt sharply over a narrow temperature range.

 

Examples:

– Naphthalene melts at 80oC – 81oC.

– Water melts at 0oC.

 

Effects of impurity on melting point.

– Impurities lower the melting point of a substance making it melt over a wide range of temperatures i.e. the melting point is not sharp.

 

Applications:

  1. Extraction of metals.

– Impurities are added to purified metal ores to lower their melting points, hence save energy and extraction costs.

  1. To prevent knocking of engines due to freezing of water in car radiators during cold seasons, impurities like ethylene glycol or salt (NaCl) is added.
  2. Defrosting of frozen roads and sidewalks in temperate countries, by sprinkling a salt such as sodium chloride.

 

(b). Liquids:

– Purity of a liquid is determined by measuring its boiling point.

– A pure liquid has a sharp boiling point.

 

Examples:

Pure water boils at 100oC at 1 atmospheric pressure.

Pure ethanol boils at 78oC.

 

 

 

 

Effect of impurity on boiling point.

– Impurities raise the boiling point of a liquid.

Example:

– Sea water boils at a higher temperature than pure water due to the presence of dissolved salts.

 

States of matter.

  • Matter:

– Matter is anything that occupies space and has mass.

– It is composed of either pure substances or a mixture of substances.

 

States of matter:

Matter exists in three states:

  • Solid
  • Liquid

 

Kinetic theory of matter:

– States that matter is made up of small particles which are in continuous random motion.

– The continuous random motion of particles in matter is called Brownian motion.

– The rate of movement of particles in matter depends on the state

 

(a). Solid state:

– Have closely packed particles held by strong forces of attraction.

– Particles do not move from one point to another but vibrate about a fixed position.

– Upon heating, they start to vibrate vigorously.

Reason:

– Due to increase in their kinetic energy.

 

(b). Liquid state:

– Particles are further apart from one another than those in the solid state

– Forces of attraction between the particles are weaker than those in the solid.

– The particles remain close, but are free to move from one position to another.

– On heating they gain energy and move rapidly.

 

(c). Gaseous state:

– The particles are far apart and free to move randomly in all directions.

– Consequently they lack definite shape and volume, but occupy the whole space within a container.

– Forces of attraction between the particles are very weak.

 

The effect of heat on substances.

– A substance can change from one state to another upon heating or cooling.

– These are physical changes and can be reversed.

– There are five processes involved in changes of state:

  • Melting
  • Evaporation
  • Condensation
  • Freezing
  • Sublimation

 

The processes involved in change of states of matter.

(i). Melting:

– Is a change of state from solid to liquid.

  • Melting point:

– Is the constant temperature at which the melting takes place.

 

Examples:
Ice melts at 0oC.

– Sodium chloride melts at 800oC.

 

– During melting the energy supplied to the particles is used to weaken the forces of attraction so that particles can move about.

 

(ii). Vapourisation (evaporation)

– Is change of state from liquid to gas.

  • Boiling point:

– Is the constant temperature at which a liquid changes from solid to a gas.

 

– During boiling, the energy supplied is used to break the forces of attraction in the liquid thus moving the particles far away from each other.

 

Examples:

Water boils at 100oC, while ethanol boils at 78oC at one atmospheric pressure.

Reason:

The forces of attraction between the water particles are stronger than those of ethanol.

 

(c). Condensation:

– Is the change of state from a gas to a liquid.

– Is a change due to decrease in temperature.

– When the temperature of gas is decreased, the particles lose kinetic energy to the surroundings to move slowly.

– The attractive forces become stronger, and the sample changes to a liquid.

Note:

– The temperature at which condensation occurs is the same as the boiling point.

 

(d). Freezing:

– Is the change from a liquid to a solid.

– It is also due to decrease in temperature.

– When a liquid is cooled, the particles lose energy and move very slowly.

– They attract one another strongly, and ultimately remain in fixed positions.

Note:

– The freezing point is the same as the melting point.

 

(e). Sublimation.

– Is the process whereby a solid does not melt when heated, but changes directly to the gaseous state.

 

Example:

– Iodine solid changes to purple vapour when heated to 70oC.

– Dry ice (solid CO2), used to cool ice cream, evaporates without leaving a liquid.

Note:

– The reverse of sublimation, whereby a gas changes directly to solid is called deposition.

 

Summary on changes of state.

E

 

Solid                           Liquid                         Gas

 

 

 

F

Key: A: melting; B: vapourisation; C: Freezing; D: Condensation; E: Sublimation; F: Deposition;

 

Experiment: Investigating changes in temperature when ice is heated.

(i). Procedure:

– A 250ml beaker is half-filled with dry ice, and the initial temperature recorded.

– The ice is heated, while stirring with a thermometer and the temperature recorded every 30 seconds.

– Heating and recording is done until the resultant water starts to boil.

– A graph of temperature against time is plotted.

 

(ii). Results:

 

Temperatures (oC) -10 0 30 60 90 120 150 180 210
Time (seconds)                  

 

(iii). Graph:

Effect of heat on pure ice

 

 

 

 

 

 

 

 

 

 

 

 

 

(iv). Explanations:

  • Point A-B:

– As the ice is heated the temperature rises steadily from -10oC to 0oC.

Reason:

– The heat supplied increases the kinetic energy of the ice (solid water) molecules; collisions between them hence increased temperature.

 

  • Point B-C:

-The temperature of the ice remains constant even as heat is applied.

Reason:

– Heat supplied is used to break the forces of attraction between the water molecules in ice.

– This is the melting point hence at B-C the ice melts.

  • Points C-D:

– At C, all the ice has already melted (turned to water).

– Between C and D, the temperature of the water increases as heating continues.

Reason:

– The heat supplied increases the kinetic energy of the water molecules; their rate of collision increases hence increased temperatures.

 

  • Points D-E:

– Temperature of the water remains constant even as heat is being supplied.

– Point D-E is the boiling point i.e. 100oC.

Reason:

– The heat supplied is used to break the forces of attraction between water molecules in the liquid.

 

  • Points E-F:

– At point E, all the liquid water has turned into vapour.

– Thus between E and F, the temperature of the vapour rises as heat is applied.

 

Note: Heating curve for an impure solid.

Effect of heat on impure ice

 

 

 

 

 

 

 

 

 

 

 

 

 

The cooling curve.

– Is a curve that shows how the temperature of a substance changes with time as it is cooled from a gas into a solid.

– It is the opposite of a heating curve.

 

Example: the cooling curve of water

 

 

 

 

 

 

 

 

 

 

 

 

 

 

Explanations:

  • Points A-B:

– Gaseous state; temperature is declining.

– Heat loss results into decrease in kinetic energy of the gaseous molecules.

 

  • Points B-C:

– This is the condensation point;

– The water vapour condenses to the liquid state; bonds are formed as the hest is lost.

 

  • Points C-D;

– Temperature of the liquid water is declining;

– Heat loss results into decrease in kinetic energy of the liquid molecules.

 

  • Points D-E;

– This is the freezing point;

– The temperature remains constant as the heat is being lost;

– The heat being lost results into bond formation; as the liquid forms a solid.

 

  • Points E-F;

– The water is now in solid state.

– The temperature of the solid declines as heat is being lost.

 

Permanent and temporary changes.

– Heat causes matter to change.

– Changes due to heat can either be permanent or non-permanent (temporary).

 

(a). Permanent changes.

– Are also called chemical changes.

– Involves substances that are relatively less stable to heat.

 

Characteristics of permanent (chemical) changes.

(i). New substances are formed.

(ii). Involves considerable heat changes; energy is either given out or absorbed.

(iii). The mass of the substance changes.

 

Types of permanent (chemical) changes.

– Chemical changes are of two main types:

  • Reversible permanent changes.
  • Irreversible (non-reversible) permanent changes.

 

(i). Reversible permanent changes.

– Are chemical changes in which the final new products can recombine to form the original substance, under certain conditions.

 

Generally:

A + B                          C + D

 

Reactants                                         Products

 

 

Examples:

  1. Effect of heat on hydrated blue copper (II) sulphate.

(i). Apparatus:

– Test tubes, Bunsen burner, test tube holder

– Hydrated copper (II) sulphate

 

(ii). Apparatus:

 

 

 

 

 

 

 

(ii). Procedure:

– Dry crystals of hydrated blue copper (II) sulphate are put in a clean dry test tube.

– The apparatus are arranged as above.

– The copper (II) sulphate is heated until no further change.

– The delivery tube is removed from the collected liquid while heating continues.

Reason:

– To avoid sucking back of the condensing liquid which would otherwise rehydrate the anhydrous copper (II) sulphate

 

– The test tube is allowed to cool and the remaining solid is divided into two portions.

– To one portion of the powder, add distilled water, while to the other potion add the condensed liquid.

 

(iii). Observations:
– A white solid/ powder remains in the test tube after heating.

– A colourless liquid condenses in the test tube dipped into the ice cold water.

– The colourless liquid turns the white solid into blue.

 

(iv). Explanations:
– Hydrated blue copper (II) sulphate have water of crystallization, giving it the characteristic blue colour.

– During heating, the heat energy supplied is used to drive out the water molecules (particles) out of the crystals;

– Without water, the copper (II) sulphate turns white and thus called anhydrous copper (II) sulphate;

– The water driven out of the crystals condenses in the test tube immersed in the ice cold water.

 

Heat

Equation

Cool

Hydrated copper (II) sulphate                                        anhydrous copper (II) sulphate + Water

                 Blue                                                                                                                  White

 

Heat

Cool

 

 

 

Chemically:
CuSO4.5H2O(s)            CuSO4(s) + 5H2O(g);

 

Confirmatory test for water.

  • It turns white anhydrous copper (II) sulphate to blue;
  • It changes blue cobalt chloride paper pink;

Confirmatory test that the water is pure:

  • It boils at 100oC;
  • It melts at 0oC;
  • It has a density of 1g cm-3;
  • It has a refractive index of 1.33;

 

 

Note:
– The delivery tube is removed from the collecting liquid while heating is continued; to ensure that no water condenses back into the copper (II) sulphate as this would cause rehydration;

– Addition of water to the anhydrous copper (III) sulphate changes its colour from white to blue;

 

Conclusion:

The effect of heat on copper (II) sulphate is a reversible chemical change;

 

  1. Effect of heat on ammonium chloride.

– When ammonium chloride is heated, it produces ammonia gas and hydrogen chloride gas.

– These are seen as dense white fumes.

– Reversible, when ammonia and hydrogen chloride are gases are reacted or allowed to cool, they produce ammonium chloride;

 

Heat

In summary:

Cool

Ammonium chloride solid                                        ammonium chloride + hydrogen chloride;

                         White                                                                                                                                 Dense white fumes

 

Heat

Cool

 

 

 

Chemically:
NH4Cl(s)                         NH3(g) + HCl(g);

     Ammonium chloride                        Ammonia gas       hydrogen chloride gas

 

  1. Decomposition of calcium carbonate.
Heat

In summary:

Cool

Calcium carbonate solid                               Calcium oxide + Carbon (IV) oxide;

 

(ii). Irreversible chemical change.

– Are chemical changes in which the resultant products cannot recombine to form the original substance (reactants);

– Majority of the chemical changes are irreversible;

 

Generally:
A + B                    C + D

Reactants                               Products

 

 

 

 

 

 

 

 

 

Examples:
1. Action of heat on potassium manganate (VII)

(i). Apparatus and chemicals.

– Bunsen burner, test tube, trough, wooden splint;

– Potassium managnate (VII);

 

(ii). Apparatus set up.

Heat
Potassium manganate (VII)

(iii). Procedure:
– 2 end-fulls of a spatula of potassium manganate (VII) are put in a hard glass test tube;

– The set up is assembled as shown above;

– The solid potassium manganate (VII) is heated, and the resultant gas collected over water;

– The resultant gas(es) is tested with a glowing splint;

 

(iv). Observations:

– The purple solid turns black;

– A colourless gas collects over water;

– The colourless relights a glowing splint;

 

(v). Explanations:
Potassium manganate (VII), a purple solid was decomposed (splint up) on heating to yield (give potassium manganate (III) and oxygen.

– The potassium manganate (III) is the black residue;

– The colourless gas is oxygen; and relighting a glowing splint is the confirmatory test;

 

In summary:
Potassium manganate (VII) → Potassium manganate (III) + oxygen

Purple solid                                                                       Black solid                                         Colourless gas

 

Note: It is not possible for oxygen and potassium manganate (III) to recombine back to potassium manganate (VII); hence the change is irreversible;

 

  1. Thermal decomposition of copper (II) nitrate.

– The blue solid decomposes to form a black solid; copper (II) oxide, red-brown fumes of nitrogen (IV) oxide and a colourless gas, oxygen;

 

In summary:
Copper (II) nitrate → Copper (II) oxide + Nitrogen (IV) oxide + oxygen

Blue solid                                           Black solid                          Brown (red-brown) fumes           Colourless gas

 

 

Note: Further examples of chemical changes

– The burning of any substance (except platinum);

– The rusting of iron;

– Addition of water to calcium oxide;

– Explosion of natural gas or hydrogen with air;

– Reacting of sodium in water;

 

Note: Exothermic and endothermic reactions:

(i). Exothermic reactions.

– Are reactions in which heat is released // given out to the surrounding;

– Usually the final temperature of the reaction vessel // mixture (e.g. beaker is higher than initially;

 

Examples:
– Freezing;

– Condensation;

– Deposition // sublimation of fumes to solid;

 

(ii). Endothermic reactions.

