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    Form 3 Physics Exams and Marking Schemes Free

    By Maverick JohnMay 31, 2025No Comments6 Mins Read

    Name___________________________________________ Index No.____________                            

    Candidates signature ____________________                          Date __________________

    PHYSICS

    PAPER 3

    PRACTICAL 

    2 ½ HOURS

     

    JOINT EXAMINATION TERM 3

     

    INSTRUCTIONS TO CANDIDATES

    • Answer all questions in both sections in the spaces provided in the question paper.
    • Read the whole paper carefully before commencing your work.
    • Marks are given for clear record of the observations actually made, their suitability and accuracy and the use of them.
    • Mathematical tables and electronic calculators may be used.

     

    FOR EXAMINER’S USE ONLY

    Question Maximum Score Candidate’s Score
    1. 20  
    2. 20  
     

    TOTAL

     

    40

     

     

     

    This paper consists of 7 printed pages. Learners should check to ensure that all pages are printed as indicated and that no questions are missing.

     

     

     

    Question 1

    You are provided with the following;

    • Masses; 10g, 20g(2), 50g and 100g
    • A helical spring with a pointer
    • Metre rule or half metre rule

     

    Proceeds as follows;

    1. a) Suspend the helical spring vertically, alongside the clamped half metre rule as shown in figure 1 below. Determine the length, L0 of the spring before loading it.

    L0=________________________________(cm)                                                      (1mk)

    1. i) Load the spring with a mass of 20g and determine the new reading on the metre rule (L).

     

    1. ii) Record this in the table below.

     

    iii) Calculate the extension, e= L-L0 due to the mass of 20g and record the value in the table given below.

     

     

     

     

     

     

     

     

     

     

     

     

    1. Repeat step b(i-iii) for other masses and complete the table.             (8mks)

     

    Mass (g) 0 20 30 40 50 60 70 80 90 100
    Weight (N) (Force)                    
    Reading L (cm)                    
    Extension e (cm)                    

     

    1. Plot a graph of Force(N) against extension e (cm).             (5mks)
    • Determine the slope S of the graph.             (3mks)

     

     

     

     

    1. Given that K=Se, determine the value of K where S is the slope of the graph and e is the extension of the spring when loaded with a 50g mass.             (3mks)

     

     

     

     

    Question 2

    You are provided with the following;

    • A Nichrome wire mounted on a millimeter scale YZ.
    • A carbon resistor R (10Ω)
    • 8 connecting wires
    • Ammeter
    • Voltmeter
    • 2 dry cells
    • Cell holders
    • Switch

     

    1. (a) Set up the circuit as shown below.
    2. Record the voltmeter reading when the switch is open.

    E=_____________________________________                                         (1mk)

    1. Close the switch and record the voltmeter and ammeter readings.

    Voltmeter reading, V=_______________________________                     (1mk)

    Ammeter reading, I=________________________________                      (1mk)

    • Explain why V is less than E.             (2mk)

    ______________________________________________________________________________________________________________________________________________________________________________________________________

     

    1. Now connect the voltmeter across the carbon resistor R and record voltmeter reading V1 when the switch is on.             (1mk)

    V1=

     

     

     

     

     

     

     

    1. Determine R given that; R=             (3mks)

     

     

     

     

     

     

     

     

    (b)

    • Measure and record the diameter, d of the resistance wire (YZ) using a micrometer screw gauge.

    d= ___________________________________mm

    d=___________________________________m                                           (2mks)

    1. ii) Set-up the circuit as shown in figure;

     

    • Determine the current I flowing in the circuit.

    I=__________________________________                                                 (1mk)

     

     

    1. Now connect the voltmeter across wire (YZ) and record the p.d, V2 across wire YZ.

    V2= ________________________________                                                 (1mk)

     

    1. Determine the resistance R of the wire YZ.             (3mks)

     

     

     

     

     

     

     

    1. Determine k, the resistance per metre of wire YZ. (2mks)

     

     

     

     

     

     

     

     

     

    • Determine Q given that Q=(where d is in metres)                    (2mks)

    ________________________________________________________________________

    JOINT EXAMINATION

    FORM 3PP3 PHYSICS

    TERM 3 MARKING SCHEME

     

    1. a) L0 – ½mk answer to 1d.p

    ½mk correct unit (cm)

     

    1. ii) (8mks)
    Mass (g) 0 20 30 40 50 60 70 80 90 100
    Weight (force) N                    
    Reading, L cm                    
    Extension, e(cm)   1.0 2.6 4.8 6.3 8.1 10.2 12.3 14.2 16.4

     

    2mks@ Row (force) – correct evaluation and substitution

    F = mg

    L to 1 d.p

    e correct (L-L0) to 1 d.p

     

    1. v) Graph of Force(N) vs extension, e (cm). (5mks)

    Correct labelling of axis – 1mk

    Scale – simple and uniform – 1mk

    Plotting (2mks) (7-10 points) – 2mks

    (5-6 points) – 1mk

    (0-4 points) – 0 mk

    Line – straight line passing through the origin – 1mk

     

    1. vi) Slope, s== 0.8N/cm                         (3mk)

    Clear points from the graph – 1mk

    Correct evaluation – 1mk

    Answer – ½mk

    Correct unit – ½mk

     

    vii) Correct substitution of k=se – 1mk

    Correct evaluation – 1mk

    Answer – ½mk

    Correct unit – ½mk

    1. a)
    2. E = 3.0- ½mk

    Correct unit – ½mk

    1. V = 2.5v1 1 d.p (1mk) and correct unit

    I = 0.20A 0.02 2 d.p (1mk) and correct unit

    • V is less than E due to the lost voltage; voltage against the internal resistance of the cell. (2mk)
    1. V1 = 1.4V1 Correct reading to 1 d.p – ½mk

    Correct unit – ½mk

    1. R=1

    Correct substitution – ½mk

    Correct evaluation – ½mk

    Answer in 4s.f – ½mk

    Correct unit – ½mk

     

    b          (i)        d=0.36mm

    d= in metres – correct conversion to 5 d.p  (1mk)

    (iii)      I = 0.10A     Correct reading – ½mk

    Correct unit – ½mk

    iv)V2 = 1.9v  0.1      Correct reading – ½mk

    Correct unit – ½mk

    1. v) R= Correct substitution – 1mk

    Correct evaluation – 1mk

    Answer in 4s.f – ½mk

    Correct unit – ½mk

    1. K=Correct evaluation – 1mk

    Answer – ½mk 4s.f

    Correct unit – ½mk (Ωm-1)

    • Q= Correct evaluation – 1mk

    Answer in 4s.f – ½mk

    Correct unit – ½mk  (Ωm)

     

     

    Maverick John

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