– Are chemical reactions in which heat is absorbed from the surrounding;

– The final temperature of the reaction vessel or reaction mixture is usually lower than the initial i.e. they are accompanied by a drop in temperature;

 

Examples.

– Melting;

– Vapourization;

– Sublimation (of solid to gas)

 

Summary on chemical changes.

Reaction Appearance of substance Changes during reaction New substance(s) Type of change
Heating hydrated copper (II) sulphate Blue Blue crystals turn into a white powder; colourless liquid condenses on cooling;

 

Anhydrous copper (II) sulphate and water Chemical
Heating potassium manganate (VII) Shiny purple crystals The purple solid turns black; evolution of a colourless gas;

 

Potassium manganate (III) and oxygen; Chemical;
Heating ammonium chloride White solid // powder; Dense white fumed that cools to a white solid;

 

Ammonia gas and hydrogen chloride gas; Chemical;
Heating lead (II) nitrate; White solid The white solid turns into a red solid during heating which on cooling turns yellow;

– Decrepitating sound;

– Brown fumes;

– colourless gas;

 

– Lead (II) oxide; nitrogen (IV) oxide and oxygen gas; Chemical;
Heating lead (II) nitrate; White solid The white solid turns into a yellow solid during heating which on cooling turns white;

– Decrepitating sound;

– Brown fumes;  colourless gas;

– Zinc (II) oxide; nitrogen (IV) oxide and oxygen gas; Chemical;
Heating copper turnings Brown turnings;

 

– Brown turnings // solid turn black; – Copper (II) oxide; Chemical;
Rusting of iron; Grey solid – Grey solid turns into a red brown solid;

 

– Hydrated iron (III) oxide; Chemical;
Heating Copper (II) nitrate; Blue solid The blue solid turns into a black solid;

– Brown fumes;

– colourless gas;

 

– Copper (II) oxide; nitrogen (IV) oxide and oxygen gas; Chemical;
Heating copper (II) carbonate Green solid The green solid turns into a black solid;

– colourless gas;

– copper (II) oxide and carbon (IV) oxide; Chemical;

 

(b). Temporary (non-permanent) changes.

– Are also called physical changes;

– They are changes that involve substances that are more stable to heat;

– On heating they do not decompose hence no new substances are formed;

 

Characteristics of permanent changes.

  1. All are reversible upon changes in temperature;
  2. No new substance is formed (instead there are only changes of state);
  3. The mass of the substances do not change;

 

Examples:

Solid Original appearance Observations during heating then cooling
1. Candle wax White sticky solid; – The solid melts into a colourless viscous liquid; and on cooling solidifies to the original solid wax again;
2. Iodine solid. Shiny dark-grey crystals; – The solid turns directly to purple vapour (sublimation);

– On cooling the purple iodine vapour (gas) changes directly to solid iodine (deposition);

 

ie. Iodine solid ═                iodine vapour;

Dark grey                          Purple

 

3. Zinc oxide White solid; – The white solid turns yellow on heating and upon cooling changes back to the original white colour;

 

ie. Zinc oxide ═                Zinc oxide;

White (cold)                          Yellow (hot)

 

4. Ice White – The solid water melts into liquid and on further heating the liquid vapourizes and turns into gas;

– On cooling the gas condenses to liquid which then freezes back into solid;

 

i.e Ice ═                  Water ═                  Gas

 

5. Platinum wire;   – A white glow of the metal is seen on heating, but on cooling the metal changes back to its original grey colour;

 

6. Lead (II) oxide; Yellow – The yellow solid turns red on heating and upon cooling changes back to the original yellow colour;

 

ie. Lead (II) oxide ═             Lead (II) oxide;

White (cold)                                   Yellow (hot)

 

Differences between Physical and Chemical changes.

 

Physical change Chemical change
1. Produces no new kind of substance; – Always produces a new kind of substance;
2. UIs usually (generally) irreversible; Are generally irreversible; with only few exceptions (i.e. most are irreversible);
3. The mass of the substance does not change; – The mass of the substance changes;
4. No energy is given out or absorbed i.e. are not accompanied by great heat changes; – Energy is usually given out or absorbed i.e are usually accompanied by great heat changes;

 

Constituents of matter

– A detailed examination of matter reveals that it is built of very tiny units called toms;

– Presently about 115 atoms have been identified;

– The arrangement and number of atoms in a substance will result into other much larger constituents of matter;

– These are:

  • Elements;
  • Molecules;
  • Compounds;
  • Mixtures;

 

  1. The atom;

– Is the smallest particle of matter that can take part in a chemical reaction;

– It is the smallest particle into which an element can be divided without losing the properties of the element;

– Atoms of various elements all differ from one another;

Examples:
– Copper is made up of many copper atoms;

– Sodium element is made up of many sodium atoms;

 

  1. Elements.

– An element is a substance that cannot be split into anything simple by any known chemical means;

– An element consists of a single type of atom;

– There are about 155 known elements, 90 of which occur naturally.

– Elements are classified into two main groups;

 

  • Metals:

– All are solids at room temperature (except mercury); and are good conductors of electricity;

 

  • Non-metals;

– Exists as solids and gases;

– All are poor electric conductors except graphite;

 

Examples of elements.

(i). Metals:

– Sodium, magnesium, potassium, aluminium, lead, iron, zinc, silver, gold, tin, platinum, uranium, calcium, manganese etc.

 

(ii). Non-elements.

– Carbon, nitrogen, sulphur, oxygen, chlorine, fluorine, argon, neon, bromine, iodine, silicon, boron, xenon, krypton.

  1. Molecule.

– Is the smallest particle of a substance that can exist independently;

– It is made when 2 or more atoms (similar or dissimilar) are chemically combined together;

– However atoms of noble/ inert gases exist as single atoms;

 

Note:

– Depending on number of atoms molecules can be categorized into:

(i). Monoatomic molecule;

– made up of only one atom;

Examples:
– Argon;

Argon atom     Argon molecule;

– Neon;

– Helium;

 

(ii). Diatomic molecules.

– Made up of 2 similar atoms; chemically combines;

Examples

– Oxygen gas;

  Oxygen atom                Oxygen molecule;

– Nitrogen gas;

– Hydrogen gas;

– Chlorine gas;

 

(ii). Triatomic molecules.

– Made up of 3 similar atoms; chemically combines;

Examples

– Ozone molecule;

 

  Oxygen atom                Ozone molecule;

 

Note:

– Other molecules are also made from atoms of different elements chemically combined together;

Examples:
(i). Hydrogen chloride;

+        →

Hydrogen   Chlorine        Hydrogen chloride molecule;

           Atom.        Atom;

 

(ii). Water molecule;

+        +                     →

               

          Hydrogen atoms     oxygen atom;                      Water molecule;

 

 

 

 

 

 

  1. Compounds.

– A compound is a pure substance consisting of two or more elements that are chemically combined.

– Compounds usually have different properties from those of its constituent elements;

– Properties of a compound are uniform throughout any given sample and from one sample to another;

 

Examples of compounds and their constituent elements.

 

Compound Constituent elements
Colourless water liquid; Oxygen and hydrogen;
Green copper (II) carbonate; Copper, carbon and oxygen;
White sodium nitrate; Sodium, nitrogen and oxygen;
Black copper (II) oxide; Copper and oxygen;
Blue copper (II) nitrate; Copper, nitrogen and oxygen;
Blue copper (II) sulphate; Copper, sulphur, oxygen and hydrogen;
Ammonium chloride; Nitrogen, hydrogen and chlorine;

 

Note:

– Carbonates are derivatives of (derived from or made of) carbon and oxygen;

– Nitrates are derivatives of nitrogen and oxygen;

– Sulphates are derivatives of sulphur and oxygen;

– Hydrogen carbonates are derivatives of hydrogen, carbon and oxygen;       

 

  1. Mixtures

– A substance that consists of two or more elements or compounds that are not chemically combined.

 

Characteristics of mixtures.

– It properties are the average of the properties of its elements;

– Its components can be separated by physical means e.g. filtration, magnetism, distillation etc.

– Its components are not necessarily if fixed positions;

– Are formed by physical means; i.e. there is usually no heat change during its formation.

 

Examples of mixtures:
1. Air:

– A mixture of oxygen, nitrogen, carbon (IV) oxide, water vapour, and noble gases.

 

  1. Sugar solution.

– A mixture of sugar and water.

 

  1. Sea water.

– Water, dissolved salts;

 

Experiment: To distinguish between an element and a compound.

(i). Apparatus.

– Watch glass, test tube, wooden splint, magnet, iron fillings, sulphur powder, dilute hydrochloric acid.

 

(ii). Procedure.

– Approximately 7g of iron fillings and 4g of sulphur are mixed in a test tube and the mixture strongly heated;

 

 

Observations:
– A red glow starts and spreads throughout the mixture forming a black solid.

– The black solid is iron (II) sulphide.

– The two products // substances in steps 1 and 2 are subjected to the following tests;

 

Test // Analysis Observations
Iron-sulphur mixture. Iron (II) sulphide
1. Colour: The colour of the substance is noted; – The resultant substance is yellow-grey due to the yellow sulphur and the grey iron powder; – The yellow-grey mixture changes to a black solid; iron (II) sulphide on heating;
2. Separation: A magnet is passed over the substances separately;

– Alternatively, water was added to each substance;

– Before heating the iron could be separated from sulphur by use of a magnet or sedimentation;

Note: These are physical methods;

– Magnetism and sedimentation have no effect on iron (II) sulphide;
3. Reaction with dilute hydrochloric acid: To each of the substances, a few drops of hydrochloric acid is added; – Iron reacted with dilute hydrochloric acid to form a colourless gas that burns with a pop sound.

– This is hydrogen gas;

– Sulphur is not affected;

– Iron (II) sulphide reacted with hydrochloric acid to produce a colourless gas with a characteristic pungent (rotten egg) smell;

– The gas is hydrogen sulphide;

4. Heat change. No heat was produced  or applied in mixing iron and sulphur; – After heating the mixture, the formation of the new substance, iron (II) sulphide produced enough heat hence the bright red glow;

 

Explanations:
– These four experiments summarize the four main differences between compounds and mixtures.

– From the results, iron and sulphur powder is a mixture; while iron (II) sulphide is a compound.

 

Differences between a mixture and a compound.

Compounds Mixtures
1. Components are in fixed positions; – Components are in any positions;
2. Components can only be separated by chemical means; which require large amounts of energy; – Components ca be separated by physical means;
3. The properties are different from those of the constituent substances; – The properties are the average of the properties of the constituent elements;
4. Are formed by chemical means // methods; i.e. a new substance is formed and there is evolution of heat; – Are formed by physical mans; no new substance is formed and there is no // negligible heat change;
5. Formation involves heat changes; either liberation or absorption; – No heat change in the formation of a mixture;

 

Names and symbols of common elements.

Chemical symbols.

– Are chemical short hands, written to refer to elements.

– They are usually based on the letters of the element;

– Chemical symbols consist of one or two letters which are usually derivatives of the Latin or English name of the element;

 

Rules in writing chemical symbols.

  1. The first letter must always be a capital letter;
  2. The letters should not be joined with each other, like in handwriting; they must be printed.
  3. If present, the second letter of a symbol must be a small letter;

 

Note: The abbreviations of the chemical symbols are mainly derivatives of English, Latin or German names.

Examples:

Copper is ymbolised as Cu; derived from Cuprum which is ltin;

  • Iron; → Fe (Ferrum –Latin)
  • Potassium; → K (Kalium –Latin)
  • Sodium; → Na (Natrium –Latin)
  • Lead; → Pb (Plumbum –Latin);

– The symbol of each element represents one atom of that element.

Example:
Ag represents one atom of silver;

– 2Ag represents 2 atoms of silver;

 

Some common elements and their symbols.

Element Latin // Greek // German name Symbol
Carbon

Fluorine

Hydrogen

Iodine

Nitrogen

Oxygen

Phosphorus

Sulphur

Aluminium

Argon

Barium

Calcium

Chlorine

Helium

Magnesium

Neon

Silicon

Zinc

Copper

Iron

Lead

Mercury

Potassium

Silver

Sodium

Gold

Tin

Manganese

Cuprum

Ferrum

Plumbum

Hydagyrum

Kalium

Argentum

Natrium

Aurum

C

F
H
I

N

O

P

S
Al

Ar

Ba

Ca
Cl

He

Mg

Ne

Si

Zn

Cu

Fe

Pb

Hg

K

Ag

Na

Au

Sn

Mn

 

Importance of chemical names and symbols over common names.

  1. Chemical names and symbols indicate the names in the compounds.

Examples:
– Compounds whose names end in  -ide; contains only two elements;

  • Iron (II) sulphide: iron and sulphur;
  • Magnesium nitride: magnesium and nitrogen;

– Compounds whose names end in –ate contain three elements and oe of them is oxygen;

  1. Chemical names are universally known and accepted; hence provide mean of easy communication among chemists all over the world;

Simple word equations.

Equations:

– Is a linear summary of a chemical reaction, showing the reactants and products.

Examples:
Copper (II) oxide + hydrogen → copper + water;

 

Explanations:
– Substances on the left hand side are called reactants;

– Substances on the right hand side are called products;

– The addition sign (+) on the left hand side means “reacts with”;

– The arrow (→) means to form;

– The addition sign (+) on the right hand side (products side) means “and”.

 

Conclusion:

Copper (II) oxide reacts with hydrogen to form copper and water;

 

Note:
– Some chemical reactions are reversible and hence have two opposite arrows (                  ) between reactants and products

– The arrows (                    ) in chemistry means a reversible chemical reaction;

 

Further examples:
1. Copper (II) carbonate → Copper (II) oxide + carbon (IV) oxide;

  1. Magnesium + oxygen → magnesium oxide;

 

 

UNIT 3: ACIDS BASES AND INDICATORS.

Unit checklist

  1. Acids:
  • Meaning of acids;
  • Organic acids
  • Mineral acids;
  1. Bases.
  • Meaning;
  1. Indicators.
  • Meaning;
  • Preparation of acid-base indicators;
  • Commercial acid-base indicators;
  • Colour of indicators in acids and bases;
  • Classifications of substances as acids or bases using acid base indicators;
  • The universal indicator;
  • The pH scale;
  • pH values of various solutions in universal indiactor;
  1. Properties of acids.
  • Physical properties;
    • Taste;
    • Effect on litmus papers;
    • Electrical conductivity;
  • Chemical properties.
    • Reaction with alkalis and bases;
    • Reaction with metals;
    • Reaction with carbonates and hydrogen carbonates;
  1. Properties of bases
  • Physical properties;
    • Taste;
    • Texture;
    • Effect on litmus papers;
    • Electrical conductivity;
  • Chemical properties.
    • Reaction with acids;
    • Precipitation of some hydroxides;
    • Effect of heat
  1. Uses of some acids and bases.

 

  1. Acids:

– Are substances that dissolve in water to release hydrogen ions.

– Acids can either be organic acids or mineral acids;

 

(i). Organic acids:

– Are acids found in plants and animals;

Examples:
– lactic acid in sour milk;

– Citric acid in citrus fruits like oranges;

– Ethanoic acid in vinegar;

– Tartaric acid in baking powder;

– Methanoic acid in bee and ant stings;

– Tannic acid in tea;

 

(ii). Mineral acids.

– Are acids made from minerals containing elements such as sulphur, chlorine, nitrogen etc.

– Are formed from reactions of chemicals;

– Main examples include:

  • Sulphuric (VI) acid (H2SO4); contains hydrogen, sulphur and oxygen;
  • Hydrochloric acid; contains hydrogen and chlorine;
  • Nitric (V) acid (HNO3); contains nitrogen, oxygen and hydrogen;

Note:
– Mineral acids are more powerful than organic acids; because they yield // release more hydrogen ions in water

– They are thus more corrosive.

  1. Bases.

– Are substances that dissolve in water to yield // release hydroxyl ions;

– Just like acids they are bitter to taste;

Examples:
– Sodium hydroxide;

– Ammonium hydroxide;

– Calcium hydroxide;

Note:
– Some bases insoluble in water while some are soluble in water;

– Soluble bases are called alkalis;

 

  1. Indicators.

– Are substances which give definite colours in acidic or basic solutions;

– Are substances which can be used to determine whether a substance is an acid or a base;

– Consequently they are called acid-base indicators;

– The determination is based on colour changes, where each indicator have particular colourations in acids and bases.

– Indicators can be commercially or locally prepared in the laboratory;

 

 

 

 

 

Indicators:

Experiment: preparation of simple acid-base indicators from flower extracts.

(i). Apparatus and chemicals.

– Test tubes;

– Pestle and mortar;

– Flower petals;

– Ethanol // propanone;

– Water;

– Various test solutions: sulphuric (VI) acid, hydrochloric acid, Ethanoic acid, sodium hydroxide, magadi soda, ammonia solution.

 

(ii). Procedure:
– Flowers from selected plants are collected and assembled e.g. bougainvillea, hibiscus etc;

– They are crushed in a mortar using a pestle and some ethanol added with continued crushing;

– The resultant liquid is decanted into a small beaker; and its colour recorded.

– Using a dropper, two to three drops of the resultant indicator are added to the test solutions.

 

(iii). Observations:
(a). Colour of extract in acids and bases

 

Plant extract Colour in hydrochloric acid Colour in dilute sodium hydroxide
1    
2    

 

(b). Result with various test solutions:

Test substance Colour (change) Type of substance (acid/base)
Lemon juice

Wood ash

Ammonia

Sour milk

Vinegar

Nitric (V) acid

Toothpaste

Lime water

Baking powder;

Sugar

Potassium hydroxide

   

 

Note:

– Plant extracts acid-base indicators are not normally preferred in Chemistry experiments.

Reason:

– They don’t give consistent (reproducible results because they are impure.

– Commercial indicators give more distinctive and reproducible results.

 

 

 

 

Commercial indicators.

– Are commercially prepared indicators which are sold in already purified forms.

 

Advantages of commercial indicators.

– They are relatively pure hence give consistent and reproducible results;

– They are readily available and easy to store in a Chemistry laboratory;

 

Main examples:
– Phenolpthalein;

– Methyl orange;

– Bromothymol blue;

– Litmus paper;

 

Note:
– Litmus is a blue vegetable compound which is extracted from “plants” called lichens;

– Litmus paper is an adsorbent paper which has been dipped in litmus indicator solution then dried;

 

Colours of various commercial indicators in acids and bases.

Indicator Colour in.
Neutral Base Acid
1. Litmus;

2. Phenolphthalein;

3. Methyl orange;

4. Bromothymol blue

Purple

Colourless;

Orange

Blue

Blue;

Pink;

Yellow

Blue

Red;

Colourless;

Pink;

Yellow;

 

Classification of various substances as acids or bases using indicators.

Substance Colour in Classification
Litmus Phenolphthalein Methyl orange Bromothymol blue
Hydrochloric acid

Sodium hydroxide

Omo (detergent)

Soda

Actal tablets

Lemon juice

Sour milk

Bleach (jik)

Fresh milk

Wood ash

         

 

The universal indicator.

– Is a full range indicator which gives range of colours depending on the strength of the acid or alkali.

– It is prepared by suitable mixing certain indicators;

– It gives a range of colour depending on the strength of acids and bases;

– Each universal indicator is supplied with a chart, to facilitate this classification.

 

 

 

 

 

 

The pH scale.

– Is a scale of numbers which shows the strength of acids or bases.

– It refers to the potential (power) of hydrogen;

– It ranges from 0 – 14;

– To determine the strength of an acid or base, the colour it gives in universal indicators solution is compared to the shades on the pH chart of the indicator;

 

Diagram: The pH scale.

 

 

 

 

 

Note:
– The strongest acid has a pH of 1;

– The strongest alkali has a pH of 14;

– Neutral substances have a pH of 7;

– Any pH less than 7 is acidic solution; while any pH above 7 is for a alkaline / basic solution;

 

Colour and pH of various solutions in universal indicator;

Substance Colour pH on chart Classification
Hydrochloric acid

Sodium hydroxide

Omo (detergent)

Soda

Actal tablets

Lemon juice

Sour milk

Bleach (jik)

Fresh milk

Wood ash

     

 

Properties of acids.

(a). Physical properties.

  1. They have a sour taste.

Examples:
– The sour taste of citric fruits is due to the citric acid in them.

– The sour taste in sour milk is due to lactic acid;

 

  1. They turn blue litmus to red;

– Red litmus will remain red in acidic solution; blue litmus will turn red;

 

  1. Electrical conductivity;

– Acids conduct electric current when dissolved in water;

– This is because they dissolve in water to release hydrogen ions; which are the ones that conduct electric current;

 

  1. Thy destroy clothing when strong; i.e. they at away clothing material leaving holes in it;

 

  1. Strong acids are corrosive; hence able to burn plant and animal tissues;

Chemical properties.

  1. Reaction with alkalis ad bases.

– Acids react with alkalis to form salt and water only;

– These types of reactions are called neutralization reactions;

– The hydrogen ions of the acid react with the hydroxyl ion of the alkali to form water;

– The name of the salt is usually derived from the acid;

Examples:

Acid Derivative salt
Sulphuric (VI) acid

Hydrochloric acid

Nitric (V) acid

Phosphoric acid

Sulphates;

Chlorides

Nitrates;

Phosphates;

 

Summary:

Acid + base (alkali) → salt + water; (a neutralization reaction);

Examples:
1. Sodium hydroxide + Hydrochloric acid → Sodium chloride + water;

  1. Calcium oxide + Sulphuric (VI) acid → calcium sulphate + water;

 

  1. Reaction with metals;

– Acids react with some metals to produce hydrogen;

 

Examples: Reaction with dilute hydrochloric acid and zinc metal;

Procedure:

– 2 cm3 of hydrochloric acid is put in a test tube;

– A spatula end-full of zinc powder is added.

– A burning splint is lowered in the test tube.

 

Observations.

– Effervescence of a colourless gas;

– The colourless gas burns with a pop sound;

 

Explanations.

– Zinc metal displaces the hydrogen ions in the acid which form the hydrogen gas;

– When a glowing splint is introduced into the hydrogen gas; it burns with a pop sound;

– This is the chemical test to confirm that a gas is hydrogen;

 

Conclusion;

– The gas produced is hydrogen gas;

– Thus, acids react with some metals to produce hydrogen gas, and a salt;

 

General equation:

Metal + Dilute acid → salt + Hydrogen gas;

 

Reaction equation:

Zinc + Hydrochloric acid → Zinc chloride + Hydrogen chloride;

 

Further examples:
i. Magnesium + Dilute sulphuric (VI) acid → magnesium sulphate + hydrogen gas;

  1. Magnesium + Dilute Hydrochloric acid → magnesium chloride + Hydrogen gas;

 

  1. Reaction with carbonates and hydrogen carbonates.

– Metal carbonates and hydrogen carbonates react with acids to form carbon (IV) oxide, water and a salt;

 

General equation:
Metal carbonate + Dilute acid → A salt + water + carbon (IV) oxide;

Metal hydrogen carbonate + Dilute acid → A salt + water + carbon (IV) oxide;

 

Examples: Reaction of sodium carbonate with dilute hydrochloric acid.

Procedure:

– About 2 cm3 of dilute hydrochloric acid is put in a test tube;

– A spatula end-full of sodium carbonate powder is then added;

– A burning splint is carefully lowered into the test tube.

 

Apparatus.

Observations.

– An effervescence occurs (bubbles); and a colourless gas is produced;

– The colourless gas does not relight a glowing splint; showing that it is carbon (IV) oxide;

 

Properties of bases.

Note:

– Bases are substances that release hydroxyl ions when added to water;

– Soluble bases are called alkalis;

 

Examples:
Sodium hydroxide + Water → Sodium ions + hydroxyl ions;

 

(a). Physical properties of bases

  1. They are bitter to taste;
  2. They are slippery or soapy to feel;
  3. They turn litmus blue;
  4. They conduct electricity / electric current. This is because when they are added to water they release hydroxyl ions which are the ones that conduct electricity;

 

(b). Chemical properties.

  1. Reaction with acids.

– They react with acids to form a salt and water as the only products;

– This is a neutralization reaction; and is used to cure indigestion;

 

Example:
– Actal tablets contain a base that neutralizes the stomach acid.

 

  1. They precipitate some metal hydroxides.

– Addition of some alkalis to salt solutions results in formation of solids;

– Most of these are normally hydroxides;

– A solid that is formed when two solutions are mixed is called a precipitate;

 

Example:

– Copper (II) sulphate + Sodium hydroxide → Copper (II) hydroxide + Sodium sulphate solution;

Blue solid;

 

  1. Effects of heat.

– Most metal hydroxides are decomposed by heat to form their oxides and water;

 

Heat

General equation:
Metal hydroxide                 Metal oxide + Water;

 

Example:
Zinc hydroxide → Zinc oxide + water;

 

Applications of acids and bases.

Application of acids

  1. Manufacture of aerated drinks;
  2. Cleaning metal surfaces to remove oxide layer;
  3. Sulphuric (VI) acid is used in car batteries to store and produce electricity;
  4. Treatment of some insect bites.

Examples:
– Wasp and bee stings can be treated by applying vinegar (Ethanoic acid) or lemon juice;

– These acidic substances neutralize the alkaline insect stings;

 

Uses of bases.

  1. Manufacture of anti-acid tablets to neutralize acid indigestions e.g. actal;
  2. Calcium oxide ad calcium chloride are used to dry gases in the laboratory;

 

UNIT 4: AIR AND COMBUSTION.

Checklist.

  1. Components
  2. Determination of percentage of the active part of air.
  • Burning candle.
  • Heating copper turnings;
  • Heating magnesium turnings.
  • Smouldering of white phosphorus.
  • Rusting of iron;
  1. Determination of presence of water and carbon (IV) oxide in water.
  2. Fractional distillation of liquid air.
  3. Rusting
  • Meaning and formula;
  • Conditions necessary for rusting;
  • Prevention of rusting;
  1. Oxygen
  • Laboratory preparation of oxygen gas;
  • Chemical test for oxygen gas;
  • Alternative methods of oxygen preparation;
    • Addition of water to solid sodium peroxide;
    • Heating potassium manganate (VII) solid.
  • Use of oxygen
  1. Burning substances in air;
  • Changes in mass;
  • Burning substances in oxygen;
    • Metals;
    • Non-metals;
  • Reactivity series;
  1. Competition for oxygen among metals;
  2. Applications for the competition for oxygen;
  3. Atmospheric pollution.

 

Introduction:

– Air is a gaseous mixture constituted of several gases, water vapour and pollutants.

 

Combustion:

– Is the burning of substances, usually in presence of air // oxygen;

– During combustion only the oxygen component of air is used; .e the active part of air.

 

Percentage composition of air.

Component Percentage volume.
Nitrogen 78%
Oxygen 21%
Carbon (IV) oxide 0.03%
Noble gases (argon) About 1%
Water vapour Variable
Smoke/dust particles Variable;
Others Trace

 

Note:

– From the noble gases argon is the most abundant, constituting about 0.93% of the entire 1%

 

Oxygen and combustion.

– When substances burn in air they consume oxygen.

– Thus the process of combustion utilizes mainly oxygen;

– The reactions in combustion are normally exothermic (give out heat) and often involve flame.

Note:

Combustion in which a flame is used is called burning;

– In combustion if all the oxygen in a given volume of air is used, the final volume of air reduces by about 21.0%;

– Since oxygen is the only constituent of air participating in combustion its termed the active part of air.

 

Experiments: Determination of the active part of air.

  1. Burning candle in air.

Apparatus and requirements.

– Candle;

– Cork / evaporating dish;

– Sodium hydroxide solution;

 

Procedure:

– A candle about 3cm long is put on a wide cork/ evaporating dish;

– It is then floated in a dilute solution of sodium hydroxide solution just above the beehive shelf;

– It is carefully covered with a dry 100cm3 measuring cylinder, during which the level of solution in the cylinder is noted and marked;

– The measuring cylinder is removed and the candle lit;

– The lighting candle is then covered with a measuring cylinder;

– The experiment is allowed to proceed until the candle goes off;

 

 

 

Observations:

– The candle went off after sometime;

– The sodium hydroxide level inside the gas jar rises;

– The sodium hydroxide level in the trough goes down;

 

Diagrams:

 

 

 

 

 

 

 

 

 

Explanations:
– The candle wax is made up of hydrogen and carbon, hence called a hydrocarbon;

– During burning it melts in air consuming oxygen and producing carbon (IV) oxide and water vapour;

– The water vapour condenses giving a negligible volume of water;

– The resultant carbon (IV) oxide is absorbed by the sodium hydroxide;

– Absorption of carbon (IV) oxide in the gas jar creates a partial vacuum within it;

– The sodium hydroxide in the trough rises to fill the resultant space; and hence a drop in the sodium hydroxide level in the tough;

 

Conclusion.

– Oxygen is the active part of air that is utilized during burning;

– Air is basically made up of 2 parts; an active part that supports burning and an inactive part that does not support burning;

 

  1. Quantitative determination of percentage of oxygen in air.

Apparatus and chemicals.

– Tough;

– Beehive;

– Candle and gas jar;

– A 30ml ruler;

– Sodium hydroxide solution;

 

Procedure:

– The entire apparatus is arranged as shown below;

– An empty gas jar is inverted over the candle before lighting it;

– The initial height A, is measured and recorded;

– The gas jar is then removed; the candle lit and covered with the gas jar again;

– The set up is allowed to run till the candle extinguishes (goes off); and the final height (B) of the air column measured.

 

 

 

 

 

Diagrams

 

 

 

 

 

 

 

 

 

 

Calculations:
– Amount of air in the gas jar initially = A cm3;

– Final amount of air remaining after burning; = Bcm3;

– Amount of oxygen used; = (A – B)

Thus;

Percentage of oxygen in air: = (A – B) x 10

A

= C%

Sample data:
Volume of air in the gas jar before burning =

Volume of air in the gas jar after burning =

Volume of air used during burning =

Percentage of air (by volume) used up = Volume used in burning x 100

Original (initial) volume

Substituting:

 

 

 

Conclusion:
– When candle burns in air, about 20% of air, which is oxygen used up;

 

  1. Determination of percentage of air used up in rusting.

Apparatus:
– Gas jar;

– Trough;

– Beehive;

– Iron fillings//powder

 

Procedure:
– The gas jar is divided into five equal portions by marking around it using a waterproof marker;

– The gas jar is wet near the bottom and some iron fillings sprinkled on it;

– Some water is put in a trough and the jar with iron fillings // wool // powder inverted over it;

– The initial colour of iron fillings is noted;

– The set up is left undisturbed for a few days until the water shows no further change in rising;

 

 

 

 

Diagrams of apparatus set up:

 

 

 

 

 

 

 

 

Observations:
– The iron fillings change colour from a grey to form a brown solid;

– Water level in the gas jar rises // increases until the first mark in the gas jar;

– The water level in the trough decreases;

 

Explanations:
– The gas jar is moistened to make the iron fillings stick onto its surface so that the fillings do not fall in the water when the gas jar is inverted;

– The brown substance formed is called rust and its chemical name is hydrated iron (III) oxide;

– During rusting, oxygen is utilized, thus creating a partial vacuum in the gas jar;

– This causes the water level in the gas jar to rise up and the water level in the trough to go down;

– The rise in water level is equivalent to about 1/5 of the original air volume, which translates to about 20%;

 

Conclusion:
– When rusting occurs about 20% of air, which is oxygen, is used up;

 

  1. Determination of percentage of air used up when air is passed over heated copper.

Apparatus and chemicals.

– Two 100cm3 syringes labeled Y and Y;

– Hard glass test tube;

– Glass wool’;

– Bunsen burner;

– Copper turnings;

 

Procedure:

– A small amount of copper turnings is put in a hard glass tube and glass wool put at both ends of the tube;

– All the air in the syringe Y is removed by pushing the plunger inside, upon which the syringe is tightly fixed at one end of the tube// glass tube;

– The plunger of syringe Z is pulled out to the 100cm3 mark; to fill it with air.

The apparatus is arranged as below.

 

Diagram:

 

 

 

 

 

 

– The tube containing copper turnings is strongly heated;

– Air is then passed over the hot copper turnings by slowly pushing the plunger Z to and fro for several times.

Reason:

– Ensure complete reaction between the hot copper turnings and oxygen (air);

 

– When no further air change in volume of air in the syringe occurs, the apparatus is allowed to cool;

– The volume of air left in syringe Z is recorded;

 

Observations:
– The brown solid (copper) turns into a black solid (copper (II) oxide);

– The plunger of syringe Z moves inwards to approximately 80 cm3 mark;

 

Explanations:
– The heated copper reacted with oxygen in air to form black copper (II) oxide;

– The percentage of oxygen that was in the air is approximately 20%, causing the plunger to move inwards to the 80 cm3 mark;

 

Equation:

Copper + Oxygen → Copper (II) oxide;

 (Brown)          (Colourless)              (Black)

 

2Cu(s) + O2(g) → 2CuO(s)

Brown      (Colourless)    (Black)

 

Conclusion:

– Burning of copper in air utilizes oxygen and produces black copper (II) oxide.

 

Sample results and calculations:

– Initial air volume in syringe Z = cm3;

– Final air volume in syringe Z = cm3;

– Volume of air used = (100 – 80) = 20 cm3;

Percentage of oxygen in air = 20 x 100 = 20%;

100

 

  1. Determination of percentage of air used up when air is passed over heated Magnesium.

– When the same set up is used to investigate the percentage of air used up in combustion of magnesium the volume of air used up is relatively higher than the 20%.

Reason:

Magnesium produces a lot of heat during combustion and thus reacts with both oxygen and nitrogen to form two products; magnesium oxide and magnesium nitride respectively;

 

Observations:

– Magnesium glows giving a bright blinding flame;

– Formation of a mixture of two white powders.

 

 

 

 

Equations:

Reaction with oxygen:

Magnesium + Oxygen → Magnesium oxide;

       (Grey)                (Colourless)                      (White)

 

2Mg(s) + O2(g) → 2MgO(s)

(Grey)         (Colourless)      (White)

 

Reaction with nitrogen:

Magnesium + Nitrogen → Magnesium nitride;

       (Grey)                (Colourless)                      (White)

 

3Mg(s) + N2(g) → Mg3N2(s)

(Grey)         (Colourless)      (White)

 

Note:

– Sodium metal will also react with both oxygen and nitrogen during combustion; forming sodium oxide and sodium nitride respectively;

 

  1. Smouldering of white phosphorus.

Apparatus and requirements.

– Graduated measuring cylinder;

– Water tough // pneumatic trough;

– Copper wire;

– White phosphorus;

 

Procedure:
– An empty measuring cylinder is inverted in a water trough and the water level noted;

– A small piece of white phosphorus is attached to the end of a piece of copper wire then put // inserted into the inverted measuring cylinder ensuring it is above the water;

– The set up is left undisturbed for 24 hours;

 

Precaution:

– Avoid contact with the phosphorus;

– Avoid inhalation of the fumes;

 

Observations:

– White fumes inside the cylinder at the start of the experiment;

– After 24 hours:
– water level inside the measuring cylinder rises;

– Water level in the trough drops;

 

Explanations:
– Yellow or white phosphorus smoulders in air; due to the fact that phosphorus reacts with oxygen to form phosphorus oxides;

-The phosphorus oxides are the white fumes;

– The phosphorus oxides then dissolves in water; forming acidic solutions of phosphoric acids;

– The water level rises inside the cylinder to occupy the volume of oxygen used up in reaction with phosphorus;

 

Equations:

Phosphorus + Oxygen → Phosphorus (V) oxide

White // yellow            Colourless              White fumes

 

P4(s) + 5O2(g) → 2P2O5(g);

White   Colourless              White fumes

Yellow

 

Phosphorus + Oxygen → Phosphorus (III) oxide

White // yellow            Colourless              White fumes

 

P4(s) + 3O2(g) → 2P2O3(g);

White   Colourless              White fumes

Yellow

 

Conclusion:

– Phosphorus smolders easily in air, reacting with oxygen (active part of air) to form phosphorus (III) or phosphorus (V) oxide;

– For this reason phosphorus is stored under water; to prevent it from reacting with atmospheric oxygen;

 

Note:
– This reaction can be made much faster by heating the copper wire; which will transmit heat to the piece of phosphorus at the tip, causing rapid burning of phosphorus to give dense white fumes of phosphorus (V) oxide // phosphorus (III) oxides;

 

Test for evidence of some components of air.

  1. Water vapour.

(i). Formation of dew;

 

(ii). When white anhydrous copper (II) sulphate is left in the open overnight; it forms a blue solid of hydrated copper (II) sulphate;

Reason:
– The white anhydrous copper (II) sulphate absorbs atmospheric water vapour;

– Upon hydration the copper (II) sulphate turns blue;

 

(iii). Sodium hydroxide pellets form a colourless solution when left in the open air overnight.

Reason:

– The sodium hydroxide pellets absorbs atmospheric water vapour and dissolves in it forming sodium hydroxide solution;

 

(iv). When air is passed through anhydrous calcium hydroxide solid in a U-tube for sometime; there is formation of a colourless solution in the U-tube.

Apparatus:

 

 

 

 

 

 

 

Reason:

– The anhydrous calcium chloride absorbs atmospheric water vapour forming a colourless solution of calcium chloride;

 

Equation:

Calcium chloride + water → calcium chloride solution;

White                                                                     Colourless solution;

 

Note:
– Substances that absorb moisture from the air to form a colourless solution are called deliquescent substances.

– Other examples of deliquescent substances include: iron (III) chloride, magnesium chloride and zinc chloride;

 

  1. Carbon (IV) oxide.

(i). Glass stoppers of reagent bottles containing sodium hydroxide solution tend to stick when left on for sometime in the laboratory;

Reason:

– The sodium hydroxide solution at the edges of the stopper is exposed to air; and thus reacts with atmospheric carbon (IV) oxide forming white sodium carbonate solid.

 

Equation:
Sodium hydroxide + Carbon (IV) oxide → Sodium carbonate + Water;

2NaOH(aq) + CO2(g) → Na2CO3(s) + H2O(l);

 

(ii). Bubbling atmospheric air through lime water (calcium hydroxide) to form a white insoluble salt of calcium carbonate.

 

Apparatus:

 

 

 

 

 

 

 

 

 

 

Reason:

– Atmospheric carbon (IV) oxide reacts with limewater (calcium hydroxide) to form a white insoluble precipitate of calcium carbonate salt;

 

Equation:
Calcium hydroxide + Carbon (IV) oxide → Calcium carbonate + Water;

 

Ca(OH)2(aq) + CO2(g) → CaCO3(s) + H2O(l);

 

 

Note:

– When the air is bubbled on even after the formation of the white precipitate; the white precipitate dissolves after sometime to form a colourless solution;

Reason:

– Excess carbon (IV) oxide reacts with the calcium carbonate to form soluble calcium hydrogen carbonate.

 

Equation:

Calcium carbonate + Water + Carbon (IV) oxide → Calcium hydroxide solution;

CaCO3(s) + H2O(g) + CO2(g) → Ca(HCO3)2(aq);

 

Fractional distillation of Liquefied air.

– Air is a mixture of gases;

– It can be separated into its constituents by fractional distillation of liquid air.

– During the process air is passed through a series of steps during which it is purified, some components eliminated then it is compressed into liquid prior to fractional distillation.

– The process can be divided into two main stages;

Purification and liquefaction;

Fractional distillation of air;

 

(a). Purification and liquefaction.

Step 1: Purification:
– The air is purified by removal of dust particles ;

– This is done through the following ways:

  • Passage through filters; during which air is passed through a series of filters; the dust particles remain within the filters while dust free air passes on to the next stage;
  • Electrostatic precipitation where air is passed through charged electrodes which trap oppositely charged dust particles;

 

Step 2: Removal of carbon (IV) oxide.

– The dust-free air is passed through a chamber containing calcium hydroxide solution;

– The sodium hydroxide solution dissolves the carbon (IV) oxide present in the air;

– During the reaction, sodium carbonate and water are formed;

– Over a prolonged time; the sodium carbonate absorbs more (excess) carbon (IV) oxide forming sodium hydrogen carbonate;

 

Equations:

Sodium hydroxide + carbon (IV) oxide → Sodium carbonate + Water;

2NaOH(aq) + CO2(g) → Na2CO3(aq) + H2O(l);

 

In excess;

Sodium carbonate + Water + Carbon (IV) oxide → Sodium hydrogen carbonate;

Na2CO3(aq) + H2O(l) + CO2(g) → 2NaHCO3(aq);

 

 

 

 

 

Step 3: Removal of water vapour;

– The dust-free, CO2 – free air is then cooled to -25oC;

– This process solidifies the water vapour out as ice;

– This cooling process may be done at temperatures a s low as -80; so as to solidify any carbon (IV) oxide (freezing point -78oC) that may have escaped absorption by the sodium hydroxide;

– The removal of water vapour and carbon (IV) oxide are important because it prevents blockage of the pipes in the rest of the system;

 

Step 4: Liquefaction of air;

– The dry, dust-free and carbon (IV) oxide-free air is compressed to about 100 atmospheres of pressure; causing it to warm;

– The compressed air is cooled by refrigeration;

– The cold compressed air is made to expand rapidly by passage through a nozzle which cools it further;

– The repeated compression, cooling and expansion of air causes it to liquefy at about -200oC:

Note:
At this temperature only neon and helium whose boiling points re lower than -200oC remain in gaseous states;

 

(b). Fractional distillation;

– The liquid air now consists only of nitrogen, oxygen and noble gases (especially argon);

– The liquid air is fed at the bottom of a fractionating column;

– It is warmed to a temperature of -192oC;

-Nitrogen distils over fast at -196oC because it has a lower boiling point; and is collected at the top of the fractionating column;

Note:

– Any vapours of oxygen and argon which rise together with nitrogen vapour condense in the column and fall back as liquids;

– The nitrogen collected is 99% pure;

The small amounts of impurities include neon and helium;

– The liquids remaining at the bottom of the fractionating column after vaporization of all nitrogen is mainly oxygen and argon; with traces of krypton and xenon;

 

– The liquid is again warmed further to a temperature of -185oC; causing the vapourization of argon whose boiling point is -186oC;

– This is collected as a gas at the top of the fractionating column;

– The residue liquid is mainly oxygen with minute quantities of krypton and xenon which have even high boiling points;

– The oxygen is drained off and stored as pressurized oxygen in steel cylinders;

 

Uses of the products:

Oxygen;

– Used in hospitals with patients with breathing difficulties;

– It is used by mountain climbers and deep-sea divers for breathing;

– It is used to burn fuels;

– It is combined with acetylene to form oxy-acetylene flame which is used in welding;

– During steel making oxygen is used to remove carbon impurities;

 

 

Nitrogen:

– Manufacture of ammonia;

– Used in light bulbs; because of its inert nature it dies not react with the filament;

– As a refrigerant e.g. storage of semen for artificial insemination;

 

Rusting.

– Is the corrosion of iron in presence of oxygen and moisture to form brown hydrated iron (III) oxide;

– The chemical name rust is therefore hydrated iron (III) oxide with the formula Fe2O3.2H2O;

– Rust itself is a brown porous substance;

 

Disadvantage of rusting:

– It weakens the structure of the metal (iron) and hence eventually destroys them.

 

Experiment: To show the conditions necessary for rusting.

 

Experiment Procedure Observation Explanation
1 – Two clean iron nails are put inside the test tube;

– 10 cm3 of tap water are then added;

– Examine for two days;

 

– Iron nails turn brown implying there is rusting; – There is presence of both oxygen and water;
2 – Two clean iron nails are added to the test tube;

– 10 cm3 of boiled hot water is added followed by about 3 cm3 of oil;

– Examine for two days;

 

– No rusting occurs; – There is water but no oxygen so no rusting occur;

– Boiling the water removes any dissolved oxygen;

– Addition of the oil on top prevents dissolution // entry of any air containing oxygen into the water;

3 – Two clean iron nails are added to the test tube;

– Push a piece of cotton wool half way the test tube;

– Place some anhydrous calcium chloride on it and cork the tube tightly;

– Examine for two days;

 

– No rusting occurs; – There is no air // oxygen but no water;

– Anhydrous calcium chloride absorbs any moisture form the air in the test tube;

– Corking the tube tightly prevents more moisture from the atmosphere from getting into the tube as the calcium chloride may get saturated and allow moisture into the nails;

4 – Two clean iron nails are added to the test tube;

– Examine for two days;

 

– Some little rusting occurs; – Air contains and oxygen and some moisture that will facilitate rusting;
5 – Two clean iron nails are added to the test tube;

– Add salty water;

– Examine for two days;

Rusting occurs; and at a faster rate than the rest;

 

– Rusting occurs due to presence of both water and oxygen in the salty water;

– Rusting is faster because the salty water contains ions which gain electrons hence facilitate faster oxidation of iron;

 

 

 

 

 

Summary diagrams

 

 

 

 

 

 

 

 

 

 

 

Further explanations:
During rusting the first step is the oxidation of iron b7y xygen (in the air) to form anhydrous iron (III) oxide;

Equation:

Iron + Oxygen → Iron (III) oxide;

 

4Fe(s) + 3O2(g) → 2Fe2O3(s);

 

– The anhydrous ion (III) oxide then undergoes hydration with water to form brown hydrated iron (III) oxide;

Equation:
Anhydrous iron (III) oxide + Water → Hydrated iron (III) oxide.

Black                                                                                Brown;

 

– Rusting occurs faster in salty conditions;

Reason:

– The initial step is the oxidation of iron, from iron (II) ions (Fe2+) to iron (III) ions (Fe3+);

– During oxidation iron (II) ions give out electrons to undergo oxidation and form iron (III) ions;

– Salty water contains several dissolved salts whose ions easily accept electrons from the iron (II) ions and thus accelerating the oxidation of iron and hence rusting;

 

Prevention of rusting.

Note:
– Rusting destroys materials; equipment and roofs made of iron;

– Rust is porous and thus allows air and water to reach the iron beneath.

– Thus if not removed iron will continue corroding until it is all eaten up.

 

Methods of preventing rusting.

  1. Galvanizing.

– Is the coating of iron with a small layer of zinc;

– Can be done by either dipping the iron object in molten zinc, spraying with a spray of molten zinc, or by electroplating (electrolytic deposition);

– On exposure to air the zinc acquires an inert layer of zinc oxide that is impervious to both air and water;

– The iron beneath is thus prevented from air and water and thus rusting.

 

 

Note:
– The iron is protected even if the zinc coating is scratched.

Reason:
– Upon scratching both the iron and zinc get into contact with air and water;

– Since zinc is more reactive than iron, air and water reacts with zinc at the expense (instead) of iron;

 

  1. Electroplating:
    – Refers to electrolytic coating of metals (iron) with less reactive (less corrosive metals);

– This is done through the process of electrolysis where floe of electric current causes the less reactive metal to coat the metal being protected from rusting;

 

Example:

– Most tin cans are in fact made yup of steel coated with a thin layer of tin.

– Other than being non-toxic tin is unreactive and rarely reacts with the contents of the can or air;

Note:

– Unlike in galvanizing, when an electroplated material gets scratched, the metal underneath (iron) rusts, and very fast;

Reason:

– Both iron and the electroplating metal (tin) are exposed to air and water;

– Since iron is more reactive than tin (the less reactive electroplating material) it reacts with oxygen and water in preference to tin;

 

– This explain why galvanization is more durable than electroplating;

– Other less reactive metals that are used to coat iron objects include chromium, silver and gold;

– Some electroplating metals such as gold and silver also increase the aesthetic value of the electroplated object;

 

  1. Sacrificial protection.

– Blocks of a more reactive metal such as zinc or magnesium are attached to the iron structure;

– The more reactive metal will be corroded in preference to iron;

– To keep the iron structure from rusting, the block of reactive metal has to be replaced regularly;

– This metal is used for the protection of underground water pipes as well as ship hulls;

– The blocks of reactive metal are either attached directly to the iron structure or connected to it by a wire.

 

Diagrams:

 

 

 

 

 

 

 

 

 

  1. Painting.

– The paint coats the metal surface and thus prevents contact with air and water hence no rusting;

– However if the paint is scratched, rusting occurs quickly;

– It is used mainly in ion railings, gates, bridges, roofs, ships ad cars;

  1. Alloying.

– Alloys are mixtures of two or more metals;

– Thus to prevent iron from rusting it may be mixed with one o more metals resulting into a substance that does not rust;

Example:

– Stainless steel is an alloy of iron with chromium, nickel and manganese and it resistant to rusting.

 

  1. Oiling and greasing;

– Oil is used in moving engine parts while grease is used I other movable metal joints;

– The oil // grease forms a barrier that prevents water and air from coming into contact with the metal surface and hence preventing rusting;

– Oiling and greasing are unique in the sense that they are the only methods that can be used to prevent rusting in movable car parts;

 

Oxygen.

– A very important constituent of air;

– Lavoisier (1743 – 1794), A French Chemist showed that it is the component of air used in respiration and also in burning fuels;

– It is the most abundant of all elements; occurring both freely as well as in combination with other elements;

– Freely it constitutes about 21% by volume of atmospheric air;

 

Laboratory preparation of oxygen gas.

Apparatus.

– Zinc; round-bottomed // flask bottomed flask; thistle // dropping funnel; rubber stopper, deliver tubes, rubber tubings, beehive shelf, trough, gas jars, wooden splint, hydrogen peroxide (20% by volume), manganese (IV) oxide.

 

Diagram;

 

 

 

 

 

 

 

 

 

 

 

 

 

Procedure.

– Some manganese (IV) oxide is placed into a flat-bottomed flask;

– The apparatus is set up as shown in the diagram above;

– Add hydrogen peroxide from a thistle funnel into the flask dropwise;

– The gas is collected as shown;

 

 

Observations:

– Bubbles of a colourless gas are released from the flask through the water then into the gas jar;

– The colourless gas collects on top of the water;

 

Explanations:
– Hydrogen peroxide decomposes slowly to oxygen and water under normal conditions;

– This process is however slow to collect enough volumes of oxygen;

– On addition of manganese (IV) oxide the decomposition is speeded up;

– Thus manganese (IV) oxide speeds up the decomposition of hydrogen peroxide and thus acts a s a catalyst;

 

Equation:

  • Without a catalyst:

Hydrogen peroxide → Water + oxygen;

2H2O2(l) → 2H2O(l) + O2(g) (slow process)

 

  • With manganese (IV) oxide catalyst:
 Manganese (IV) oxide

 

 

Hydrogen peroxide                              Water + oxygen;

2H2O2(l) → 2H2O(l) + O2(g) (faster process)

 

Note:

The first few bubbles of oxygen gas are not collected.

Reason: The gas is mixed with air which was originally in air and hence impure.

 

Method of collection;

– Over water collection.

Reason:

– It is insoluble in water and less dense than water

 

Physical properties of oxygen gas.

– It is colourless;

– It is odourless;

– Has a low boiling point of about -183oC;

– Almost insoluble in water (hence collected over water);

 

Chemical test for oxygen gas.

– On inserting a glowing splint on a gas jar full of oxygen gas; it relights a glowing splint;

 

Drying of oxygen gas.

– The resultant oxygen is usually moist due to the fact that it is collected over water;

– If required dry the gas ca be died using either of the two methods:

(i). Using sulphuric (VI) acid.

– Bubbling the gas through a wash bottle containing concentrated sulphuric (VI) acid;

– The concentrated sulphuric (VI) acid absorbs moisture from the gas leaving it dry;

– The dry gas is then draw into collection syringe;

 

 

Diagram;

 

 

 

 

 

 

 

 

 

(ii). Using anhydrous calcium chloride.

– From the flask the gas is passed through a U-tube containing anhydrous calcium chloride;

– The anhydrous calcium chloride also absorbs moisture from the gas leaving it dry;

– The dry gas is then drawn into a collection syringe;

 

Diagram:

 

 

 

 

 

 

 

 

 

Alternative methods of oxygen preparation.

  1. Addition of water to sodium peroxide.

Apparatus:
– Sodium peroxide; round-bottomed // flask bottomed flask; thistle // dropping funnel; rubber stopper, deliver tubes, rubber tubings, beehive shelf, trough, gas jars, wooden splint, water;

 

Diagram of apparatus.

 

 

 

 

 

 

 

 

 

 

 

Procedure.

– Some sodium peroxide is placed into a flat-bottomed flask;

– The apparatus is set up as shown in the diagram above;

– Add water from a thistle funnel into the flask dropwise;

– The gas is collected as shown;

 

Observations:

– Bubbles of a colourless gas are released from the flask through the water then into the gas jar;

– The colourless gas collects on top of the water;

 

Explanations:
– Sodium peroxide reacts with water to liberate oxygen;

– A solution of sodium hydroxide remains in the flask;

– This solution will turn litmus paper blue showing it is alkaline.

 

Equation:

Sodium peroxide + water → Sodium hydroxide + oxygen;

2Na2O2(l) + 2H2O(l) → 4NaOH(aq) + O2(g)

 

Note:

The first few bubbles of oxygen gas are not collected.

Reason: The gas is mixed with air which was originally in air and hence impure.

 

Method of collection;

– Over water collection;

Reason:

– It is insoluble in water and less dense than water;

 

Chemical test for oxygen gas.

– On inserting a glowing splint on a gas jar full of oxygen gas; it relights a glowing splint;

 

 

 

 

 

  1. Heating potassium manganate (VII) solid.

Apparatus:
– Ignition tube // boiling tube; means of heating; solid potassium manganate (VII); rubber stopper, deliver tubes, beehive shelf, trough, gas jars, wooden splint, water;

 

Diagram of apparatus.

 

 

 

 

 

 

 

 

 

Procedure:

– The apparatus is set up as shown above.

– Some solid potassium manganate (VII) is put in a hard ignition// combustion tube and strongly heated as shown above.

– The resultant gas is collected over water as shown above.

Observations;

– The purple solid forms a black solid (potassium manganate (II) solid);

– Bubbles of a colourless gas are evolved and collect over water;

 

Explanations:
– Upon heating potassium manganate (VII) decompose to manganese (VI) oxide; potassium

 

Equation:
Potassium manganate (VII) → Potassium manganate (II) + Oxygen gas

KMnO4(s) → KMnO2(s) + O2(g);

 

Uses of oxygen.

  1. Used in hospitals for breathing by patients with breathing difficulties;
  2. It is used by mountain climbers and deep sea divers for breathing;
  3. It is used to burn fuels e.g. burning fuels for propelling rockets;
  4. Used in welding and cutting metals

Examples:
It combines with hydrogen to form a very hot oxy-hydrogen flame that is used in welding and cutting metals;

– It combines with acetylene to form oxy-acetylene flame which is also used in welding and cutting metals;

 

  1. During steel making, oxygen is used to remove iron impurities.

– During this process oxygen is blown over hot impure iron.

– The oxygen react with carbon impurities forming carbon (IV) oxide which escapes laving pure iron which is steel due to its higher purity;

 

Burning substances in air.

– When substances burn in air they mainly react mainly with oxygen (the active part of air);

– Some metals however also react with nitrogen;

– During burning there is usually change in mass;

 

Experiment: To investigate burning substances in air.

Requirements:
– Metal (magnesium ribbon); crucible; tripod stand; pipe clay triangle; means of heating;

 

Apparatus.

 

 

Procedure:

– About 1g of magnesium is put in the crucible;

– The crucible (with the magnesium is then weighed)

– The apparatus is set up as above;

– The crucible is heated with the lid lifted occasionally; so as to allow in air;

– No content of the crucible is allowed to escape; to ensure all products of the burning are retained;

– After all the magnesium has burned the crucible is allowed to cool;

– The crucible and its contents are weighed again;

 

Observations

Mass of crucible + magnesium before burning = xg

Mass of crucible + contents after burning = yg

Change in mass = (x –y) g;

Mass of product before burning is lower // less than the mass of the product after burning;

 

Explanations:

– When the magnesium is burned in a closed crucible in a closed container, most of the air is consumed;

– It is therefore necessary to allow in air so that the burning can continue;

– During burning the magnesium combines with air to form a new product;

– Magnesium combines with both oxygen and nitrogen in air to form magnesium nitride and magnesium oxide;

 

Equations

With oxygen:
Magnesium + oxygen → Magnesium oxide;

Mg(s) + O2(g) → MgO(s);

 

With nitrogen:

Magnesium + Nitrogen →Magnesium nitride;

3Mg(s) + N2(g) → Mg3N2(s);

 

Conclusion:

– Generally when metals burn in air, there is increase in mass;

– All metals react with oxygen to form metal oxides;

– Only more reactive metals react with nitrogen in air;

 

Note:

– During burning if the product(s) of the burning is gaseous, then there would be decrease in mass.

 

Examples:
Phosphorus → Phosphorus (V) oxide;

Lead (II) nitrate → Phosphorus (V) oxide + Nitrogen (IV) oxide + Oxygen gas;

Calcium carbonate → Calcium oxide + carbon (IV) oxide;

 

 

 

 

 

Burning metals in air and in oxygen.

Requirements:

– Metals; deflagrating spoon; gas jar; source of heat;

 

Diagram of apparatus;

 

 

 

 

 

 

 

 

 

 

 

Procedure:

– A piece of sodium is warmed on a deflagrating spoon until it begins to burn;

– It is then lowered into a gas jar of air as shown above;

– The flame colour is noted;

– The gas jar is allowed to cool; some water added to the product(s) in the gas jar and shook well;

– Any gases produced are tested by smell and also with litmus papers;

– The experiment is then repeated with pure oxygen;

– The whole procedure is repeated with other metals;

 

Observations;

– When substances burn in oxygen they form only oxides; as opposed to burning substances in air where some react with both air and nitrogen;

– Different substances produce different flame colours;

– Many metals burn in air and in oxygen at different speeds; with more reactive metals burning more vigorously than the less reactive metals;

– Burning is faster in oxygen than in air;

Reason:

– Oxygen is pure but in air there are other constituents such as nitrogen, carbon (IV) oxide and noble gases which slow down the burning;

– In air products are generally oxides and in some few cases (magnesium and sodium) nitrides as well;

– Metals that tend to be more reactive are the ones that react with both oxygen and nitrogen;

– In oxygen products are strictly oxides;

– Some of then products are soluble in water while others are not.

 

Sample equations:

Magnesium:

With oxygen:
Magnesium + oxygen → Magnesium oxide;

Mg(s) + O2(g) → MgO(s);

 

With nitrogen:

Magnesium + Nitrogen →Magnesium nitride;

3Mg(s) + N2(g) → Mg3N2(s);

Sodium:

With oxygen:
Sodium + oxygen → Sodium oxide;

4Na(s) + O2(g) → 2Na2O(s);

 

With nitrogen:

Sodium + Nitrogen →Magnesium nitride;

6Na(s) + N2(g) → 2Na3N(s);

 

Summary: burning metals in air.

Metal How it burns Appearance of product Name of products Solubility of product in water Effect of solution on litmus paper
Magnesium Burns with a bright white flame; White powder Magnesium oxide and magnesium nitride; Slightly soluble; alkaline gas (ammonia) is produced during the process; Turns blue;
Copper Burns with a blue flame; surface turns black; Black solid; Copper (II) oxide; Insoluble; No effect;
Iron. Glows to red hot; produces sparks; Brown black (dark brown) solid; Iron (II) oxide Insoluble; No effect;
Sodium Buns very vigorously with a golden yellow flame; White solid; Sodium oxide and sodium nitride Soluble; alkaline gas (ammonia) is produced in the process; Turns litmus blue;
Calcium Vigorous with a red flame; White solid; Calcium oxide and calcium nitride; Slightly soluble; alkaline gas evolved in the process; Turns blue;
Zinc   Yellow solid which cools to white; Zinc oxide Insoluble; No effect
Lead   Red solid which cools to yellow; Lead (II) oxide Insoluble; No effect;
Potassium Very vigorously with a lilac flame; White solid; Potassium oxide and potassium nitride; Soluble; alkaline gas evolved in the process; Turns blue;

 

Note:
– When metals combine with oxygen, it forms metal oxides. In these reactions oxygen is added to the metals; hence the reaction is called oxidation.

Oxidation refers to the addition of oxygen to a substance;

– The reactivity of various metals with oxygen differs.

– The arrangement of the metals in order of their activity forms the reactivity series;

– Metallic oxides generally turn litmus paper blue and are thus said to be basic oxides;

– Some metallic oxides however have both acidic and basic properties and are thus termed amphoteric oxides e.g. aluminium oxides;

 

 

 

 

 

The Reactivity series of metals;

Potassium;      Most reactive;

Sodium;

Calcium;

Aluminium;

Zinc;               increasing reactivity;

Iron;

Lead;

Copper;

Mercury;

Silver;

Gold;               Least reactive

 

Burning non-metals in oxygen

Requirements:

– Non-metals; deflagrating spoon; gas jar; source of heat;

 

Diagram of apparatus;

 

 

 

 

 

 

 

 

 

 

 

Procedure:

– A piece of sulphur is heated on a deflagrating spoon until it begins to burn;

– It is then lowered into a gas jar of oxygen as shown above;

– The flame colour is noted;

– The gas jar is allowed to cool; some water added to the product(s) in the gas jar and shook well;

– Any resultant solution is tested with litmus papers;

– Any gases produced are tested by smell and also with litmus papers;

– The experiment is then repeated with pure oxygen;

– The whole procedure is repeated with other non-metals such as carbon and phosphorus;

 

Explanations:
1. Sulphur.

– Burns in oxygen with a blue flame to give a colourless gas with a choking irritating smell;

– The gas is sulphur (IV) oxide;

Equation:
Sulphur + Oxygen → Sulphur (IV) oxide;

S + O2(g) → SO2(g);

– The sulphur (IV) oxide dissolves in water to form sulphurous acid, which turns litmus rd;

SO2(g) + H2O(l) → H2SO3(l);

 

  1. Carbon

– Glows red to give a colourless gas that forms a white precipitate in lime water;

– The gas is Carbon (IV) oxide;

Equation:
Carbon + Oxygen → Carbon (IV) oxide;

C + O2(g) → CO2(g);

– The Carbon (IV) oxide dissolves in water to form weak carbonic acid, which turns litmus rd;

CO2(g) + H2O(l) → H2CO3(l);

 

Note:
– In limited oxygen the carbon undergoes partial oxidation forming carbon (II) oxide;

Equation:
2C(s) + O2(g) → 2CO(g)

 

  1. Phosphorus.

– Burns in oxygen with a white flame to give dense white fumes;

– The white fumes are either phosphorus (V) oxide or phosphorus (III) oxide;

– Both solids // fumes dissolve in water to form phosphoric acid;

 

Equations:

With limited supply of oxygen:
Phosphorus + Oxygen → Phosphorus (III) oxide;

P4(s) + 3O2(g) →2P2O3(g);

 

With excess oxygen.

Phosphorus + Oxygen → Phosphorus (V) oxide;

P4(s) + 5O2(g) →P2O10(g);

 

Summary: effects of burning non-metals in air.

Non-metal How it burns in oxygen Name of products formed Appearance of the product Effect of solution on litmus paper
Sulphur Burns with a blue flame; Sulphur (IV) oxide White fumes; Turns ed
Carbon Glows red Carbon (IV) oxide Colourless gas; Turns red;
Phosphorus Burns with a white flame Phosphorus (V) oxide and phosphorus (III) oxide White fumes Turns red;

 

Precautions:
The experiment should be done in a fume cupboard.

Reason:
Products of burning sulphur and phosphorus in air are poisonous.

 

 

 

Note:
– Most non-metallic oxides are acidic in nature and therefore turn litmus red and are thus referred to as acidic oxides;

– Some non-metallic oxides form oxides which are neither acidic nor basic and are thus termed neutral oxides; e.g. carbon (II) oxide and water (hydrogen oxide);

 

Competition for combined oxygen among elements.

Apparatus:

– Metal oxides, source of heat, metals.

 

Procedure:

– A spatula end full of copper (II) oxide in a bottle top.

– Magnesium powder and mixed well;

– Record the observations;

– The experiment is repeated using other metal oxides with various other metals like zinc, iron etc.

 

Observations:

                Metal

Metal

oxide

Magnesium Zinc Iron Lead Copper
Magnesium oxide (white) No reaction No reaction No reaction No reaction No reaction
Zinc oxide (white) White magnesium oxide and grey zinc metal No reaction No reaction No reaction No reaction
Iron (III) oxide White magnesium oxide and grey iron metal;

 

White zinc oxide and iron; No reaction No reaction No reaction
Lead (II) oxide (yellow when White magnesium oxide and White zinc oxide and lead; Iron (III) oxide and lead; No reaction No reaction
Copper (II) oxide (Black White magnesium oxide and brown copper metal; White zinc oxide and brown copper metal; Brown iron (III) oxide and brown copper metal Yellow lead (II) oxide and brown copper metal No reaction

 

Explanations:

– A more reactive metal takes away oxygen from a less reactive metal;

– This is because a more reactive metal reacts more readily with a less reactive metal;

– These reactions are called displacement reactions;

– Some metals can displace other metals from their oxides upon heating;

– Metals which are higher in the reactivity series can displace metals which are lower in the reactivity series from their oxides;

– From the table none of the metals can displace magnesium from its oxide, while copper can be displaced from its oxides by all the metals.

– Thus from the list magnesium is the most reactive while copper is the least reactive.

– Such results of displacement reactions can also be used to develop a reactivity series of the metals (elements) concerned.

Selected equations:

  1. Copper (II) oxide + Magnesium → Magnesium oxide + Copper

CuO(s) + Mg(s) → MgO(s) + Cu(s);

       Black             Grey               White          Brown.

 

  1. Zinc (II) oxide + Magnesium → Magnesium oxide + Zinc

White when cold                           Grey                                  White                      Grey.

      Yellow when hot

ZnO(s) + Mg(s) → MgO(s) + Cu(s);

 

  1. Copper (II) oxide + Zinc → Zinc oxide + Copper

  Black                                       Grey          White when cold        Brown.

                                                                         Yellow when hot

CuO(s) + Mg(s) → MgO(s) + Cu(s);

 

  1. Lead (II) oxide + Magnesium → Magnesium oxide + Lead

Yellow when cold                           Grey                                  White                      Grey.

      Redwhen hot

CuO(s) + Mg(s) → MgO(s) + Cu(s);

 

  1. Copper (II) oxide + Zinc → Magnesium oxide + Copper

CuO(s) + Zn(s) → MgO(s) + Zn(s);

       Black             Grey               White         Brown.

 

Typical reactivity series from the results above:

Magnesium ↑ Most reactive

Zinc

Iron

Lead

Copper       ↓ Least reactive

 

Note:

– Removal of oxygen is called reduction;

– Addition of oxygen is called oxidation;

– A substance that loses oxygen during a reaction is said to be reduced while a substance that removes oxygen from another is called reducing agent;

– A substance that gains oxygen during a reaction is said to be oxidized while a substance that loses / donates oxygen to another is called an oxidizing agent;

 

Examples:

  1. Copper (II) oxide + Magnesium → Magnesium oxide + Copper

CuO(s) + Mg(s) → MgO(s) + Cu(s);

       Black             Grey               White          Brown.

 

Reducing agent: magnesium

Oxidizing agent: Copper (II) oxide

Oxidized species: Magnesium

Reduced species: Copper

 

 

 

 

  1. Copper (II) oxide + Zinc → Magnesium oxide + Copper

CuO(s) + Zn(s) → MgO(s) + Zn(s);

       Black             Grey               White         Brown.

Reducing agent: Zinc

Oxidizing agent: Copper (II) oxide

Oxidized species: Zinc

Reduced species: Copper

 

– In the above reactions both reduction and oxidation take place at the same time;

– A reaction in which both reduction and oxidation occur at the same time is called a redox reaction; “red” from reduction and “ox” from oxidation;

 

Application of Redox reactions:

  1. Extraction of metals;

– Ores of metals such as zinc, iron’ lead etc are roasted in air to form corresponding metal oxides;

– The metal oxides are then reduced to corresponding metals using common reducing agents like carbon and carbon (II) oxide.

 

Examples:

Zinc (II) oxide + Carbon (II) oxide → Zinc + carbon (IV) oxide;

 

Atmospheric pollution and percentage composition of air.

– Human activities have changes the normal composition of air in some places;

– This has not only altered the percentage composition of the main components but also added other components into the air.

 

Examples:

– Mining increases the amount of dust particles in the air;

– Geothermal power drilling may result into emission of gases like hydrogen sulphide, sulphur (IV) oxide into the air;

– Industrial processes like manufacture of nitric (V) acid, contact process etc may add gases ilke sulphur (IV) oxide, nitrogen oxides into the air;

 

These gases and emissions cause atmospheric pollution:

– Gases like sulphur (IV) oxide and nitrogen (IV) oxide dissolve I rain water to form acidic rain that causes corrosion of buildings, iron sheet roofing, bleaching of plants; irritation in bodies and respiratory surfaces in animals etc;

– Dust particles may block stomata in plants; cause smog formation hence reducing visibility (leading to more cases of road accidents).

 

Uses of oxygen:
1. Used for breathing in hospitals fro patients with breathing difficulties.

  1. Used for breathing by mountain climbers and deep sea divers.
  2. Used to burn fuels e.g. burning fuels to propel rockets.
  3. Manufacture of the oxy-acetylene flame that is used in welding and cutting of metals;
  4. Removal of iron impurities during steel making i.e. oxygen is blown through impure iron; the oxygen then reacts with carbon impurities forming carbon (IV) oxide which escapes leaving behind pure iron (steel).

 

UNIT 5: WATER AND HYDROGEN.

Checklist:
1. Introduction

  1. Burning candle wax in air.
  2. Reaction of water with metals
  • Sodium
  • Potassium
  • Calcium
  1. Reaction of metals with steam.
  • Calcium
  • Magnesium
  • Zinc
  • Iron
  • Aluminium
  1. Hydrogen
  • Hydrogen;
  • Reduction property of hydrogen
  • Burning hydrogen in air;
  1. Uses of hydrogen

 

Introduction:

– Water is the most abundant substances on earth;

– It covers about 71% of the earth’s surface;

– Main sources of water include seas, lakes, rivers, oceans.

 

Burning candle wax in air.

Apparatus:

 

 

 

 

 

 

 

 

 

 

Procedure.

– The candle is lit under the funnel and the suction pump turned on.

– The set up is left undisturbed for about 15 minutes.

 

Observations;

– The candle continues to burn.

– Droplets of a colourless liquid in the tube A;

– The colourless liquid turns white anhydrous copper (II) sulphate to blue and blue anhydrous cobalt (II) chloride into pink;

– A white precipitate forms in the calcium hydroxide in tube B;

– Deposits of a black solid on the inner sides of the funnel;

 

Explanations;

– The suction pump ensures continuous supply of air hence the candle continues to burn;

– Candle wax buns in oxygen to form carbon (IV) oxide and steam;

– The carbon (IV) oxide is sucked out through the apparatus by the suction pump;

– Carbon (IV) oxide forms a white precipitate of calcium carbonate when bubbled through lime water (calcium hydroxide)

– Incomplete combustion of the carbon in the candle wax produces carbon particles which cools and deposits as black solids;

 

Equations:

As the candle burns:
Carbon + Oxygen → Carbon (IV) oxide;

C(s) + O2(g) → CO2(g);

 

Hydrogen + Oxygen → Carbon (IV) oxide;

2H2(s) + O2(g) → 2H2O(g);

 

For the formation of the black deposits (soot)

Carbon + Oxygen → Carbon + Carbon (IV) oxide;

2C(s) + O2(g) → C(s) + CO2(g);

In the calcium hydroxide:

Carbon (IV) oxide + calcium hydroxide → Calcium carbonate + Water

Colourless                                                            Colourless                                        White precipitate                    Colourless

CO2(g) + Ca(OH)2(aq) → CaCO3(s) + H2O(l);

 

– The steam condenses into water in the boiling tube;

– Water turns white anhydrous copper (II) sulphate to blue and blue anhydrous cobalt chloride paper into pink;

 

General equation:
Hydrocarbon + Oxygen → Water + Carbon (IV) oxide;

 

Conclusion:

– Candle wax is a compound of carbon and hydrogen only; and such compounds are defined as hydrocarbons;

– When burned in air (oxygen) hydrocarbons produce carbon (IV) oxide ad steam (water);

– Other examples of hydrocarbons include: petrol; diesel; kerosene etc;

 

Note: Effects of repeating the same experiment without a suction pump.

Apparatus:

 

 

 

 

 

 

 

 

 

Observations:
– The candle went off;

– Deposition of black solid on the inner sides of the funnel;

– No colourless liquid in tube A;

– No white precipitate in tube B;

 

Explanations:
– The carbon (IV) oxide and steam produced would accumulate in the filter funnel hence making the flame to go off;

– Incomplete combustion of the candle would produce carbon particles which cool as soot;

– Only negligible amount of water and carbon (IV) oxide would pass through the apparatus;

 

 

 

 

 

 

 

 

Reactions of water with metals:
1. Potassium.

Procedure:
– A small piece of potassium metal is cut and dropped into a trough containing water;

– The resultant solution is tested with litmus paper;

 

Diagram of apparatus:

 

 

 

 

 

 

 

 

Observations and explanations:

– The metal floats on the water surface; because it is less dense than water;

– A hissing sound is produced; due to production of hydrogen gas;

– It explosively melts into a silvery ball then disappears because reaction between water and sodium is exothermic (produces heat). The resultant heat melts the potassium due to its low melting point.

– It darts on the surface; due to propulsion by hydrogen;

– The metal bursts into a lilac flame; because hydrogen explodes into a flame which then burns the small quantities potassium vapour produced during the reaction;

– The resultant solution turns blue; because potassium hydroxide solution formed is a strong base;

 

(b). Reaction equations.

Equation I

2K(s) + 2H2O(l) → 2KOH(aq) + H2(g);

 

Equation II

4K(s) + O2 (g) → 2K2O(s);

 

Equation III:

K2O(s) + H2O(l) → 2KOH(aq)

 

Effect of resultant solution on litmus paper;

– Litmus paper turns blue; sodium hydroxide formed is highly soluble in water; releasing a large number of hydroxyl ions which result into alkaline conditions // high pH;

 

 

 

 

 

 

 

 

 

 

 

  1. Sodium.

Procedure:
– A small piece of sodium metal is cut and dropped into a trough containing water;

– The resultant solution is tested with litmus paper;

 

Diagram of apparatus:

 

 

 

 

 

 

 

 

Observations and explanations:

– The metal floats on the water surface; because it is less dense than water;

– A hissing sound is produced; due to production of hydrogen gas;

– It vigorously melts into a silvery ball then disappears because reaction between water and sodium is exothermic (produces heat). The resultant heat melts the sodium due to its low melting point.

– It darts on the surface; due to propulsion by hydrogen;

– The metal may burst into a golden yellow flame; because hydrogen may explode into a flame which then burns the sodium;

– The resultant solution turns blue; because sodium hydroxide solution formed is a strong base;

 

(b). Reaction equations.

Equation I

2Na(s) + 2H2O(l) → 2NaOH(aq) + H2(g);

 

Equation II

4Na(s) + O2 (g) → 2Na2O(s);

 

Equation III:

Na2O(s) + H2O(l) → 2NaOH(aq)

 

Effect of resultant solution on litmus paper;

– Litmus paper turns blue; sodium hydroxide formed is highly soluble in water; releasing a large number of hydroxyl ions which result into alkaline conditions // high pH;

 

  1. Calcium.

Procedure:
– A small piece of calcium metal is cut and dropped into a trough containing water;

– A filter funnel is inverted over it;

– A test tube filled with water is then inverted over the funnel;

– The gas given out is collected as shown in the apparatus below.

– The resultant gas is then tested with a burning splint;

– The resultant solution in the trough is tested with litmus paper.

 

 

 

Diagram of apparatus:

Observations and explanations:

– Calcium sinks to the bottom of the beaker; because it is denser than water;

– Slow effervescence of a colourless gas; due to slow evolution of hydrogen gas;

– Soapy solution formed; due to formation of alkaline calcium hydroxide;

– A white suspension is formed; because calcium hydroxide is slightly soluble in water;

 

Reaction equation:

Ca(s) + H2O (l) → Ca (OH) 2(aq) + H2 (g);

 

Effect of resultant solution on litmus paper;

– Litmus paper slowly turns blue; calcium hydroxide formed is slightly soluble in water; releasing a small number of hydroxyl ions which result into alkaline conditions // high pH;

 

  1. Magnesium and other metals.

– Magnesium reacts with atmospheric oxygen to form magnesium oxide that coast the metal surface;

– Thus before reacting it with water this oxide layer has to be removed e.g. by polishing metal surface using sand paper;

– Reaction between magnesium and cold water is generally very slow; with very slow evolution of hydrogen gas;

– Zinc and iron metals do not react with cold water;

 

Reaction of metals with steam.

Note:

– Metals that react with cold water would react very explosively with steam and thus their reactions with steam should not be attempted in the laboratory;

– However some metals which react only sparingly with cold water or do not react with cold water at all react with steam to produce respective metal oxide and hydrogen gas;

 

  1. Magnesium

Procedure:
– A small amount of wet sand is put at the bottom of a boiling tube;

– A small piece of magnesium ribbon is cleaned and put in the middle of the combustion tube;

– The magnesium ribbon is heated strongly then the wet sand is warmed gently;

– The delivery tube is removed before heating stops; and the gas produced is tested using a burning splint;

 

 

 

 

Diagram of apparatus:

Observations and explanations.

– Magnesium burns with a bright blinding flame;

– Grey solid (magnesium) forms a white solid; due to formation of magnesium oxide;

– Evolution of a colourless gas that burns with a pop sound; confirming it is hydrogen;

 

Reaction equation.

Magnesium + Steam → Magnesium oxide + Hydrogen gas;

Mg(s) + H2O(g) → MgO(s) + H2(g);

 

  1. Zinc

Procedure:
– A small amount of wet sand is put at the bottom of a boiling tube;

– A small piece of zinc put in the middle of the combustion tube;

– The zinc is heated strongly then the wet sand is warmed gently;

– The delivery tube is removed before heating stops; and the gas produced is tested using a burning splint;

 

Diagram of apparatus:

Observations and explanations.

– Zinc metal does not burn but rather glows;

– Grey solid (zinc) forms a yellow solid which cools to a white solid (zinc oxide);

– Evolution of a colourless gas that produces a pop sound when exposed to a burning splint; confirming it is hydrogen;

 

Reaction equation.

Zinc + Steam → Zinc oxide + Hydrogen gas;

Grey        Colourless      Yellow when hot            Colourless

                                       White on cooling

Zn(s) + H2O(g) → ZnO(s) + H2(g);

 

 

 

  1. Iron

Procedure:
– A small amount of wet sand is put at the bottom of a boiling tube;

– A small piece of iron put in the middle of the combustion tube;

– The iron is heated strongly then the wet sand is warmed gently;

– The delivery tube is removed before heating stops; and the gas produced is tested using a burning splint;

 

Diagram of apparatus:

Observations and explanations.

– Iron metal does not burn but rather glows;

– Grey solid (zinc) forms a black solid; due to formation of tri-iron tetra-oxide;

– Evolution of a colourless gas that burns with a pop sound; confirming it is hydrogen;

 

Reaction equation.

Iron + Steam → Tri-iron tetra-oxide + Hydrogen gas;

Grey        Colourless                     Black                                     Colourless

 

3Fe(s) + 4H2O(g) → Fe3O4(s) + 4H2(g);

 

  1. Aluminium

Procedure:
– A small amount of wet sand is put at the bottom of a boiling tube;

– A small piece of aluminium put in the middle of the combustion tube;

– The aluminium is heated strongly then the wet sand is warmed gently;

– The delivery tube is removed before heating stops; and the gas produced is tested using a burning splint;

 

Diagram of apparatus:

Observations and explanations.

– Aluminium burns in steam but the reaction quickly stops; because the reaction forms a layer of aluminium oxide that coats the metal surface preventing further reaction;

– Grey solid (aluminium) forms a white solid of aluminium oxide;

– Slight evolution of a colourless gas that burns with a pop sound; confirming it is hydrogen;

– The production of the gas however stops soon after the reaction starts because the oxide layer stops further reaction;

 

Reaction equation.

Aluminium + Steam → Zinc oxide + Hydrogen gas;

Grey                        Colourless                White                    Colourless

 

2Al(s) + 3H2O(g) → Al2O3(s) + 3H2(g);

 

  1. Other metals.

– Lead and copper do not react with steam;

 

Summary of the reaction between metals with cold water and steam

Metal Action of metal on water Action of metal on steam
Potassium

Sodium

Calcium

Magnesium

Aluminium

Zinc

Iron

Lead

Copper

Violent

Violent

Moderate

Very slow

No reaction

No reaction

No reaction

No reaction

No reaction

Explosive

Explosive

Violent

Rapid

Slow

Slow

Slow

No reaction

No reaction

 

Note:

– Metals can thus be arranged in order of their reactivities with water; resulting to a reactivity series similar to that obtained form reaction between metals with oxygen;

 

Reactivity series of metals:

Potassium;           Most reactive;

Sodium;

Calcium;

Magnesium

Aluminium;

Zinc;                     increasing reactivity;

Iron;

Lead;

Copper;                Least reactive;

 

 

 

 

 

 

 

 

 

 

 

 

Hydrogen

– An element that does not exist freely in nature;

– Generally exists in compounds such as water, sugars, fuels etc;

 

Laboratory preparation of hydrogen gas.

Note:

– Hydrogen gas is generally prepared by the reaction between dilute acids and metals;

– Most suitable acids are dilute hydrochloric acid and dilute sulphuric (VI) acid;

– Most suitable metal is zinc metal;

 

Apparatus:

Procedure:
– Zinc granules are added to dilute sulphuric (VI) acid;

– Small amounts of copper (II) sulphate are added to the zinc – acid mixture;

Reason: To act as a catalyst hence speed up the reaction;

– The resultant colourless gas is collected over water;

Reason: The gas is insoluble in water;

– If the gas is required dry, the gas is passed through concentrated sulphuric (VI) acid or a U-tube containing calcium chloride;

 

Diagrams for drying the gas:

             Zinc granules

– The dry gas is collected by upward delivery (downward displacement of air);

Reason: It is less dense than air (note that hydrogen is the lightest gas known);

 

 

 

 

 

Note:

– Nitric (V) acid is not used in preparation of hydrogen gas; except very dilute nitric (V) acid and magnesium

Reason: Nitric acid is a strong oxidizing agent hence the hydrogen formed is immediately oxidized to water
– Potassium, sodium, lithium and calcium are not used in laboratory preparation of hydrogen gas;
Reason: They react explosively with acids;

– Magnesium is not usually used for laboratory preparation of hydrogen;

Reason: It is expensive;

– Prior to using it for preparation of hydrogen; aluminium should be washed with concentrated hydrochloric acid;

Reason: To remove the protective oxide layer that usually forms on the aluminium surface on its exposure to air;

– Hydrogen gas produced from iron metal tends to have a foul smell;

Reason: Iron gives a mixture of gases due to impurities in the iron; the foul smell is usually due to production of hydrogen sulphide that results from sulphide impurities in the iron metal;

 

Reaction equations:

  1. Iron + Sulphuric (VI) acid → Iron (II) sulphate + Hydrogen gas;

Fe(s) + H2SO4(aq) → FeSO4(aq) + H2(g)

 

  1. Iron (II) sulphide + Sulphuric (VI) acid → Iron (II) sulphate + Hydrogen sulphide gas;

FeS(s) + H2SO4(aq) → FeSO4(aq) + H2S(g);

 

Other sources of hydrogen.

– Cracking of alkanes;

– Fractional distillation of petroleum;

 

Properties of Hydrogen gas;

Physical properties.

  1. Colourless and odourless;
  2. It is insoluble in water;
  3. It is less dense than air (it is the lightest gas known);

 

Chemical properties.

  1. It has no effect on litmus paper implying that it is neutral;
  2. It burns with a pop sound when mixed with air;
  3. Pure hydrogen burns quietly with a blue flame producing water;
  4. Hydrogen does not support combustion but it burns in air;
  5. It is a reducing agent;

 

Chemical test for hydrogen;

– When a burning splint is introduced into a gas jar full of hydrogen gas; the gas buns with a “pop sound”

Note:
– The intensity of the “pop sound” diminishes as the purity of hydrogen increases;

 

 

 

Reactions of hydrogen:

  1. Passing hydrogen over heated copper (II) oxide;

Requirements:

Copper (II) oxide; porcelain boat; mean of heating; combustion tube; dry hydrogen gas;

 

Diagram of apparatus.

Procedure:

– Apparatus are arranged as shown above;

– Dry hydrogen gas is passed through the combustion tube for sometime prior to heating the oxide;

Reason:

  • To drive out all the air from the apparatus which may otherwise re-oxidize the metal after reduction.
  • A mixture of hydrogen and air will explode when the combustion tube is heated;

– The gas is continuously collected at the jet and tested; until the gas burns smoothly without a “pop” sound;

– The gas is then lit at the jet and the copper oxide heated;

– This is done until no further change;

– The apparatus is allowed to cool as hydrogen is still continuously allowed to pass through;

Reason:

  • To prevent re-entry of atmospheric oxygen which will re-oxidize the hot metal back to the metal oxide;

– Excess hydrogen must be burnt at the jet so that excess gas is not allowed to escape into the air;

Reason:

  • The mixture of hydrogen and oxygen is explosive when ignited;

 

Observations and explanations

– The black solid turns into a brown solid;

– Droplets of a colourless liquid on the cooler parts of the combustion tube;

Reason:

The hot black copper (II) oxide is reduced by hydrogen gas into brown copper metal while hydrogen gas is oxidized to water;

– The colourless liquid is confirmed to be water by:

  • Adding drops of it to anhydrous copper (II) sulphate which forms a blue solid;
  • Adding drops of it onto blue anhydrous cobalt (II) chloride which turns pink;

 

Reaction equations:

In the combustion tube:

Copper (II) oxide + Hydrogen → Copper + Water;

Black solid                                   Colourless gas    Brown solid     Colourless liquid

CuO(s) + H2(g) → Cu(s) + H2O(l);

 

At the jet:

– Hydrogen burns with a blue flame producing water;

Equation:

2H2(g) + O2(g) → 2H2O(l);

 

Conclusion:

– Hydrogen is a reducing agent and thus reduces the copper (II) oxide to copper metals while hydrogen itself undergoes oxidation to form water;

– Hydrogen is the reducing agent;

– Copper (II) oxide is the oxidizing agent;

 

  1. Passing hydrogen over heated Lead (II) oxide;

Requirements:

Lead (II) oxide; porcelain boat; mean of heating; combustion tube; dry hydrogen gas;

 

Diagram of apparatus.

Procedure:

– Apparatus are arranged as shown above;

– Dry hydrogen gas is passed through the combustion tube for sometime prior to heating the oxide;

Reason:

  • To drive out all the air from the apparatus which may otherwise re-oxidize the metal after reduction.
  • A mixture of hydrogen and air will explode when the combustion tube is heated;

– The gas is continuously collected at the jet and tested; until the gas burns smoothly without a “pop” sound;

– The gas is then lit at the jet and the copper oxide heated;

– This is done until no further change;

– The apparatus is allowed to cool as hydrogen is still continuously allowed to pass through;

Reason:

  • To prevent re-entry of atmospheric oxygen which will re-oxidize the hot metal back to the metal oxide;

– Excess hydrogen must be burnt at the jet so that excess gas is not allowed to escape into the air;

Reason:

  • The mixture of hydrogen and oxygen is explosive when ignited;

 

Observations and explanations

– The yellow solid turns red on heating then finally into a grey solid;

– Droplets of a colourless liquid on the cooler parts of the combustion tube;

 

 

 

Reason:

The hot red lead (II) oxide is reduced by hydrogen gas into grey lead metal while hydrogen gas is oxidized to water;

– The colourless liquid is confirmed to be water by:

  • Adding drops of it to anhydrous copper (II) sulphate which forms a blue solid;
  • Adding drops of it onto blue anhydrous cobalt (II) chloride which turns pink;

 

Reaction equations:

In the combustion tube:

Lead (II) oxide + Hydrogen → Lead + Water;

Yellow-cold; red – hot        Colourless gas       Grey solid     Colourless liquid

PbO(s) + H2(g) → Pb(s) + H2O(l);

 

At the jet:

– Hydrogen burns with a blue flame producing water;

Equation:

2H2(g) + O2(g) → 2H2O(l);

 

Conclusion:

– Hydrogen is a reducing agent and thus reduces the lead (II) oxide to lead metals while hydrogen itself undergoes oxidation to form water;

– Hydrogen is the reducing agent;

– Lead (II) oxide is the oxidizing agent;

 

  1. Passing hydrogen over heated Iron (III) oxide;

Requirements:

Iron (III) oxide; porcelain boat; mean of heating; combustion tube; dry hydrogen gas;

 

Diagram of apparatus.

Procedure:

– Apparatus are arranged as shown above;

– Dry hydrogen gas is passed through the combustion tube for sometime prior to heating the oxide;

Reason:

  • To drive out all the air from the apparatus which may otherwise re-oxidize the metal after reduction.
  • A mixture of hydrogen and air will explode when the combustion tube is heated;

– The gas is continuously collected at the jet and tested; until the gas burns smoothly without a “pop” sound;

– The gas is then lit at the jet and the copper oxide heated;

– This is done until no further change;

– The apparatus is allowed to cool as hydrogen is still continuously allowed to pass through;

Reason:

  • To prevent re-entry of atmospheric oxygen which will re-oxidize the hot metal back to the metal oxide;

– Excess hydrogen must be burnt at the jet so that excess gas is not allowed to escape into the air;

Reason:

  • The mixture of hydrogen and oxygen is explosive when ignited;

 

Observations and explanations

– The Brown solid turns into a grey solid;

– Droplets of a colourless liquid on the cooler parts of the combustion tube;

 

Reason:

The hot brown iron (III) oxide is reduced by hydrogen gas into grey iron metal while hydrogen gas is oxidized to water;

– The colourless liquid is confirmed to be water by:

  • Adding drops of it to anhydrous copper (II) sulphate which forms a blue solid;
  • Adding drops of it onto blue anhydrous cobalt (II) chloride which turns pink;

 

Reaction equations:

In the combustion tube:

Iron (III) oxide + Hydrogen → Iron + Water;

Brown solid                     Colourless gas      Grey solid     Colourless liquid

Fe2O3(s) + 3H2(g) → 2Fe(s) + 3H2O(l);

 

At the jet:

– Hydrogen burns with a blue flame producing water;

Equation:

2H2(g) + O2(g) → 2H2O(l);

 

Conclusion:

– Hydrogen is a reducing agent and thus reduces the iron (III) oxide to iron metal while hydrogen itself undergoes oxidation to form water;

– Hydrogen is the reducing agent;

– Iron (III) oxide is the oxidizing agent;

 

Note:

– Hydrogen does not reduce (remove oxygen) from oxides of metals above it in the reactivity series;

 

 

 

 

 

 

 

 

 

 

 

 

Products of burning hydrogen gas in air.

Apparatus and requirements:

– The apparatus is arranged as shown below.

Procedure:

– Apparatus is arranged as shown below.

– A stream of hydrogen is passed through anhydrous calcium chloride;

– The gas is tested for purity by collecting samples over the jet and testing with a burning splint.

Note: pure hydrogen gas should burn smoothly without the typical “pop sound”;

– The gas is then lit and the pump tuned on;

– The products of burning hydrogen is drown in through the apparatus using the pump for about 15 minutes;

– The product condensing in the test tube in cold water is tested with white anhydrous copper (II) sulphate and blue cobalt chloride paper;

 

Observations:
– Pure hydrogen burns with a blue flame;

– A colourless liquid condenses in the test tube immersed in cold water;

– The liquid turns white anhydrous copper (II) sulphate blue;

– The colourless liquid turns blue anhydrous cobalt chloride pink;

 

Explanations:

– The calcium chloride in the U-tube is used to dry the gas;

– The pure dry hydrogen gas burns with a blue flame to form steam which condenses into liquid water;

– Water turns anhydrous copper (II) chloride from white to blue; and turns blue anhydrous cobalt chloride paper into pink;

 

Reaction equations:

At the jet:

2H2(g) + O2(g) → 2H2O(g);

 

 

 

 

 

 

 

 

 

 

 

Uses of Hydrogen

  1. Large scale manufacture of ammonia in the Haber process;
  2. Hydrogenation for the manufacture of margarine.

– This refers to hardening of oils into fats.

– In this reaction Hydrogen gas is bubbled into liquid oil in presence o0f nickel catalyst;

– The oil takes up hydrogen and is converted into fat;

  1. Hydrogen is used in weather balloons because it is lighter than air;

– Usually a radio transmitter is connected to a weather balloon filled with air; as the balloon floats in air the transmitter collects information which is conveyed to weather stations for interpretation by meteorologists;

  1. A mixture of hydrogen and oxygen forms the very hot oxy-hydrogen flame (with temperatures up to 2000oC that is used in welding and cutting metals;
  2. It is used in rocket fuels for propulsion of rockets;
  3. Manufacture of hydrochloric acid; during which hydrogen is burnt in chlorine;